similar to: Make R 3.0 open .RData files

Hi John (and other authors of ChoiceModelR package), I am experiencing a weird thing when using the function choicemodelr under R3.0.1. Before I updated to R3.0, I had used choicemodelr unde R2.15. It was always as fast or faster than exactly the same task in Sawtooth software. Now, I've tried to run it under R3.0.1. It seems to be doing the job. But something is slowing it down dramatically.

Hello. Until today I've been using R2.9 and since today R2.10 (on a PC). In both of them it takes about 20 sec for the prompt to appear IN R console after I start R. And every time it says: "Previous saved work space restored" - even if I have not saved any workspace or, in case of R2.10 - even though I have not used it once. In the older versions - R would start within 2-3 sec. Is

?hanks for the advice, Jeff. Will keep it in mind. But I am anal - I shy away from using letters and words that "look familiar" to me in R (such as mean, sd, T, etc.) But still, it's a good advice. On Thu, Jul 27, 2017 at 11:53 AM, Jeff Newmiller <jdnewmil at dcn.davis.ca.us> wrote: > I think you should be more suspicious of yourself, Dimitri. A letter T > variable can

I think you should be more suspicious of yourself, Dimitri. A letter T variable can easily arise in the problem domain when you are not thinking of logical values at all, at which point your cavalier use of T as a synonym for TRUE can suddenly become a bug. -- Sent from my phone. Please excuse my brevity. On July 27, 2017 8:18:03 AM PDT, Dimitri Liakhovitski <dimitri.liakhovitski at

Just a thought: Did you try na.rm = TRUE in case you have an object named "T" in scope? -- Bert Bert Gunter "The trouble with having an open mind is that people keep coming along and sticking things into it." -- Opus (aka Berkeley Breathed in his "Bloom County" comic strip ) On Thu, Jul 27, 2017 at 7:49 AM, Dimitri Liakhovitski <dimitri.liakhovitski at

Thank you, Bert! I do NOT have an object named "T" in scope (I checked - and besides, it would never occur to me to use this name). TRUE or T results in the same unexpected behavior: ggplot(data = md, mapping = aes(x = a)) + geom_bar(na.rm = TRUE) On Thu, Jul 27, 2017 at 10:57 AM, Bert Gunter <bgunter.4567 at gmail.com> wrote: > Just a thought: > > Did you try

I have just installed R 12. I have Windows 7, 64-bit verison. I currently have IE as my default browser. The internet connection is very good. Whenever I try to run a help command (?lm, for example), I get this error: Error in shell.exec(url) : access to 'http://127.0.0.1:20271/library/stats/html/lm.html' denied I first got this message when Google Chrome was my default browser. For some

Dear R'ers, I am wondering what is the smallest geographicterritorial unit available for formatting in Canada. Provinces? I know that in the US it is the county so that I can color US counties any way I want, for example: ### Example for coloring US counties ### Creating an ARTIFICIAL criterion for coloring US counties: library(maps) allcounties<-data.frame(county=map('county',

To clarify: my question is not about "who could I exclude NAs from being counted" - I know how to do that. My question is: Why na.rm = T is not working for geom_bar in this case? On Thu, Jul 27, 2017 at 8:24 AM, Dimitri Liakhovitski < dimitri.liakhovitski at gmail.com> wrote: > Hello! > > I am trying to understand how ggplot2's geom_bar treats NAs. > The help file

I suspect this is by design. Questions about "why" should probably cc the contributed package maintainer(s). -- Sent from my phone. Please excuse my brevity. On July 27, 2017 7:49:47 AM PDT, Dimitri Liakhovitski <dimitri.liakhovitski at gmail.com> wrote: >To clarify: my question is not about "who could I exclude NAs from >being >counted" - I know how to do

Somehow, I've managed to have my .Rdata files become `disassociated' from the R program. I am running Windows XP Pro. I have re-installed R 2.4 in an attempt to have it re-associate itself with .Rdata files, but to no avail. .Rdata files are now associated with a file compression program or alternatively with Rgui.exe. .Rdata files are represented by the blue R, but double-clicking on

I added a new data file, NLSY.RData, to a package that uses LazyData: Yes It passed R CRAN check and R CMD install worked w/o significant complaints. * installing to library 'C:/R/R-2.15.2/library' * installing *source* package 'heplots' ... ** R ** data ** moving datasets to lazyload DB ** demo ** inst ** preparing package for lazy loading Warning: package 'nnet' was

Somehow I have lost the correct file association for .RData files. They are now associated with a text file editor. When I right click on any .RData file and try to change the association, R is not listed as a choice of program. I browse to c:\Program Files\R\rw2001\bin\Rgui.exe and select that file to open .RData, but Windows does not then place Rgui.exe in the list of programs to use. I can

Hello! I am using function "curve" to create a line graph. I was wondering, if it's possible to "turn off" the default tick marks and introduce those tick marks in specific locations. For example, currently in my X axis tick marks are (automatically) at 10, 11, 12, 13 but I want them to be in 5 specific locations, like 9.89, 10.34, etc. Any hint would be greatly

Dear R-ers! I have x as a variable in a data frame x. x<-data.frame(x=c("aa.bb","cc.dd.ee")) x$x<-as.character(x$x) x I am sorry for such a simple question - but how can I replace all periods in x$x with spaces? sub('.', ' ', x$x) - removes all letters to the left of each period... Thanks a lot for your advice! -- Dimitri Liakhovitski Ninah.com

Dear R'rs, is there a function that checks if a given vector contains a certain value. E.g., x<-c(1,2,3,4). How can I get a TRUE or FALSE for whether x contains a 2? -- Dimitri Liakhovitski Ninah.com Dimitri.Liakhovitski at ninah.com

Hello everyone! I have a list X with 3 elements, each of which is a data frame, for example: a<-data.frame(a=1,b=2,c=3) b<-data.frame(a=c(4,7),b=c(5,8),c=c(6,9)) c<-data.frame(a=c(10,13,16),b=c(11,14,17),c=c(12,15,18)) X<-list() X[[1]]<-a X[[2]]<-b X[[3]]<-c (X) How can I most effectively transform X into a data frame with columns a, b, and c? I would love to find a generic

I am not sure if this question has been asked before - but is there a procedure in R (in lm or glm?) that is equivalent to ENTER and REMOVE regression commands in SPSS? Thanks a lot! -- Dimitri Liakhovitski Ninah.com Dimitri.Liakhovitski at ninah.com

Hello, My target features some very-high-latency instructions that access an on-chip network (we'll call them FXLV). In one important kernel (snippet below), register allocation needs to spill values resulting from FXLV. The spiller is unaware of FXLV's latency, and thus naively inserts those spills immediately after the FXLV, incurring huge and unnecessary data stalls. FXLV r10,

Dear R-ers, I have a data frame data with predictors x1 through x5 and the response variable y. I am running a simple regression: reg<-lm(y~x1, data=data) I would like to loop through all predictors. Something like: predictors<-c("x1","x2",... "x10) for(i in predictors){ reg<-lm(y~i) etc. } But it's not working. I am getting an error: Error in