similar to: Shirewall and ppp interface

> > ---------- Mensaje reenviado ---------- > From: Roberto C. Sánchez <roberto@connexer.com> > To: shorewall-users@lists.sourceforge.net > Date: Fri, 4 Jul 2008 18:52:36 -0400 > Subject: Re: [Shorewall-users] Shaper > On Fri, Jul 04, 2008 at 04:47:31PM -0500, RokeFeler wrote: > > Saludos, Tengo 3 inferfaces eth0, eth1, eth2 > > eth0 - Net > > eth1 -

Hi all, I finally got my IPSec tunnel from my Fedora firewall system (running Shorewall 4.0.6) to a remote Draytek Router up-and-running, but I''m having difficulties directing traffic through the tunnel. From the output of "racoon -F -f racoon.conf" and the connection status page of the Draytek I can tell the tunnel is UP, but ping and traceroute requests to several hosts

Hi all, As long as I can remember reading various articles/docs, they all say that telnet is not secure because all traffic is in clear text. Well, out of boredom, I try to sniff username and password from a telnet session. The command I use: tcpdump tcp port 23 -vvv -w test.txt Then I read the result: strings test.txt |`D |fD |fD 38400,38400 Red Hat Enterprise Linux ESD Ologin: D 5eE

Hallo Leute :) Ich bin sehr neu in der Linux Branche und sto?e zu anfang direkt an meine grenzen. Wine startet alle meine Windows Programme einwandfrei.. ausser das spiel was ich in meiner freizeit spiele wenn ich mal nicht rausgehe und mal langeweile habe. Das spielt nennt sich Dragonica. Ich benutze Ubuntu 9. Der Patcher startet erfolgroch. nachdem ich das spiel starte.. ?ffnet sich dieses

I am just beginning to use LLVM, and find that 'getting started' is the steep part of the learning curve. I am using MingW and msys, which I have not fully grokked yet. Anyway, actually building the libraries from source is turning out to be difficult. I want to work with LLVM as described in the except from the LLVM FAQ below. I am using C++, so the FFI is a non-issue. Can someone

Hey all, Chronic will parse a date range in console: Chronic.parse(1/1/2011 - 1/1/2012, :guess => false) => 2012-01-01 12:00:00 -0500..2012-01-01 12:00:01 -0500 However, when I use logger to check if it''s parsing in application, it is not: logger.info "The value of history date is #{history_date}" => The value of history date is 1/1/2011 - 1/1/2012

Hi all, Using the Chronic.parse method, I see some weird behavior. Perhaps someone can set me straight or confirm that it is indeed weird. Note that the date changes to one day earlier in the last example below. Since the date and time are uniquely specified using the hh:mm:ss notation -- though in the future -- I would expect the same result as when I specify the time as in

Hi, I'm having difficulty with getting a table to show with multiple rows and columns. Below is the commands that I've typed in and errors that I am getting. Thank you. Laura Table trying to enter: Diet: Binger-yes: Binger-No: Total: None 24 134 158 Healthy 9 52 61 Unhealthy 23 72 95 Dangerous 12 15 27 >

Hey all, I am getting this error: NoMethodError (undefined method `gsub!'' for 2012-01-22 17:00:00 -0500..2012-01-23 00:00:00 -0500:Chronic::Span): in this code: date_range = Chronic.parse(the_date, :guess => false) reports.sum_distance_by_date(date_range).each do |d| u[:m] << d end def

Otras variantes con y sin paquetes adicionales... > sapply(split(datIn$Gain, as.factor(datIn$Diet)), mean) d1 d2 d3 280 278 312 > by(datIn$Gain, datIn$Diet, mean) datIn$Diet: d1 [1] 280 -------------------------------------------------------------- datIn$Diet: d2 [1] 278 -------------------------------------------------------------- datIn$Diet: d3 [1] 312 > > library(dplyr) >

Me gusta la respuesta uqe has dado, pero si por ejemplo, alguno de los datos tiene datos faltantes, entonces devuelve NA. He probado con: sapply(split(datos$uno, as.factor(datos$dos)), mean(na.rm=TRUE)) pero da fallo. ¿Cómo se podría hacer para que devolviera además la media obviando los NA y que contara el numero de NA por categoria? > Date: Wed, 28 Oct 2015 00:13:45 +0100 > From: cof

Estimados Cuando existia epicalc, había una manera muy fácil de determinar la media de una variable (en esta caso Gain) por grupos, en este caso (Diet). ?Como se puede hacer ahora? Diet Gain 1 d1 270 2 d1 300 3 d1 280 4 d1 280 5 d1 270 6 d2 290 7 d2 250 8 d2 280 9 d2 290 10 d2 280 11 d3 290 12 d3 340 13 d3 330 14 d3 300 15 d3 300

Dear all, This question may be too basic quesition for this list, but if someone has time to answer I will be happy. I have tried to find out, but haven't found a consice answer. As an example I use "Pinheiro, J. C. & Bates, D. M. 2000. Mixed-effects models in S and S-PLUS. Springer, New York." page 225, where rats are fed by 3 different diets over time, which body mass has

Hello This is Elaine. I am using package lattice to generate boxplots. Using Richard's code, the display was almost perfect except the outlier shape. Based on the following code, the outliers are vertical lines. However, I want the outliers to be empty circles. Please kindly help how to modify the code to change the outlier shapes. Thank you. code package (lattice) dataN <-

Hi, In the examples from the ReShape package there is a simple example of using melt followed by cast that produces a smallish amount of output about the chicks database. Here's the code: library(reshape) names(ChickWeight) <- tolower(names(ChickWeight)) chick_m <- melt(ChickWeight, id=2:4, na.rm=TRUE) DietResults <- cast(chick_m, diet + chick ~ time) DietResults My challenge

All I want to do is find the objects that were created today under the ''created_on'' column. I''ve tried many ways, here is one example using the chronic gem. @products = Product.find_all_by_created_on(Chronic.parse(''today'')) I must be missing something right in front of me .... Thanks for any help.

Hi all , I have a dataframe (Hypertension) with following headers :- > Hypertension ID Hypertension(before drug A) Hypertension(On drug A) On drug B? Healthy diet? 1 160 90 True True 2 190

Hello I ran the code below but it said: no object "'panel.xyplot.intermediate.hh'" Please kindly advise how to modify the code. thank you. (It works with panel.bwplot.intermediate.hh) Elaine code library(HH) # data input dataN <-read.csv("H:/R_data/Mig_bird_586.csv",header=T, row.names=1) dim(dataN) dataN[1,] str(dataN) diet.code <-

Hello I want to draw a xyplot. Its dots will have three colors: red for meat, green for vegetable, and blue for both. I used the code below but could not make the dot in the same group show the same color. Please kindly advise how to modify it. Thank you. code library (lattice) diet.code <- c("Herbivore", "Omnivore", "Carnivore") Diet.colors <-

according to the documentation of the cast function in the reshape function, I would expect this bit of code from the examples to calculate marginal means over only the 'diet' variable. #Chick weight example names(ChickWeight) <- tolower(names(ChickWeight)) chick_m <- melt(ChickWeight, id=2:4, na.rm=TRUE) cast(chick_m, diet + chick ~ time, mean, margins="diet") But,