similar to: [RHSA-2000:052-02] Zope update

--------------------------------------------------------------------- Red Hat, Inc. Security Advisory Synopsis: Zope update Advisory ID: RHSA-2000:052-04 Issue date: 2000-08-11 Updated on: 2000-08-18 Product: Red Hat Powertools Keywords: Zope Cross references: N/A

--------------------------------------------------------------------- Red Hat, Inc. Security Advisory Synopsis: Zope update Advisory ID: RHSA-2000:038-01 Issue date: 2000-06-22 Updated on: 2000-06-22 Product: Red Hat Powertools Keywords: Zope Cross references: N/A

--------------------------------------------------------------------- Red Hat, Inc. Red Hat Security Advisory Synopsis: New Zope packages are available Advisory ID: RHSA-2001:115-05 Issue date: 2001-10-02 Updated on: 2001-10-09 Product: Red Hat Powertools Keywords: Cross references: Obsoletes: RHSA-2001-065

-----BEGIN PGP SIGNED MESSAGE----- Hash: SHA1 ______________________________________________________________________________ Caldera Systems, Inc. Security Advisory Subject: local ROOT exploit in BRU Advisory number: CSSA-2000-018.0 Issue date: 2000 June, 14 Cross reference: ______________________________________________________________________________ 1. Problem Description

Are you using liveice with -@ 2 option? You can see liveice's options by running it with the -h switch. I hope it helps you. --- Luis Gallardo. Caracas - Venezuela. Cédric Mallet wrote: > > I have a very weird problem between Liveice and Zope. > > I start LiveIce with a script shell that works well. Since I want to run > it under a Zope page I made a Zope "external

I have a very weird problem between Liveice and Zope. I start LiveIce with a script shell that works well. Since I want to run it under a Zope page I made a Zope "external method" to run the script through a Python module. When I call the method, the script is called by a function in the python module, and runs, but LiveIce does not work (seems like it does not even start). The weird

Hi everyone, I've got a dataframe with columns of different types. A certain number of columns in the dataframe hold the results of a series of Likert-type items. I've got a function that will print a simple table of frequencies and I want to apply that function to those columns of the dataframe only. What's the best approach? -Tim -- Tim Wilson | Visit Sibley online: |

-----BEGIN PGP SIGNED MESSAGE----- Hash: SHA1 ________________________________________________________________________ Linux-Mandrake Security Update Advisory ________________________________________________________________________ Package name: Zope Date: July 28th, 2000 Advisory ID: MDKSA-2000:026 Affected versions: 7.1

Hi everyone, I want to use the Fisher r-to-z transformation as part of a hypothesis test of r. I can't find an R function that can do that. Am I missing it? -Tim -- Tim Wilson | Visit Sibley online: | Check out: Henry Sibley HS | http://www.isd197.org | http://www.zope.com W. St. Paul, MN | | http://slashdot.org wilson at visi.com | <dtml-var

Hi everyone, I've got a dataframe called 'faculty'. I want to do a weighted mean on the column called 'Q8' weighted by the contents of column 'CETP'. In addition, I need to operate on the result of splitting 'faculty' according to the contents of a column 'FACULTY'. For example > lapply(split(faculty$Q8, faculty$FACULTY), mean) $"1" [1]

Hi everyone, I wonder if there's a patient soul out there who has a minute to look at the following. I've got a set of summary statistics I need to perform many times. Naturally, I've looked at writing a function to automate the process as much as possible. (These are the data I mentioned recently in my question about weighted means.) I'm having trouble figuring out the proper

Hi everyone, I've got a problem with an analysis of variance where it appears that my independent variable is being treated as an integer when it should be nominal. The data are being loaded from an SPSS file and the independent variable 'YearColl' corresponds (surprisingly enough) to a student's year in college. :-) The integers 1-4 are used in the dataset for this purpose. My

Hi everyone, I've downloaded the lmtest package, but I'm having trouble building it. Here's the output: copland:/home/wilson/tmp# R CMD INSTALL -l /usr/lib/R/library lmtest_0.9-0.tar.gz * Installing *source* package 'lmtest' ... ** libs g77 -fPIC -g -O2 -c pan.f -o pan.o gcc -shared -o lmtest.so pan.o -L/usr/lib/gcc-lib/i386-linux/2.95.4 -lreadline -ldl -lncurses

Hi everyone, I'm having trouble figuring out how to split a dataframe more than once. Let's say I have a dataframe d with a certain column called splitcol composed of four possible ordinal values. The same dataframe has two other columns, col1 and col2, that have one of two possible values each. I'd like to split d$splitcol based on col1 and col2 so I can report frequencies of the

try ?power.prop.test > -----Messaggio originale----- > Da: Tim Wilson [mailto:wilson at visi.com] > Inviato: sabato 6 luglio 2002 6.05 > A: R-help > Oggetto: [R] one-sample binomial test > > > Hi everyone, > > Here's how I solved a problem for my stats class. I'm pretty sure I > understand what's going on, but I wonder if there's a more >

Hi everyone, Here's a question about extracting data from a dataframe: Let's say I've got a dataframe with two vectors, TEST and GENDER. GENDER contains a 1 for males and 2 for females. I want to separate the results of TEST by GENDER so I can compare their means. What's the most efficient way to do this with R? -Tim -- Tim Wilson | Visit Sibley online: | Check out:

Hi everyone, I'm taking a course in statistics as part of my doctoral program in education at the U. of Minnesota, USA. I found R via Rpy, a python module that makes it possible to use R from python scripts. The instructor refers to SPSS a lot and that seems to be the standard stats tool around here. But being more of a Unix guy and not intimidated by programming, I'd like to see if I

Hello everyone, Thanks to all who offered suggestions after my initial query to the list. I've been busy trying to absorb the docs as fast as possible, but this little thing has me stumped for the moment. I'm creating a random sample of 100 item and saving it to a vector named 'iq'. I'd like to create a second vector (iq_prime, say) by adding 20 to each element of the

Hello everyone, Thanks to all who offered suggestions after my initial query to the list. I've been busy trying to absorb the docs as fast as possible, but this little thing has me stumped for the moment. I'm creating a random sample of 100 item and saving it to a vector named 'iq'. I'd like to create a second vector (iq_prime, say) by adding 20 to each element of the

--------------------------------------------------------------------- Red Hat, Inc. Red Hat Security Advisory Synopsis: New bugzilla packages are available Advisory ID: RHSA-2001:107-07 Issue date: 2001-08-30 Updated on: 2001-09-10 Product: Red Hat Powertools Keywords: Cross references: Obsoletes: