similar to: NoMethodError

There must be a better way to write this code: @project_pages, @projects= paginate :project, :per_page => 10, :conditions => ["account_id = ?", account] ?! If only I could pass the sub-collection account = ... @projects = account.project to paginate, instead of letting it extract it with a find :all + sql conditions Alain. -- Posted via

I have the following: def index begin @restaurant_pages, @restaurants = paginate :restaurants, :order => (params[ :sort ] || "name"), :per_page => 2 @cuisines = Cuisine.find_all rescue redirect_to :action => :index end end # sort by cuisine def

Hi all, Is there a way to create pagination with a complex SQL, more complex than the :conditions option will support? I have two databases, houses and images. Houses has_many images, and each Image belongs_to house. I''m creating a search engine for the house records and I''d like to be able to filter out all the houses without any associated images. So far I''m

I have searched for days for an example that demonstrates what i would like to do, and this morning i thought i''d worked it out, but no....here''s what i have: Controller ========== class ProfilesController < ApplicationController def friends current_user.profile.friends end def list_friends @profile_pages, @profiles = paginate( friends, :per_page => 10) end end

i''ve figured out how to use the next and previous links with the paginator class but now i''m trying to figure out how to display all the page numbers in between. looking through the rails api, i found paginator.each() but i''m not sure how to use it, or if that''s even what i am looking for. also, is there a way to limit the amount of pages like some sites

hi everybody, i am new to rails.. plz clear my doubt... this is my question In my table(public_topics), i have 11 rows of data.. whenever i run the following view, it shows the entire rows in the current page.. and i have set the '':per_page'' option to ''2''.so it must show two data per page..but it shows all the rows in a single page..and this case continue

Im using this paginate function to paginate complex sql queries http://www.bigbold.com/snippets/posts/show/389, all seems to work fine but theres one thing, when i hit the next link it show nothing, i mean it only shows the first page, here is the code im using: #application.rb----------------- def paginate_collection(collection, options = {}) default_options = {:per_page => 10, :page

I''m just wondering where I would put the pagination for search results when using "acts_as_ferret". At the moment my search code is.. def search @query = params[:query] || '''' unless @query.blank? @results = Tutorial.find_by_contents @query end end Cheers SchmakO -- Posted via http://www.ruby-forum.com/.

Hi everyone, I''m at the end of my rope on this. I can''t get pagination to work with anything but a standard find on a model. If I try to do a search and customize the pagination, I get lots of different variations. My thought was to have the list action do what it does, but to pass it a list of search conditions from the search action. So, if search determines that we need

hi All, i wants to implement ajax pagination but i am facing a lot of problem , i found i lots of links on google but their is no explanation like what object we have to pass and condition can any body help me out in this concern pls i need your help as soon as possible thanks sachin --~--~---------~--~----~------------~-------~--~----~ You received this message because you are subscribed to the

Hello, I have 2 tables table colors : +----------------------+ | id | user_id | name | +----------------------+ | 1 | 1 | test1 | | 2 | 2 | test2 | | 3 | 3 | test3 | +----------------------+ table users : +----------------------+ | id | enabled | name | +----------------------+ | 1 | 1 | bob | | 2 | 1

Hi there, Is there a neat and easy way to implement pagination with letters rather than numbers eg : A B C D ... Z Rob

I am a Rails newbie and I am trying to build a test site in which users will have their own sets of data. I understand how to manipulate shared data very well. Most of the Rails examples out there seem to deal with such shared data. I am struggling with the "best practice" method for a user to work with their own data however (and not be able to view/edit other users''

Hi there, I''ve been trying to paginate over a list of members that all share a tag in common using the acts_as_taggable plugin. The regular way of paginating over a collection doesn''t seem to work with acts_as_taggable. Here''s what my method looks like that takes in a tag name, finds all the members that share the tag and then displays all the members. Nothing too fancy

Hi! I''ve got a list of project on the main page and if one of them is selected i render a partial using ajax with data of selected project. How to create links to next/previous project using pagination? -- Posted via http://www.ruby-forum.com/.

I have my list view filtering rows shown within the table <tr> tags like most of the introductory tutorials do. As I''m adding a few dozen entries I''m noticing the standard scaffolding pagination doesn''t pick up the number of rows from the filter since it is not being passed the number of rows returned within the scope of the filter statement. >From a

Just wondering how to best integrate with pagination and still stick to MVC... Say I have a Post model that has a published attribute. I want to show all the recent published posts on a page. My first instinct is to create a method in the Post model called recent that does the find with proper conditions and order, but the problem I have is how do I use that with pagination (which definitely

Hey all, I''m using a simple search function. It''s working great except for foreign keys. I have one table pets (id,name,owner_id) and another table people(id,name) owner_id being a foreign key of pet pointing to people name. here it is on the pet controller: @paginator, @pets= paginate(:pets, :conditions =>["name OR owner_id like

Hello, How do I get params from a form to use with a paginator? debug(params) shows this city: !map:HashWithIndifferentAccess id: "1" but in my controller, when I try to use @hotel_pages = Paginator.new self, Hotel.count(:conditions => "hotels.city_id = params[:city][:id]"), 3, @params[''page''] it doesn''t work. I suppose it''s a simple

Hi there everyone, I''ve recently moved to RoR and am still struggling with the basics of what used to be second nature in php, so on with my question: I have a database with products, and I need to create a search form that paginates the results. What I have so far in my controller is: def list # If the values are nil, then set them, otherwise wrap them in % # Also,