similar to: Anybody have a week ending date helper?

I''ve tried Time.parse() and DateTime.parse() but they interpret the date as US format. Is there any way to tell it to interpret as dd/mm/yyyy? -- Posted via http://www.ruby-forum.com/.

I''ve been banging my head against this wall for several hours, and it hurts now so I''ll stop and ask someone. In one of my forms I had been using a statement to extract the current year for use with some form field calculations. <% currentyear = DateTime.now.year %> And then further down several date_selects like the following, <%= date_select

I have an application where user sets his/her preferred date/time format. User is expected to enter datetime in his preferred format across the application. Now the problem is for few formats the datetime is parsed wrongly while create/update ActiveRecord. For example user has set date/time format in hh:mm dd/MM/yyyy. Now if user enters 17:00 04/05/2012 it parses it as 5 PM 5 Apr, 2012 where it

Hey all, I''m working on a site for a client that has a scedule im trying to display that pulls the next events for the upcoming Sunday from a MySQL table....The table stores the event date as mm/dd/yyyy. I''ve tried to think of everyway possible to get this thing to change after every sunday to show the next sunday''s events, but I end up doing it manually... Is it

Dear R Community, I am new to R, and have a question that I suspect may be quite simple but is proving a formidable roadblock for me. I have a large data set that includes water-quality measurements collected over many 24-hour periods. The date and time of sample collection are in a combined Date/Time field in the format yyyy-mm-dd hh:mm:ss. I need to be able to subset the data for analysis of

Within an R dataset, I have a date field called “date_”. (The dates are in the format “YYYY-MM-DD”, e.g. “1995-12-01”.) How can I add or subtract “1 month” from this date, to get “1996-01-01” or “ “1995-11-01”. --------------------------------- [[alternative HTML version deleted]]

Hello All, I have 1M rows of time stamped information about delivery trucks and their trip related information from simulation .Detailed info the column names and attributes for clarity 1. id: alphanumeric factor/character 2. datetime.of.trip.start: POSIXct yyyy-mm-dd hh:mm:ss 3. datetime.of.trip.end: POSIXct yyyy-mm-dd hh:mm:ss 4. trip.distance: numeric, miles 5.

Hey there all, Is there some way to tell rails or sql server to ignore the time in a datetime field when doing a comparison? For example, if I do something like select * from users where registration_date = ?, @date where @date might equal some user input like ''03/14/2006'' The result is nothing returned, because in my tables the datetime field looks like this: 3/14/2006

I have a table with "expires_on" a DATE field. "Show" and "Destroy" work, but "Edit" errors: /usr/local/lib/ruby/gems/1.8/gems/actionpack-1.11.2/lib/action_view/helpers/date_helper.rb:150:in `select_hour'' /usr/local/lib/ruby/gems/1.8/gems/actionpack-1.11.2/lib/action_view/helpers/date_helper.rb:149:in `select_hour'' It only happens when

I''ve found an issue when trying to use the time_ago_in_words and distance_of_time_in_words from action view''s date_helper.rb Using SQL Server, I have a datetime column that gets returned as: "2007/02/21 09:54:00". When I pass this to time_ago_in_words (which just passes on to distance_of_time_in_words) it miscalculates the difference as "9 hours" (...um yeah,

Dear list, I need to transform the DateTime of my GPS data from: "666.1751" into "yyyy/mm/dd hh:mm:ss" I have the following code: d$Date <- ISOdatetime(2009, 1, 1, 0, 0, 0, tz = "GMT")+d$Date*(24*3600) This gives me: 2010-10-29 04:12:09, which is wrong. It should be 2010-10-29 06:12:09 Another example: 418.3219 corresponds to: 2010-02-23 07:43:30, but it

The (*windows only*) xlsReadWrite package has been updated and the new version is available on CRAN. xlsReadWrite natively reads and writes Excel files (v97 - 2003). o Changes from v1.1.1 to v1.3.3 (versions between never really published) - ROWNAMES-support also for matrices (not only for data.frame) - explicit rowNames argument in interface. (stimulated by email Adrian Dusa) -

I don''t believe that Rails has support for the inline editing of datetime objects or dropdown combo boxes. Does anyone have a helper function or two that would allow me to do such a thing? -- Posted via http://www.ruby-forum.com/.

Dear list, I have to look examine hourly time - series and would like to plot variable section of them using plot.zoo. Hourly time series data which looks like this: YYYY MM DD HH P-uk P-kor P-SME EPOT EREA RO R1 R2 RGES S-SNO SI SSM SUZ SLZ 2003 1 1 1 0.385 0.456 0.021 0.000 0.000 0.000 0.013 0.223 0.235 0.01 0.38

I know this: > library(date) > x="1979-04-04" > try=as.date(x, "ymd") > print(try) [1] 4Apr79 and that `x' here has to be a string, e.g.: > x=1979-04-04 > print(x) [1] 1971 I'm stuck in reading from a file. I say: > A <- read.table(file="try") > print(A) V1 V2 1 1979-04-04

Oleksij Rempel <bug-track at fisher-privat.net> wrote: > Ok, > you are right, using existing technology will save time :) What has not yet been discussed is what you are streaming *to*. That is to say, what software is going to receive the metadata, and what will it do with it. This is important because VorbisComments can contain pretty much anything you want. Suggestions for field

What''s the best way to check a field to ensure it is a valid datetime? I could validates_format_of :with a regular expression for "yyyy-mm-dd hh:mm:ss", but I''m wondering if there is a more direct way to do this. -- Posted via http://www.ruby-forum.com/.

Hello R Users, How to convert decimal date to date as YYYY.mm.dd.hr.min.sec For example, I have decimal date in one column , and want to convert and write it in equivalent date(YYYY.mm.dd.hr.min.sec) in another next six columns. 1979.000000 1979.020833 1979.041667 1979.062500 Is it possible in R ? Kindly help, Regards, Yogesh -- Dr. Yogesh K. Tiwari, Scientist, Indian Institute

Hi folks, I have been tormented for some time by Excel's habit of exporting dates to CSV files as mm/dd/yyyy format even if the dates are formatted dd/mm/yyyy in the display. What's worse, if there are dates that are of ambiguous (6/6/2011) and unambiguous (16/6/2011) format in the same column, Excel reformats the unambiguous dates and leaves the ambiguous ones as they were! Yesterday

Hi all, I am using InstantRails with MySQL-Front. Date is stored in format yyyy-mm-dd in database. I want to retrieve and show date in dd-mm-yyyy in my view.rhtml. How can I change it to dd-mm-yyyy form. Please help me out. Thanks -- Posted via http://www.ruby-forum.com/. --~--~---------~--~----~------------~-------~--~----~ You received this message because you are subscribed to the Google