similar to: find_by_sql + Join + Rails 2

Displaying 20 results from an estimated 7000 matches similar to: "find_by_sql + Join + Rails 2"

2007 Sep 22
2
Rails + XSLT
hey all, i wanna learn how to use and integrate XSLT with RoR but i don''t find any resources so if any one know any good resources i will be appreciated thanks -- Mohamed Saeed software engineer --~--~---------~--~----~------------~-------~--~----~ You received this message because you are subscribed to the Google Groups "Ruby on Rails: Talk" group. To post to this group,
2006 Jan 10
15
KISS and DRY? Not even close!
Hi all, After working on my first rails app and having handed over some very sophisticated coding from a lot of you guys. My app does what I want it to do, but I''m no where near the end yet, and it seems that the KISS and DRY objectives already went down the drain. It could be lack of knowledge, only doing Ruby on (and) Rails for a month, but I''m stuck on the following:
2005 Oct 28
4
find_by_sql column types
Hello-- There must be a better way to do this. I have a class method in my model that finds averages and does a few calculations using find_by_sql. The problem I¹m encountering is that all computed columns from MySQL come back as type string. E.g., def self.find_averages(domain_id) if @@domain_average return @@domain_average else @@domain_average =
2009 Sep 16
3
find_by_sql - multiple selects, same statement SQL error
I''m trying to get the following statement to work using variable substitution (it works if hard-code the where (med_type) param in the inner SQL statement): med_type = ''game'' @mediaformats = MediaFormat.find_by_sql("select * from media_formats where media_formats.media_type_id = (select media_type_id from media_types where media_type = ?, :med_type) order by
2007 Jan 20
2
find_by_sql with named parameterized sql
I tried to use named parameters in my SQL query , using find_by_sql Order.find_by_sql ([select * from orders where amount > ? and quantity > ?", [ @amount, @quantity ] works;.. but Order.find_by_sql ([select * from orders where amount > :amount and quantity > :quantity ", [ :amount => @amt, :quantity => @qty ] is not working a I wrong or should I use a plain select
2006 Oct 02
2
when to use find_by_sql
I have a bunch of queries to compute some counters, like find_by_sql(<<-SQL SELECT p.*, c.nfavourites FROM people p, ( SELECT fp.person_id, COUNT(fp.user_id) as nfavourites FROM favourite_people fp, users u WHERE fp.user_id = u.id AND u.cluster = ''#{in_cluster_of_user.cluster}'' GROUP BY fp.person_id ) as c WHERE
2006 Jan 07
8
Using find_by_sql to get the sum of a column
Hello, I was wondering if there was a method in Rails that returns the sum of a column. For example, I have a column called ''score'' and writing a SQL statement such a ''select sum(score) from table_name'' does return the sum of the values in the column. In the past (not too long ago being a newbie), I defined all sorts of methods only to discover that Rails
2006 Apr 18
3
Join Queries? - find() or find_by_sql()
Hi All, Is there a way to do join queries with find() or is it best to use find_by_sql() instead? I''m looking to do something like: SELECT winery_name, wine_name FROM winery, wine WHERE wine.winery_id = winery.winery_id AND winery.winery_name LIKE ''Borg%''; Thanks! : ) Jason
2010 May 07
1
undefined method 'find_by_sql'
Why would I get an undefined method `find_by_sql'' for #Example: 0x981a4e4> for error when trying to use the find_by_sql method in my model? def init_dictionaries tables = find_by_sql( "SHOW TABLES FROM thesaurus" ) @@tables = tables.collect{ |t| t.Tables_in_thesaurus } end -- You received this message because you are subscribed to the Google Groups "Ruby
2011 Aug 25
3
ActiveRecord searching in batch (with find_by_sql)
I have an issue where I am getting a large number of records from the database and I cant afford to keep it in the memory due to performance issues. Therefore using the following would be ideal, User.find_each(:batch_size => 5000, :start => 2000) do |user| NewsLetter.weekly_deliver(user) end however, I would like to use find_by_sql since my query is user defined. Question is, is it
