similar to: Find with Inheritance

Hi Rspec-Users, I''m not sure if I am correctly specing my index since I''m using will_paginate. params[:filter_by] will filter the paginate list accordingly. Tickets Controller: def index @tickets = Ticket.filter_status_by(params[:filter_by],params[:page]) end Ticket Model: def self.filter_status_by(status, page, per_page = 10) conditions = {:status => false} if

Hi, I have the following find statment @client_pages, @clients = paginate :clients, :per_page => 20, :order => "organisation_id, surname" currently im ordering by organisation_id however I need to order by the field in the organisation table organisations.name how can this be done? Thanks Scott -- Posted via http://www.ruby-forum.com/.

Hello. I call a find_all_by_subject("action") which returns 2 videos and displays them properly. But when I add @video_pages, @videos = paginate :videos, :per_page => 10 so I can paginate the videos, it displays ALL the videos as if I selected list videos. Can someone please tell me what I am doing wrong? Thank you. selectaction.rhtml <table> <tr> <% x = 0 %>

> Unfortunately I still get the same error. Here is my code now (the > commented line works): > > def list > @upload_pages, @uploads = paginate(:uploads, :per_page => > 20, :order > => ''id'') > # @upload_pages, @uploads = paginate(:uploads, :per_page => 20) > end You may have an older version, try using the order_by clause

I have a controller and list page for region object. My list page has a ''name'' text input that can be used to limit the list. It works except that the paginate gets the full set of regions unqualified by my search term. I believe this full list is contained in :regions symbol which I dont seem to be allowed to modify or replace (yes I am a ruby and rails newb). How can I

Hi, Why can''t I use a variable to specify the :per_page attribute when using the most basic form of pagination? (if I use a hardcode number, it runs) What did I do? Thx. My code: def list_orders page_size = 20 ... order_pages, @orders = paginate(:orders, :per_page => page_size) end My Errors: undefined method `>'' for false:FalseClass RAILS_ROOT:

I am having this problem with pagination query in my controller class. I am using SQL server and following code to create pagination fails, complains about column name ''program_name'' (which is valid column/attribute of program) The error message is: DBI::DatabaseError: S0022 (207) [Microsoft][ODBC SQL Server Driver][SQL Server]Invalid column name

Is there a quick and easy way to paginate something like @member.items (Member with has_many :items)? Right now I do in the controller: @item_pages, @member_items = paginate :item, :conditions=>["member_id=?", @member.id], :per_page=>25, :order=>''datetime desc'' It''d be more DRY if this was possible: @item_pages, @member_items = paginate

Hi Guys, I am trying to paginate the results from a search. When I use actual constants in the search conditions, it works fine: def query @k2_result_pages, @k2_results = paginate (:k2_results, :conditions => [''e_date >= ? AND e_date <= ?'', ''2006-07-12'', ''2006-08-12''],

Hi, I am using the rails find command as below @project_pages, @projects = paginate :projects, :per_page => 20, :conditions => "clients.organisation_id = " + params[''search''][''organisation_id''], :joins => ''inner join clients ON clients.id = projects.client_id'' There seems to be a problem with project.id being over written

Im using this paginate function to paginate complex sql queries http://www.bigbold.com/snippets/posts/show/389, all seems to work fine but theres one thing, when i hit the next link it show nothing, i mean it only shows the first page, here is the code im using: #application.rb----------------- def paginate_collection(collection, options = {}) default_options = {:per_page => 10, :page

How come I allways immediately run into difficult stuff when I''m trying some new programming language? Am I blind for the simplicity of Ruby/Rail, which a see must be there? Anyway, don''t try and answer this rhetoric question. I have got another one for you, seemingly difficult. I''m struggling with a n:m relationship (in a database, that is) and its join table.

mislav-will_paginate(will_paginate) doesn''t work after search. servers_controller.rb def index @servers = Server.paginate(:page => params[:page], :per_page => 20, :order => ''device_id ASC'') respond_to do |format| format.html # index.html.erb format.xml { render :xml => @servers } end end def search @servers =

i can use <%= link_to_remote("MEMBER LIST",:update => "mcont", :url => {:controller => :users, :action => :list }) %> this for user listing and then it display record i want to do paging on this list file but it is display one page when i click on second page this will no go to second my controller def list #@images = Image.paginate :page =>

Hello, I want to know how can I paginate a set of records. It seems there is no direct way of doing this, and I am not able to understand the documentation of paginate, so any pointers on how to do this will be much appreciated. To be specific what I want is that the records returned by user.recipes, the recipes of the particular user be paginated. My attempt to do this failed because

The automatically generated scaffolds made code like this: def list @address_pages, @addresses = paginate :addresses, :per_page => 10 end which was fine, but I only want to return the logged-in user''s addresses. So I changed it to: def list @address_pages, @addresses = paginate :addresses, :per_page => 10, :conditions => [''user_id = ?'',

I am a Rails newbie and I am trying to build a test site in which users will have their own sets of data. I understand how to manipulate shared data very well. Most of the Rails examples out there seem to deal with such shared data. I am struggling with the "best practice" method for a user to work with their own data however (and not be able to view/edit other users''

hi everybody, i am new to rails.. plz clear my doubt... this is my question In my table(public_topics), i have 11 rows of data.. whenever i run the following view, it shows the entire rows in the current page.. and i have set the '':per_page'' option to ''2''.so it must show two data per page..but it shows all the rows in a single page..and this case continue

hi i know i can do: @customer_pages, @customers = paginate :customers, :per_page => 8 but these customers have helpdesk calls which are child records. I hoped i could do something like paginate customers.calls, but dat doesn''t work what is the best way to get a paginated list of child records? remco -- Posted via http://www.ruby-forum.com/.

Hi all, I ve some troubles in my small acpplication (only 2 tables). I want to follow up tasks but these tasks are linked to others tasks. So I ve tried to do store the nn relationship in other table called links 1st table : tasks columns : id | infos neutral... (as title, description etc ...) ----------------------------------------------------------------------------------- model : class