similar to: How to change Date format

Hi, In my form I have date field set as ''datetime_select'' which is fine as I wanted it in the same format. But while displaying (list action) it displays date in long format i.e. ''Tue May 30 15:39:00 Central Daylight Time 2006''. How can I format it so that it will just be diaplyed as ''dd/mm/yyyy'' format? Thanks -- Posted via

Hi, I have a few dates coming from the datebase in the format ''DD-MM-YYYY'' How can I change this in to a more human readable format? such as 1st July 2006 Thanks Scott -- Posted via http://www.ruby-forum.com/.

I have a user table, and it has forty columns, including name, gender, address, email, phone... So my @user object will have forty attributes. I divide these attributes into 4 groups... namely ''general info'', ''personal info'', ''contact info''... and I make separate forms to edit these 4 different group attributes. The problem is when I update

I have a customer that has a request that the select_datetime fields have AM/PM selectors instead of 24 hour time. The rails time and datetime selects seem to only support 24 hour time. I can''t seem to find any information on this. i was wondering if there is already a solution out there, or will i have to roll my own? Sean Wolfe master nerd of i heart squares, inc. 3711 N.

When I convert a datetime to a string, it prints out something like this Jan 20 12:00:00 EST 2006 I want to trim off the last twelve characters, i.e. :00 EST 2006 I tried to do it like so: @date = @meeting.date.to_s.chomp.chomp.chomp.chomp.chomp.chomp.chomp.chomp.chomp.chomp.chomp.chomp but the chomps seem to do nothing. I''d love to use regex, but I don''t know which

Hallo, I am trying to plot dates in x-axis. The format of my dates are in dd/mm/yyyy. At first I install zoo package. After R reads my file, I change the default format of dates to the format that I have, >myfile<-read.csv >DATE<-as.Date(DATE,format="%d/%m/%Y") up till now everything goes ok; when however I go and plot for example >plot(DATE, Discharge) in the x-axis I

hi all, i want my users to enter a date in "ddmmyyyy" format, do someone know how may i transform it in "yyyy-mm-dd" in the controler before i add it to the base please? thks irong -- Posted via http://www.ruby-forum.com/.

hi, overhere users go nuts if they have to enter the date in iso format, so i have to make my applications in such a way that not only dates are displayed in the "dd-mm-yyy" format but also can be entered in that way. somewhere i found this code to put in the environment script: ActiveSupport::CoreExtensions::Time::Conversions::DATE_FORMATS.update( :default => ''%d/%m/%Y

Hi, I''m stuck. How do you parse a "dd/mm/yyyy" formatted date string??? I get a date format error. Thanks in advance Greg --~--~---------~--~----~------------~-------~--~----~ You received this message because you are subscribed to the Google Groups "Ruby on Rails: Talk" group. To post to this group, send email to

Hi all, I need to use asterisk to record all phonecall I have test using mixmonitor to record a call. Now I need to set the configure file to let asterisk auto record all calls. I have searched many document but still can not succeed. My version is 1.8beta and I prefer using mixmonitor. Regards!

I am trying, without success, to compile a custom locale for the utf-8 character set. I have issued this command: localedef --no-archive -f UTF-8 -i /usr/share/i18n/locales/en_CA at yyyy-mmm-dd en_CA at yyyy-mmm-dd.utf8 which produces the requisite files without reporting an error but which none-the-less insists on using the iso-8859-1 charset: LC_ALL=en_CA at yyyy-mm-dd locale charmap

The ruby code in this isn''t evaluated... flash[:notice] = "Your last recorded entry was <%= @in_out.time_in %> <br />You are currently marked as ''In'', you probably want to check ''Out''" Is there a way? Craig

I''ve spent all day digging through the rails api and postgres-pr on this, I think it''s time to ask the list. Postgres stores a Date in YYYY-MM-DD format. My users want the dates in MM/DD/YYYY format. Sure, I could explicitly convert it on the app level every place where a date is displayed, but that seemed like a DRY violation. I thought I''d be clever and simply

In trying to use as.Date(), I've come across the conversion of POSIXlt to POSIXct when a POSIXlt variable is included in a data frame: my_POSIX <- strptime(c("11-09-2006", "11-10-2006", "11-11-2006", "11-12-2006", "11-13-2006"), "%m-%d-%Y") str(my_POSIX) my_Date <- as.Date(my_POSIX) str(my_Date) data <- format(my_Date)

Hi- Is it possible to use search parameters with will_paginate? For example, something like this: @var = Model.paginate :per_page => 20, :page => params[:page], :order => ''my_date DESC'', :conditions =>["my_date >= ? AND my_date <=?",@start,@end] I am getting some errors with this, but will this generally work?

Hi all: How do I create opus encoder and decoder executable on Windows using MS Visual Studio 2010? What I'm doing is the following: 1. I downloaded the codebase on my local drive using: $ git clone git://git.opus-codec.org/opus.git 2. Then I go to D:\opus\win32\VS2010 and open the opus.sln using MS Visual Studio 2010. 3. Then I build the solution opus. I get 3 executable at

https://bugzilla.mindrot.org/show_bug.cgi?id=3781 Bug ID: 3781 Summary: IPv6 inconsistency causes TOFU Product: Portable OpenSSH Version: 9.7p1 Hardware: All OS: Other Status: NEW Severity: normal Priority: P5 Component: ssh Assignee: unassigned-bugs at mindrot.org

Hello List, with CentOS 7.2 it is not longer possible to run fail2ban on a Server ? I install a new CentOS 7.2 and the EPEL directory yum install fail2ban I don't change anything only I create a jail.local to enable the Filters [sshd] enabled = true .... ..... When I start afterward fail2ban systemctl status fail2ban is clean But systemctl status firewalld is broken ? firewalld.service -

On 2/17/2016 10:32 AM, Rowland penny wrote: > On 17/02/16 18:07, Ian wrote: >> Actually, that works for me too. I just issued the command 'chgrp >> "BUILTIN\administrators" CoreLib' and it returned successfully for that >> folder. 'ls -la' shows: >> d---------+ 2 MMIA\domain admins BUILTIN\administrators 5 Dec 8 11:59 >> CoreLib//

Dear list, I am trying to evaluate how many elements in a vector equal a certain value. The vectors are the columns of a data.frame, read in using read.table(): > dim(data) [1] 2600 742 > data[1:5,1:5] SNP001 SNP002 SNP003 SNP004 SNP005 1 GG AA TT TT GG 2 GG AA TC TT GG 3 GG AC CC TT GG 4 AG AA TT TT GG 5