similar to: Creating Subgroups in Puppet Dashboard

Hello, I'm using the rmeta package to perform a meta analysis using summary statistics rather than raw data, and would like to analyze the effects in three different subgroups of my data. Furthermore, I'd like to plot this on one forest plot, with corresponding summary weighted averages of the effects displayed beneath each subgroup. I am able to generate the subgroup analyses by simply

Dear list, I have a data frame with one column (group) and want to add a second column (sub) with a serial number that says to which subgroup a cell belongs. A subgroup contains the consecutive rows of the same group. The number of a subgroup is based on its position in the table. The first subgroup of A's and B's should have nr A1 and B1, the second nr A2 and B2, etc.. I hope the

Dear R-users, I want to multiple impute missing scores, but only for a few subgroups in my data (variable 'subgroups': only impute for subgroups 2 and 3). Does anyone knows how to do this in MICE? This is my script for the multiple imputation: imp <- mice(data, m=20, predictorMatrix=pred, post=post, method=c("", "", "", "",

Hi, I have data that looks like this: ASA1 ASA2 C1_C2 C M 9.0225 S S 2.4315 M C 3.4894 M S 4.5282 C M 1.3183 C S 1.3735 S C 1.0488 S M 7.948 M C 4.5827 I need to plot Boxplots for a given ASA1 (either C,S, or M) with respect to C1_C2. However, instead of one boxplot I want to plot

# Dear all, # how to replace values in x by means in subgroups created in ... # replace only these values where y=0 in continous sequence # replace by mean calculated locally for each subgroup created by # continous sequence of 0,0,0 in parallel y vector, i.e. # where there is continous sequence of 0 in data frame vector y # but we do not replace values in x[i], if y[i]!=0 # we do not want

Hi folks, I have a dataframe df.vars with the follwing structure: var1 var2 var3 group Group is a factor. Now I want to standardize the vars 1-3 (actually - there are many more) by class, so I define z.mean.sd <- function(data){ return.values <- (data - mean(data)) / (sd(data)) return(return.values) } now I can call for each var z.var1 <- by(df.vars$var1, group,

Dear Members of the R-Help, While using a R function - 'aggregate' that you developed, I become to have a question. In that function, > aggregate(x, by, FUN, ..., simplify = TRUE) I was wondering about what type of FUN I should write if I want to get "the most frequent value of the subgroup" as a summary statistics of the subgroups. I will appreciate if I can get

Dear R-ers, In my question there are no statistics involved - it's all about data manipulation in R. I am trying to write a code that should replace what's currently being done in SAS and SPSS. Or, at least, I am trying to show to my colleagues R is not much worse than SAS/SPSS for the task at hand. I've written a code that works but it's too slow. Probably because it's

Hello. I know how to make a bar plot in which a numeric y variable is plotted against some grouping variable X (say, groups A, B, C) when this grouping variable is subdivided into each of two subgroups; so the bars would be: (group A subgroup 1) beside (group A subgroup 2), then (group B subgroup 1) beside (group B subgroup 2), and so on. This is done using the beside=TRUE argument in the

I have a nice hierarchical table structure like this: divisions has_many groups groups belongs_to division has_many subgroups subgroups belongs_to group has_many units units belongs_to subgroup I have a report which is based on units, but i want to be able to filter the units by which subgroup, or which group, or which division. I also want to sort them by division.name,then group.name,

Dear R-ers, I have a large data frame (several thousands of rows and about 2.5 thousand columns). One variable ("group") is a grouping variable with over 30 levels. And I have a lot of NAs. For each variable, I need to divide each value by variable mean - by subgroup. I have the code but it's way too slow - takes me about 1.5 hours. Below is a data example and my code that is too

Hi, Is there is any way in ruby on rails where we show all my groups there subgroups with check boxes in tree structure way? e.g group A | ----Group A.1 | ----Group A.2 | ---------Group A.2.1 All with check boxes and subgroup opens when click on root ? -- Posted via

Hi, I have a data.frame with many variables for which I am performing the mean by subgroup, for a pair of variables at a time, where one of them for each pair defines the subgroup. The subgroups in the x$cm1 are 0, 1 and 2. x ph1 cm1 0.2345 2 1.2222 1 2.0033 0 0.0000 2 1.0033 1 0.2345 0 1.2222 2 2.0033 0 0.0000 1 1.0033 2 > meanbygroup <- as.vector(with(x, by(x$ph1, x$cm1, mean)))

With this mail I would like to make a proposal to add additional informations to the core and plugin metadata files. Currently these tags are already handled in the ccs configuration system. Ccs automatically adds this informations to the core/plugin option set, but I think that it would make more sense to add this to the official files, to allow similar features in other configuration

On Fri 2015-06-12 01:52:54 -0400, Mark D. Baushke wrote: > I have communicated with Allen Roginsky on this topic and I have been given permission to post his response. > > In this message below, the 'vendor' was Darren Tucker's generated prime > that used a generator value of 5. > > -- Mark > > From: "Roginsky, Allen" <allen.roginsky at

Re:_: how to replace values in x by means in subgroups created in ...(not loops) Thanks, below some code and reply: #_-_-_-_-_-_-_-_-_-_-_-_-_-_-_-_-_# #------------------------------------------------------- # my slow function with loops: # replace_x_by_locallyMean_x_4_0s_in_y.f(x,y) #-------------------------------------------------------

On Wed 2015-05-27 05:23:41 -0400, Hubert Kario wrote: > On Tuesday 26 May 2015 15:10:01 Daniel Kahn Gillmor wrote: >> On Tue 2015-05-26 14:02:07 -0400, Hubert Kario wrote: >> > OEIS A014233 >> >> Hm, this is a sequence, but not an algorithm. It looks to me like it is >> not exhaustive, just a list of those integers which are known to have >> the stated

Dear users of metafor, I am working on a meta-analysis using the metafor package. I have a excel csv database that I am working with. I am interested in pooling the effect measures for a particular subgroup (European women) in this csv database. I am conducting both sub-group and meta-regression. In subgroup-analyses, I have stratified the database to create a separate csv file just for European

I have the following formula for a linear model: z <- lm(y~x + factor(a) + factor(b), data=NT2010) where a (groups) and b (Sub-groups) are categorical variables (factors), x is a continuous covariate, and y the response variable. Since b is nested within a, the formula can also be written as: z <- lm(y~x + factor(a) + factor(a)/factor(b), data=NT2010) and the same output is achieved

On Wed, May 27, 2015 at 05:08:25PM -0400, Daniel Kahn Gillmor wrote: > On Tue 2015-05-26 15:39:49 -0400, Mark D. Baushke wrote: > > Hi Folks, > > > > The generator value of 5 does not lead to a q-ordered subgroup which > > is needed to pass tests in > > > > http://csrc.nist.gov/publications/nistpubs/800-56A/SP800-56A_Revision1_Mar08-2007.pdf > > I