similar to: Django and Rails...

Hi I''ve got a little quetion. For school I''ve to make a blog either using ruby on rails or Django. I''ve to do this at home, install the languages, etc. I''ve to make screenshots while running the language and blog. tell why I chose that language and the files i made for the blog. What would be the fastes way to do this?? Thanks a lot already -- Posted via

Hi I''d like rails to create the tables in the DB if they do not exist. Is this possible? Is there an easy way to do this? DJANGO does this which is nice, Thanks, Chris -- Posted via http://www.ruby-forum.com/.

Hello, This post is to announce a new release of the Spatial Adapter for Rails, which is a plugin that adds support for columns of geometric types (point, linestring, polygon,etc...) to ActiveRecord. Currently the only supported databases are MySql and PostGIS. With this release, geometric columns should behave like columns of any other basic types in all areas: migration, data access, dumping

My organisation is currently looking at Django and Rails. Has anyone tried Django? What was your experience? Do you prefer Rails or Django? Thanks, Chris -- Posted via http://www.ruby-forum.com/.

Anyone here using django on centos. On my Mac, running python 2.7, I upgraded from 1.4 to 1.5 by doing this: rm -rf /Library/Python/2.7/site-packages/django Followed by python setup.py install in the dir I untar-ed Django-1.5.1 to. This all worked fine. On a Centos system running python 2.6 I did: rm -rf /usr/lib/python2.6/site-packages/django followed by the setup.py install. My django app

HI am using Highchart on rails on heroku. View Source of : http://localhost:3000/highchart RAILS_ENV=production series: [{name: "Restaurants",pointInterval: 86400000,pointStart: 1207526400000,data: [[1325462400000, 4], [1325462400000, 5], [1325462400000, 3], [1328140800000, 5], [1328140800000, 3], [1328140800000, 4], [1330646400000, 3], View Source of :

We've got an application in django that has passwords stored in both sha1 and pbkdf2_sha256 form. We need dovecot to be able to authenticate against the django database (we can't modify django to store passwords in dovecot's form, I'm afraid). Has anyone done a dovecot authentication plugin to support these password forms (and/or any other forms that django supports)? Thanks-

Hi, I`ve searched the net looking for a way to synchronize users in a django-based web project ( www.djangoproject.com ) with samba users. I want all registered django users to have access to a user-specific password protected share and I want to maintain the users using django`s built-in user management. My question is easy; can I add/edit/delete samba users, samba shares, set samba passwords

Hi, please have a look at http://www2.jeffcroft.com/2006/may/02/django-non-programmers/ especially the screenshot in the middle with the Calender. Instead of 3 selectfields with day, month, year I find this one much more userfriendly, also having yesterday, today and tomorrow. Are there plugins for this? I know http://www.dynarch.com/projects/calendar/ which I often included in my php-sites, and

Hello, Does anyone know where I can find information on using ext3 with Django. Specifically, I want to place Django template tags inside of a particular panel in my ext3 viewport... I have tried what is seen below, but it doesn't seem to work.. var viewport=new Ext.Panel({ layout: 'border', width:1200, height:650, renderTo: Ext.getBody(), items: [{

Hi, I am building an application where i need to have an admin interface from where the admin can assign permission for different methods (create, edit etc.) in controller based on roles . It should be similar to django administration, where we can assign permission on methods based on the role. How can i do the implementaton ? Can anybody give me some pointers on how to start ? Thanks and

Hi I am the newbie to both Django as well as ROR.... Which one i have to choose as my carrier one.... And what is the main difference.... Djkango in Python & It is in Ruby.. which one is best to easy learn and about security Thank you... -- WithRegards... K.Ramkumar Blog at http://fallinlinux.wordpress.com/ contact : 97915 89522

Hi, In the great tradition of web framework comparisons ;-) : here is a blog entry focused on a source code analysis of RoR, Django and Seam: http://www.mininglabs.com/2008/05/13/web-frameworks-a-free-software-oriented-study --~--~---------~--~----~------------~-------~--~----~ You received this message because you are subscribed to the Google Groups "Ruby on Rails: Talk" group. To

Don't know if anyone here can help me or not, but here's my problem: I have a django app. I develop on a Mac, but it's deployed on CentOS. I've been doing it like this for a long time with no issues. Today I changed a template on my Mac, and the change was picked up, no problem. I checked my change into git, went to a CentOS box, pulled the change down, but django is not picking

OK. This may help, but it will also make your head hurt. The basic problem that you''re running into is that you want a "for all" operator and sql doesn''t have one. Instead, you have to think of the query in terms of the logically equivalent "not exists not". Effectively, a proposition is true for all x if you can''t find a counter-example in

I''ve got a Cuisine and a Restaurant model, with a habtm. One thing I want to do is find all the cuisines that have at least one restaurant associated with them. Right now I''m using the following SQL query: SELECT DISTINCT(cuisines.*) FROM cuisines, restaurants, cuisines_restaurants WHERE cuisines.id = cuisines_restaurants.cuisine_id AND restaurants.id =

I have the following: def index begin @restaurant_pages, @restaurants = paginate :restaurants, :order => (params[ :sort ] || "name"), :per_page => 2 @cuisines = Cuisine.find_all rescue redirect_to :action => :index end end # sort by cuisine def

So, I''m coding my school project in Rails. There are two models, User and Restaurants. I noticed that in Restaurants, when you use the belongs_to method, you could specify the condition of the associated table. There are a few types of users, in the user_type column of the users table - owners is type 1, users are type 2. So in my haste to hand in enough code, in the Restaurant model,

Is it my environment? Is something wrong, cause I thought this should just work? I have a simple table and I created a model and a controller: ruby script/generate controller Restaurant ruby script/generate model Restaurant I edited the controller to this: class RestaurantController < ApplicationController scaffold :Restaurant end I run it and: http://0.0.0.0:3000/Restaurant works

My client is a flourishing, integrated global marketing agency with offices all over the world. We work with amazing Fortune 1000 brands that are household names. Project work runs the gamut - from microsites, digital installations and social media to online videos, responsive design and mobile/tablet apps and sites. We''ve won just about any industry creative award you can think