similar to: Idiomatic way to do a non-database Enumeration?

Hi, I am wondering if there is a way to display the full anme of the regression coeffients/factors in the summary? Suppose I have a bogus data set using weekday as factor which has 7 levels such as: mydata <- sample(364) wk <- rep(1:7, 52) weekday <-

Hi, I am wondering if there is a simple way to fix the problem I am having. For unknown reason, I could not get the full name of the factors to be printed in the summary. I have tried to used summary.lm as well but the problem still persists. SJ$Weekday <-

Hi, I am trying to count weekday of the month using R. For example, 1/4/2001 is the 4th weekday of Jan, and 1/5/2001 is the 5th weekday of the month, and 1/8/2001 is the 6th weekday of the month, etc. I get as far as extracting the weekdays from a sequence of dates (see below). But I have not yet figured out a fast way of counting without using a For Loop. Does anyone know how to do such counting

(Sorry for reposting. Please delete previous msgs. Thanks!) Hi, all Here I created a data frame like mydates<- seq(as.Date("2010-05-29"), length = 43, by = "day") myvalues<-runif(43,0,1) myframe<-data.frame(dates=mydates, day=weekdays(dates), value=myvalues) dates day value 1 2010-05-29 Saturday 0.14576143 2 2010-05-30 Sunday 0.37669604

Hi, all Here I created a data frame like mydates<- seq(as.Date("2010-05-29"), length = 43, by = "day") myvalues<-runif(43,0,1) myframe<-data.frame(dates=mydates, day=weekdays(dates), value=myvalues) dates day value 1 2010-05-29 Saturday 0.14576143 2 2010-05-30 Sunday 0.37669604 3 2010-05-31 Monday 0.74813943 4 2010-06-01 Tuesday

R experts, I am working with a fairly large data set comprised of 563 rows by 116 columns including several different modes. I have been unable to read in the data set completely using the read.table function and the RGui (i.e. nearly half the total number of rows are missing from the data set along with the column names). The data does read in fully using Tinn-R's Rterm; however, at several

Question from an [R] novice... Hi, I have a vector of date/times like the one shown below (a truncated sample of a much longer list...) > dates[1:4] [1] "2006-03-16 08:41:00" "2006-03-16 10:28:00" "2006-03-16 11:03:00" [4] "2006-03-16 11:04:00" I would like to generate a weekday histogram showing the frequency of dates falling on each weekday. I know

Hi, I am trying to replace (lattice) standard xyplot with xYplot variant from Hmisc package to be able to add error bars to my plots. However, this does not work, e.g: library(lattice) d <- data.frame( SKU=gl(3, 1, 21, labels=c("a", "b", "c")), Weekday=gl(7, 3, 21), QCRate=runif(21)) xyplot(QCRate ~ Weekday | SKU, data=d) (this plots nice 3 panels as per

Dear R-Gurus I have a data frame (from CSV file) which has its first column called Date. The Date is in the format mm/dd/yyyy. I was trying to get the weekday for these dates and I tried using wday() and day.of.week() functions and both of them gave me precisely the wrong answers. I think the issue lies in the proper formatting of dates. The class of this column is a factor class and hence I

Hi all, probably really simple: I seem to be lacking some understanding for the character class: I have a bunch of dates in a dataframe and I want to add a string variable with the weekday for each date. If I use something like mydata$day <- weekdays (mydata$date), I can create subsets for each weekday (eg mydata=="Monday"), but summary (mydata$day) doesn't count the instances for

Hello, I am currently doing my project and I need some help. I am trying to schedule tutors for a study room where students come in and out for helps. My goal is to schedule the tutors to maximally accomodate to the flow of students that need help with math so that each tutor is given an appropriate(also consecutive) hours of schedule. I am using monte carlo simulation for this, however I have

Hi All, I'm fitting an intercept ANOVA model using R. I'm using following contrast statement, so my first level is considered as base level. options(contrasts = c("contr.treatment", "contr.treatment")) My data has two factors are "Month" and "WeekDay". Due to default alphabetic ordering, the Month(April) and WeekDay(Friday) are considered as base

For what it's worth, I tried setting my Region | Formats setting to Spanish (Peru) in Windows 10 Control Panel, and got Spanish weekday and month results. I believe on Windows we use the Microsoft C strftime function to produce these strings, with the %A (for weekday) or %B (for month) formats. So this question probably needs to be addressed to Microsoft. Duncan Murdoch On 05/06/2017

I'm an R noob and have a (maybe) stupid question... I have a table where I have the weekdays and a number for each weekday of entries: Thats what the table looks like... Now I want to have an pie3D plot of this, but obviously the order of the weekdays are not as one would expect... Friday Monday Saturday Sunday Thursday Tuesday Wednesday 119 173 80

Thank you Duncan and Rui for your time and interest in this issue. Maybe it is a problem with Windows 7 and Spanish, and not Windows 10. Let's wait for someone with the same enviroment, before assuming it's a problem with my PC/configuration. 2017-06-05 14:37 GMT-05:00 Duncan Murdoch <murdoch.duncan at gmail.com>: > For what it's worth, I tried setting my Region

Fellow R users, I am stumped on what would seem to be something fairly simple. I have a dataframe that has a variable named 'WEEK' that takes the numbers 1:26 (26 week time-period) with each number repeated five times consecutively (once for each weekday, Monday through Friday). Ex. 111112222233333.....2626262626. I would like to randomly extract two weekdays per five day week for

Hello, I have a dataset which has fields giving both calendar date and weekday. I know better functions are now available, but I am still using chron because of the is.holiday() function and a homemade (even Heath Robinson would be ashamed) is.daylight() function. As a check for typos in the data input, I checked that the dates matched the weekdays. I'm getting some confusing results

Dear kind R helpers, I have a vector of runway names in rwy ("31R", "31L",... the number is user selectable) arrgnd is a data frame with data for all flights and all runways, with a Runway column. I am trying to subset arrgnd into a dat frame for each selected runway, and then combine them back together using the following code: for (j in 1:nr) { # nr = number of

I''m working on a fairly complex join query and could use a bit of advice from more expert users of ActiveRecord. I have an events table with quite a lot of data, with has_many relations to categories, age_groups, and event_images. In my first naive implementation, each event had a date, so to load all upcoming events efficiently, I''d do: Event.find(:all,

Is there a way to clear the Queue stats? That is with out restarting *? I'd like to reset them daily and don't see a way to do that. Unless the only way is maybe a cron restart asterisk like every weekday @ 04:00?