similar to: Pls sends your CV in www.allindiajobbank.com website. It is fast and gives U positive response. Pls pass this message to Ur friend also because vacancies are waiting.

Dear Friends, I do require centos 4.2 x86_64 cds here in delhi,India. If anyone of you can arrange that for me i will be vary grateful. The requirement is urgent. Thanks for your time and effort. -- Regards Abhishek Jain -------------------------------------------------------------------- mail2web - Check your email from the web at http://mail2web.com/ .

I want to store, retrieve and handle all times inside my app in just one Timezone. => "New Delhi" for that I''ve set in my application.rb file, config.time_zone = "New Delhi" When i create a record like Event.create(:when => DateTime.new(2011, 5, 7, 16, 0, 0)) it creates an event record in my mysql db (local) with "when" field as "2011-05-07

Hi Team, I using the syntax as: data.df<- data.frame( city= c(rep(c("Delhi", "Bangalore","Chandigarh"),each=5)), population= c(4000:6000,3500:4300,3000:3200) ) But i am getting the error as arguments imply differing number of rows: 15, 3003. Tried searching google but could not understand & find the solution. Thanks, Shivi [[alternative HTML version

Hello everyone! I'm Ayush Tomar, junior undergrad in Computer Science from New Delhi, India. I love C++ coding and working on machine learning and information retrieval project. I was exploring the GSoC ideas for Xapian and the project on "Adding Weighting Schemes" looked really interesting to me. I wanted to work on text mining/IR this summer and this idea seems perfect! I have

I am trying to do t-test to test whether the mean of one one column of the data frame is greater then another. please help me out. -- Arkajyoti Jana M. Phil/ 2nd semester Centre for Economic Studies and planning School of Social Sciences Jawaharlal Nehru University New Delhi-67 [[alternative HTML version deleted]]

hello sir myself Jyoti Sharma, and i am working as preoject fellow in IGIB Delhi. I need your help to know how to create a package as well as how to post that package to the CRAN mirror, for public use. i have used package.skeleton() command but its not working properly. So, please suggest me the right way asap. i'll be very thankful to you. Jyoti Sharma JRF @IGIB

I am new to R. I have a data like: x y z w p .......... m 1 10 15 20 25 30 2 11 16 21 26 31 3 12 17 18 19 20 4 51 52 53 55 67 ....... thus I have 145 rows

Hi, I have been trying to debug Xen using kdb. However, I am unable to successfully boot dom0 after compiling and installing kdb. Software/hardware config: Base distribution - Debian Lenny (64-bit) on a Dell desktop (Optiplex 780) with a serial cable to another machine. Xen 4.0.1 (without kdb) works fine. Here are the steps I followed to set up Xen-unstable with kdb. 1. Cloned code from

Hi All, I have an small issue, which is not creating any problem on working syatem but not sure about the problem that is why eager to know about it. I had installed Asterisk realtime with Asterisk 1.4.41. Every thing is working good but getting warning at Asterisk CLI. [Jul 26 21:17:36] WARNING[17811]: chan_sip.c:10571 check_via: '[' is not a valid host [Jul 26 21:17:36] WARNING[17811]:

In order to get around the problems of my posting a few minutes ago, I thought: $ awk -F\| '(NR > 2) {print $2}' cmie_firm_data.text > col2 $ awk -F\| '(NR > 2) {print $4}' cmie_firm_data.text > col4 $ paste col2 col4 | head -2 -510.45 -510.27 60700 101900 $ paste col2 col4 | tail -2 28648.12 31617.02 491014.77 494308.52 $ wc -l col2 col4 89323 col2

I am discovering sapply! :-) Could you please help me with a very elementary question? Here is what I know. The following two programs generate the same answer. --------------------------------+---------------------------------------- Loops version | sapply version --------------------------------+----------------------------------------

I know that this is correct: library(chron) x = dates("01-03-04", format="d-m-y", out.format="day mon year") print(x) It gives me the string "01 Mar 2004" which is correct. I also know that I can say: print(day.of.week(3,1,2004)) in which case he says 1, for today is monday. My question is: How do I combine these two!? :-) I have a

hi , lik <- function(nO, nA, nB, nAB){ loglik <- function(par) { p=par[1] q=par[2] r <- 1 - p - q if (c(p,q,r) > rep(0,3) && c(p,q,r) < rep(1,3) ) { -(2 * nO * log (r) + nA * log (p^2 + 2 * p * r) + nB * log (q^2 + 2 * q * r) + nAB * (log(2) +log(p) +log(q))) } else NA } loglik }

Hi all, I have n no. of extensions in my dialer. from 456 to 556 extensions. I was created 2 other extensions 667 and 668 I need to allow only STD calls to go from this extensions. These all extensions are same context . I need to define the STD dialplan for only this 2 extensions. how I can ? Best Regards, Mahesh Katta *BUZZ**WORKS* Business Services Private Limited BANGALORE | CHENNAI |

Respected all, I am working on a socio-economic survey (named as National Sample Survey in India provided by National Sample Survey Organization, Govt. of India) data of individual as well as households. This is a sample survey where stratified random sapling method has been used to draw samples. The data set uses 'weights' to estimate figures for region, state or

I'm in this situation: factorlabels <- c("School", "College", "Beyond") with data for 8 families: education.man <- c(1,2,1,2,1,2,1,2) # Note : no "3" values education.wife <- c(1,2,3,1,2,3,1,2) # 1,2,3 are all present. My goal is to create this table: School College Beyond

x <- iris$Sepal.Length[1:50]/iris$Sepal.Width[1:50] y <- iris$Petal.Length[1:50]/iris$Petal.Width[1:50] I want to check whether (x,y) follows a bivariate normal distribution or not, using density plot or scatter plot. Is it possible to plot a bivariate density in R. I cant find any. Arindam Fadikar M.Stat Indian Statistical Institute. New Delhi, India [[alternative HTML version

4000:6000 gives you 4000, 4001, ..., 6000. I suspect you want population= c(seq(4000, 6000, length=5), seq(3500, 4300, length=5), seq(3000, 3200, length=5)) Bob On 20 September 2017 at 17:07, Shivi Bhatia <shivipmp82 at gmail.com> wrote: > Hi Team, > > I using the syntax as: > > data.df<- data.frame( > city= c(rep(c("Delhi",

Hi, Can we find the size of memory a pointer is pointing to in LLVM. For example type *p = (type *)malloc(sizeof(type)*20); then it should give us size as sizeof(type) * 20. -- Sunil Rathee MTech IIT Delhi Not going along with the crowd can help you stand out in the crowd -------------- next part -------------- An HTML attachment was scrubbed... URL:

Hi, Within the basic block I got the instructions and so the operands i got the operands. Can we get the size of the operands. Specifically, if operand is of type structure, Can we get size of this operand? -- Sunil Rathee MTech IIT Delhi Not going along with the crowd can help you stand out in the crowd -------------- next part -------------- An HTML attachment was scrubbed... URL: