similar to: $FIG FUTURE INCOME GENERATOR$

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Hi all, Small problem in generating the line charts. Question: Legend for the first graph is coming wrong., for second graph correctly. Please fix the legend postion at the down of graph. Plesae give me the solution. Thank you Devarayalu Orange1 <- structure(list(REFID = c(7, 7, 7, 7, 7, 7, 7, 7, 8, 8, 8, 8, 8, 8, 8, 8, 9, 9, 9, 9), ARM = c(1, 1, 1, 1, 2, 2, 2, 2, 1, 1, 1, 1, 2, 2, 2,

Hi all, Can anybody debug the following programme, as I am getting some Junk graphs in the pdf. Please find the attached raw data file. Thank you Regards Rayalu library(ggplot2) setwd("D:\\General Check list") library(RODBC) conn <- odbcConnectExcel ("Book1.xls") Orange1 <- sqlFetch (conn, "Sheet3") odbcClose(conn) rm(conn) #CDAI Change

Hi All, I want small modification in apperance of legend. I want seperate legend for each graph representing the lines present in that graph only (not all the lines in all graphs) . Can you please help? Thank you Regards Devarayalu Orange1 <- structure(list(REFID = c(7, 7, 7, 7, 7, 7, 7, 7, 8, 8, 8, 8, 8, 8, 8, 8, 9, 9, 9, 9), ARM = c(1, 1, 1, 1, 2, 2, 2, 2, 1, 1, 1, 1, 2, 2, 2, 2, 1, 1, 2,

Hi all, Error is coming as "error in data.frame(...., check.names = FALSE): arguments has differents counts of rows: 0, 18" for the following code. Can you please help? Thank you Devarayalu library(ggplot2) setwd("D:\\General Check list") library(RODBC) conn <- odbcConnectExcel ("Book1.xls") Orange1 <- sqlFetch (conn, "Sheet2") odbcClose(conn)

Suppose I have "Orange1" data like this. TIME1 RESPONSE RESPSTAT RESPUT REFID ARM SUBARM 0 299.5 Mean 8-item scale 68 0 0 0 287 Median 8-item scale 68 0 0 0 303.9 Mean 8-item scale 68 1 0 0 286 Median 8-item scale 68 1 0 0 295 Mean 8-item scale 85 0 0 12 254 Mean 8-item scale 85 0 0 0 287 Mean 8-item scale 85 1 0 12 216 Mean

Hi Marco, As far i can see here. Are all your ADDC servers set to the same source NTP ( preffered a stratum 1 or 2 ) server. ( and not pool ntp sources ) Because below i see stratum 4 and stratum 3 servers and a timeout on one server. When i look at this. > C:\Users\gaio>w32tm /query /peers > N. peer: 1

In our network we found some client with clock differences. Some machine have effectively some troubles, eg have NO 'Windows Time' service defined, probably some glitches happened when moving from our old NT-like domain. Anyway, catching for that, we have found some other strangeness. Windows time service run: C:\Users\gaio>sc query w32time NOME_SERVIZIO: w32time TIPO

Hi All, Can you please help me, why this code in not generating line chart? library(ggplot2) par(mfrow=c(1,3)) #qplot(TIME1, BASCHGA, data=Orange1, geom= c("point", "line"), colour= ACTTRT) unique(Orange1$REFID) -> refid for (i in refid) { Orange2 <- Orange1[i == Orange1$REFID, ] pdf('PGA.pdf') qplot(TIME1, BASCHGA, data=Orange2, geom= c("line"),

Hi, I successfully created 3 screens with the following: fig.mat<-c(0,.5,.5,.5,1,1,0,0,.5,1,.5,1) fig.mat<-matrix(fig.mat,nrow=3) fig.mat split.screen(fig.mat) I can plot three different plots on those 3 screens, but when I try the following: (Trying to create three graphs with a common x-axis but different y-axis on screen 1) screen(1) par(oma=c(3,3,0,0)) par(fig=c(0,1,0,0.33))

Any idea why I can no longer plot two graphs on the same graphics device using the par(fig=) parameter? A simpler par(mfrow=c(1,2)) does work, showing the two plots side-by-side, but I would like the first to be larger. This simple example fails: x<-c(1,1,NA,2,2,NA,3,3) y<-c(2,4,NA,3,5,NA,1,4) par(fig=c(0,2/3,0,1)) plot(x,y) par(fig=c(2/3,1,0,1)) qqnorm(x) When plotted, the last

Martin, I have an objection in principle to anything that has the side-effect of clobbering something in the global environment, even something as innocuous looking as "old.par". I certainly object to putting something like that into a public library, however clever and useful the code might be. It just is not safe. As a quick way round this I suggest the following (R only) solution:

I followed Bill Venables's suggestion and tried to make a multiplot figure with fig (using R .62). > x<-rnorm(100) > y<-rnorm(100) > x11() > par(fig=c(0,2/3,0,1)) > plot(x,y) > par(fig=c(2/3,1,0,1)) > qqnorm(x) > postscript(file="twoplot.ps") > par(fig=c(0,2/3,0,1)) > plot(x,y) > par(fig=c(2/3,1,0,1)) > qqnorm(x) However

hello all, I want to draw a figure with multiple plot on the same page using the par(fig=value) parameter but > par(fig = c(0, 50, 60, 95)/100, adj = 5/10) > eboulis(iris.acp) > par(fig = c(45, 100, 60, 95)/100, mgp = c(3, 1/2, 0)) > boites(iris.acp) draw the graphics on 2 different pages. what am I doing wrong ? thanks for your help. Mathieu [using R 0.65 under Linux Redhat

Hi all, I am new in R tool. I would like to plot two dataset in in fig. Here is what I did for both a and b data sets jpeg(file="a.jpeg") dat<-read.table('a', header=F, sep=',') dim(dat) y<-dat[,1] y<-y[!is.na(y)] plot(y);lines(lowess(y, f=0.05), col = ("red"), lwd=5) dev.off Two questions: 1. How I can save this lowess smooth data? 2. Once I

hello R-users, I'd like to plot four graphics on the same page but with different sizes. I've tried to use : par(fig=c(0,0.5,0,0.6)) plot(fig1) par(fig=c(0.5,1,0,0.6)) plot(fig2) etc... but when a figure is plotted, it erase the previous. I've tried to pass 'new=T' to plot function but it's not possible. What can I do ? is it a bug ? I've already reported this a 2 or

many thanks to P. Dalgaard, J. Fox, J. Lemon, JE. Paradis and J. Polzehl for their quick replies. The original posting is at the end of this summary. I've not well explained myself but I don't wanted to use par(mfrow) or par(mfcol) because I wanted to plot very different graphics and this solution doesn't match my needs. E. Paradis and P. Dalgaard made me discover a new (for me!)

Hi everyone, I'm using R, Latex and Sweave for some years now, but today it confuses me alot: Running Sweave produces only figures in .pdf format, no .eps figures. The header looks like this: <<echo=TRUE, fig=TRUE, label=Fig1>>= There was no error message. Does anybody have an idea? Any changes in the Sweave-package? Or a missing driver or something like that? I recently

The following code was adapted from an example Vincent Zoonekynd gave on his web site http://zoonek2.free.fr/UNIX/48_R/03.html: n <- 1000 x <- rnorm(n) qqnorm(x) qqline(x, col="red") op <- par(fig=c(.02,.5,.5,.98), new=TRUE) hist(x, probability=T, col="light blue", xlab="", ylab="", main="", axes=F) lines(density(x),