similar to: LARTC related talks at Swiss Unix Conference 2004

Surprisingly, I played around with some test code and below actually creates equations that look correct. tempmat<-matrix(10,nrow=6,ncol=6) restrictmat<-diag(6) colnames(tempmat)<-c("AUD.l1","CHF.l1","CAD.l1","GBP.l1","EUR.l1","JPY.l 1")

Hi, I have an xts starting with a number of columns (currency pairs see below), then I add new ones which are derived from existing ones (like adding the moving average of a column) by merging the new columns one by one. These get the name of the column they are calculated from concatenated with ".1". All done by merge.xts, easy. Now, I have a function (procState below) which generates

Hi all I extended the Globalize Plugin the following way: -------- module Globalize class Currency def conversion_rate code = Locale.active.currency_code rates = { :USD => 1, :CHF => 0.75, :EUR => 1.1, :GBP => 3.1 } value = rates[code.to_sym] raise "No conversion rate found for currency

*Hola!!! resulta que tengo unos datos de divisas ordenados por fechas (días) los que he convertido a formato tipo YYYY-MM-DD donde DD siempre es 01:* * * * EUR.resto$date<-as.Date(EUR.resto$date) EUR.resto$mo <- substr(EUR.resto$date,6,7) EUR.resto$yr <- substr(EUR.resto$date, 1,4)

Hello, I'm willing to donate hardware, see the IRC log below for a few details. If you are interested, reply to "christoph at alte-pflasterei.de", I'll send an Open Document Spreadsheet then with the complete card list containing all details I know. -8<---- IRC chat log --------------------------------- (2019-09-04 16:50:54) chf: Hi, is any of the developers interested in

My mistake sir. I was literally engrossed in my stupid logic, and while doing so, overlooked the simple and very effective solution you had offered. Sorry once again sir and will certainly try to be very careful in future. Thanks again and have a great weekend sir. Regards Amelia --- On Fri, 7/1/11, Petr PIKAL <petr.pikal@precheza.cz> wrote: From: Petr PIKAL

Dear sir, I am extremely sorry for messing up the logic asking for help w.r.t. my earlier mails   I have tried to explain below what I am looking for.     I have a database (say, currency_rates) storing datewise currency exchange rates with some base currency XYZ.   currency_rates <- data.frame(date = c("12/31/2010", "12/30/2010", "12/29/2010",

I have two R objects, allDataSubset1 and allDataSubset2 and the str of both of them is shown below ( I don't show all 18 lists for space purposes ). The difference between them is that the times ( and possibly the days ) and the data is different and what I want to do is merge them so that only the data in Subset2 that is the same day and times as Subset 1 remains in the merged dataset.

Dear List, I posted this in R-mixed and did not receive any feedback. I might post it in the wrong place. I re-post in R-help and hope to receive any suggestions and\or thoughts regarding data analysis. The objective of the study is to investigate effects of soil properties on insect outbreaks. There are four study fields (or sites). Data were collected from 1996 through 2009. Below is

Dear R forum helpers, I am extremely sorry for the receipt of my incomplete mail yesterday. There was connectivity problem at my end and so I chose to send the mail through my cell, only to realize today about the way mail has been transmitted. I am again sending my complete mail through regular channel and sincerely apologize for the inconvenience caused. ## Here is my actual mail Dear R

Dear R users: I want to convert some character vectors into numeric vectors. > head(price) [1] "15450 EUR" "7900 EUR" "13800 EUR" "3990 EUR" "4500 EUR" [6] "4250 EUR" >head(mileage) [1] "21000?km" "119000?km" "36600?km" "92000?km" "140200?km" [6] "90000?km" in

Hi, I have recently been playing with the grid package in an attempt to create some pages containing multiple lattice plots on the same page. However, when I specify a grid layout with different widths, such as: pushViewport(viewport(layout = grid.layout(1, 2, unit(c(2, 1), "null")))) the individual graphs do not end up as the same height - which is a feature I would prefer to have.

Hi R users, I have a dataframe in the below format xyz 01/03/2007 15.25 USD xyz 01/04/2007 15.32 USD xyz 01/02/2008 23.22 USD abc 01/03/2007 45.2 EUR abc 01/04/2007 45.00 EUR

This is a question about how to calculate similarities/distances among items that are classified by hierarchical attributes for the purpose of visualizing the relations among items by means of clustering, MDS, self-organizing maps, and so forth. I have a set of ~260 items that have been classified using two sets of hierarchically-organized codes on the basis of form and content. The data looks

Hi, i export data from an csv file like this :  Data <- read.csv2("c:/Art.csv",sep=",") # import data into R > Data <- Data [1:5,1:5]# extracting the first 5 rows and columns > Data   Policy.Number AXA.Entity Country LoB ccy.data 1         6e+13        BNL     BNL   P      EUR 2         6e+13        USA     BNL   P      EUR 3         6e+13         UK     BNL  

  Hi, i export data from an csv file like this :  Data <- read.csv2("c:/Art.csv",sep=",") # import data into R > Data <- Data [1:5,1:5]# extracting the first 5 rows and columns > Data   Policy.Number AXA.Entity Country LoB ccy.data 1         6e+13        BNL     BNL   P      EUR 2         6e+13        USA     BNL   P      EUR 3         6e+13         UK     BNL  

I have a vector of character strings such as mainnames<-c("CAD","AUD") and another vector say checknames<-c("CAD.l1","AUD.l1","JPY.l1","EUR.l1","CAD.l2","AUD.l2","JPY .l2","EUR.l2") I want a new vector of character strings that is just

Folks, I have three dataframes storing some information about two currency pairs, as follows: R> a EUR-USD NOK-SEK 1.23 1.33 1.22 1.43 1.26 1.42 1.24 1.50 1.21 1.36 1.26 1.60 1.29 1.44 1.25 1.36 1.27 1.39 1.23 1.48 1.22 1.26 1.24 1.29 1.27 1.57 1.21 1.55 1.23 1.35 1.25 1.41 1.25 1.30 1.23 1.11 1.28 1.37 1.27 1.23 R> b EUR-USD NOK-SEK 1.23 1.22 1.21 1.36 1.28 1.61 1.23 1.34 1.21 1.22

I'm trying to do a Hosmer-Lemeshow 'goodness of fit' test on my logistic regression model. I found some code here: http://sas-and-r.blogspot.com/2010/09/example-87-hosmer-and-lemeshow-goodness.html The R code is above is a little complicated for me but I'm having trouble with my answer: Hosmer-Lemeshow: p=0.6163585 le Cessie and Houwelingen test (Design library): p=0.2843620

Hi, Gordon Smyth brought the following problem to my attention. PROBLEM/"BUG": Using R v1.9.0 alpha for Windows and the latest Rtools from Brian Ripley you get the following problem trying to R CMD build a package (or a bundle); >R CMD build R.basic * checking for file 'R.basic/DESCRIPTION' ... OK * preparing 'R.basic': * checking whether 'INDEX' is