similar to: dividing a long column to many short ones by a condition

Hi, is there a way to retrieve a VM message pressing some key during the greeting playback? Our scenario is a PBX with analog trunks and no DID. There's a general mailbox and no way to assign a number to voicemail. I've seen these question before in this list, but seen no answer to it... Thanks, Renato

Hi Folks, I've been looking around and found some references of some Caller ID patches (Mantis bug#9) for X100P and TDM400 for Netherlands, Sweden and UK. It's been quite hard to understand what has finally been incorporated to the distribution (if anything) or which patches must be applied in witch snapshot of the repository. I've tried some different approaches but nothing worked

Same problem here: if call come over ISDN PRI and it is for a SIP phone that equals to strong echo situation, at the SIP end. Interestingly this doesn't happen on all calls but it does on 95% of them. Asterisk load at that moment is insignificant - 1 to 2 calls. I have tried with all possible echo cancellers in zconfig.h, with and without MMX, and with and without CFLAGS+=-march=i686 in

How can I divide a unit by an number or average a vector of units, e.g.: u1 <- unit( 3, 'npc' ) u2 <- unit( 6, 'npc' ) u1 / 2 ( u1 + u2 ) / 2 mean( unit.c(u1,u2) ) I would use that e.g. to to calculate the coordinates of the midpoint of a line. Wolfram

Hello everyone, I've a problem and dont know how to solve. This is my first posting and it would be fantastic if you could help me. I want to divide n objects in k classes and need an output with all (n+1)(n+2)/2 possibilities. For example n=4, k=3: That would be: 4 0 0 3 1 0 3 0 1 2 2 0 2 1 1 2 0 2 1 3 0 1 2 1 1 1 2 1 0 3 0 3 1 0 2 2 0 1 3

I have this problem... I am working on implimenting a school network. I have two kinds of users on my network: students and facutly. I have also two types of operating system on my network: win 98 and win XPP. Here is the rights and privilages I am thinking about giving my users Students (usage only in computer labs): - limited roaming profile (basically, deny desktop roaming profile) - give

Hai All, Can any one please help me to divide theora video into individual frames. what is the procedure for it?. I have referred theora documentation for the same issue, but didn''t get any answer...!!?? *Thanks & Regards,JIBIN THOMAS* _______________________________________________ theora mailing list theora@xiph.org http://lists.xiph.org/mailman/listinfo/theora

Hai All, Can any one please help me to divide theora video into individual frames. what is the procedure for it?. I have referred theora documentation for the same issue, but didn''t get any answer...!!?? *Thanks & Regards,JIBIN THOMAS* _______________________________________________ theora mailing list theora@xiph.org http://lists.xiph.org/mailman/listinfo/theora

Hello, I have two time series objects, 1 is yearly (population) and the other is quarterly (bankruptcy statistics). I would like to produce a quarterly time series object that consists of bankruptcy/population. Is there a pre-built function to intelligently divide these time series: br.ts = ts(data=br.df[,-1], frequency = 4, start=c(2001,1), end=c(2008,2)) distPop.ts = ts(data=distPop.df[,-1],

to whomever that was. i deleted your email but I think below does what you want. as always, there's probably some improvement that could be done. whether it's ? minor or major, i'm not sure ? also, 3 things:? ? A)there are some Inf's in the output because of division by zero but I wasn't sure how you wanted to handle that. B) it also assumes that an n=1

hey I'd like to divide my data into four seasons. for this I made a function: Jahreszeit <- function(x) { if (x<=02 || x==12) {return("Winter") }else{ if (x>=03 && x<=05) {return("Fruehling") }else{ if (x>=06 && x<=08) {return("Sommer") }else{ if (x>=09 && x<=11) {return("Herbst") }}}}} Now, I have some

Hey Guys I want to divide(numerically) all the columns of a data frame by different numbers. Here is what I am doing but getting a weird error. The values in each column are not getting divided by the corresponding value in the denominator vector instead by the alternative values. I am sure I am messing up something. Appreciate your help -Abhi head(counts) WT_CON WT_RB MU_CON

Hello all. I am not 100% familiar with the Linux advanced routing capbalieties yet, so I thought , after reading source code, documentation and more that I might be better off asking the experts on this list. I am not using this ina production environment, but at home, as a test case. First of all, here is the network topology. Internal LAN <--> Switch <--> [NAT/FIREWALL/INTERNAL LAN

Hello R community, I have two questions about using R. The first is about dividing each element of a list with another similar sized list. So, if the first list has two elements and so does the second, then the result should also be a list with two elements. For example, the inputs are: list(matrix(1:6,ncol=2),matrix(1:6,ncol=2))->l1 l2<-list(1:3,2) I want to get a list, l3 with the

This will handle all the columns; it assumes the ones you want to start with are in column 2 through the end: > library(dplyr) > df1 <- read.table(text = "ID A B + 1 1 2 + 1 0 3 + 2 5 NA + 2 1 3 + 3 1 4 + 4 NA NA + 4 0 1 + 4

Hi I have two data frames as shown below (second one is obtained by aggregating rows of similar IDs in df1.). They both have similar number of columns but rows of df2 are lesser than rows of df1. df1: ID A B 1 1 2 1 0 3 2 5 NA 2 1 3 3 1 4 4 NA NA 4

Hi, I have two dataframes one with 144 rows and 160 columns (SDF1) and one with 12 rows and 160 columns (SDF2). Now I'm trying to divide rows 1:12 with SDF2, rows 13:24 with SDF2, rows 25:36 with SDF 2, . In S-Plus the following code works fine: DFS = SDF1[1:144,1:60] / as.vector(SDF2[1:12,1:160]) but in R when I try to implement the formula I get the following error: "/

[I originally sent this mail to Martin and Richard, but then realised it's of wider interest, so I'm resending it to the list with Martin's reply attached (with his consent)] I was talking to Richard about trying to use shortened dividing keys in the B-trees. Shorter keys are better because you can then fit more in each block, so you need fewer B-tree levels for the same data.

Hi, I have a numeric pixel image which I would like to divide into factors for analysis in Spatstat. I have found that I can use cut.im() function to divide the range of pixel values into a series of equal length intervals (e.g. if my pixels values range from 0 to 60, cut.im(X.im,breaks=2) will produce two factors one containing pixel values 0-30 and one containing pixel values of 30 - 60, or

Hi R-users, I am trying to divide a vector (say X) into equal frequency bins. If one uses the hist() function, then a histogram is plotted, but with bins of equal widths, and not with bins having the same number of data points. I have then tried the histogram() function as follows: histogram(X, nint=10, breaks=NULL, equal.widths=F) This works as I want. However, I can't extract which