2012 Jun 30
4
find_by_sql and join
hi I amd tanizawa. I had problem. I can not get main.name value from below sql. "find_by_sql ''select main.id,main.name,sub.name from main left join sub on sub.id = main.id''" Please teach me how to get borth name value. -- You received this message because you are subscribed to the Google Groups "Ruby on Rails: Talk" group. To view this discussion on the
2006 Jan 26
1
Help constructing a find_by_sql command
Hello all. I am trying to do the equivalent of: @componentlogs = Componentlog.find(:all, :conditions => [ "cl_compname like ?", @criteria ], :offset => offset, :limit => items_per_page, :order => "cl_spr DESC" ) in a find_by_sql statement. I cannot use the build in because the adaptor isn''t quite right (OCI8) When I use it I get the following error
2006 Jan 30
1
find_by_sql and memcached
Is a find_by_sql query cached with memcached and cached_model (http://dev.robotcoop.com/Libraries/)? Looks like the answer is no. Is there a reason for this? I have a lot of very complicated querys with a lot of unions, subquerys and joins that would greatly benefit from the cache. Going through the code I can see that the find_by_sql method is changed in cached_model.rb, but it does not call
2007 Aug 14
1
find_by_sql vs connection.select_all
I was trying to do SUM based mySQL query simliar to the following: SELECT SUM(updated_on - created_on) AS total from signups If I were to run this command in the mySQL console I would get a result. However, if I were to run it using the following command in Rails: Signup.find_by_sql("SELECT SUM(updated_on - created_on) AS total from signups") The query that is written to the log is:
2008 May 30
9
find_by_sql without a model? how to do this?
Hi, I''d like to do a "find_by_sql" without a model (e.g. <model name>.find_by_sql("...")) as the results I get back are a once off special, and I''m happy to handle them as an array. How do I do this? "ActiveRecord::Base.find_by_sql(...)" does not seem to work? Background - At the moment I''m doing within a model <model_name>,
2006 Jun 23
7
find_by_sql, can''t print results
I am a little stuck with getting an sql result into my page. I want to run a select distinct that returns all of the different sections available and displays this as a form select. In my controller I have: def edit @resource = Resource.find(params[:id]) @sections = Resource.find_by_sql "SELECT DISTINCT resources.section FROM resources" end And then in my view I have: <%
2011 Dec 07
5
Find_by_sql help?
How to make it work with paginator (kaminari)? MySQL and full text search: Words (id, word) @words = Word.find_by_sql(["SELECT id, word, MATCH (word) AGAINST (?) AS Score FROM words WHERE MATCH (word) AGAINST (?) ORDER BY Score Desc, word!=?", params[:search],params[:search],params[:search]]) I can''t add .page(params[:page]).per(5) to the end of "find_by_sql()" so
2005 Dec 21
7
use of SET command in find_by_sql
Hi, I''m trying to execute something like this method in a model: def self.sql_for_rankings() sql = "SET @counter:=0;" sql << " SET @counter:=0; SELECT *, @counter:=@counter+1 AS rank FROM testscores. " find_by_sql(sql) end Where the new rank column is a kind of autoincrementer inside of
2006 Sep 01
3
find_by_sql with :include?
When you use find, you can include related objects with include so that both objects get instantiated in the results, e.g. Foo.find(:all, :include => :bar). But when you use find_by_sql, is there a way to do this? You could definitely write the find_by_sql SQL to join Foo and Bar tables: Foo.find_by_sql("SELECT foo.*, bar.* from foo, bar where foo.bar_id = bar.id") But is there a
2006 Jan 17
4
find_by_sql column ordering defect?
Hello. I have a program that accesses a metadata (translation) table for column names as well as the ordering of columns for a specific model. Also in there is a collection of bool options such as column_visible_on_form, column_visible_on_screen_quicklist etc. The idea is that our customer can specify to a certain extent how their layout/user interface will appear. To accomplish this, I use