similar to: I don't understand the 'order' function

Hi, I'm trying to use pipes in R. By now, I could launch the linux command "wc" (to count words from a text), but I don't know how to capture the results, say in a vector of chars... Here is the R code I'm trying: :> f <- pipe("wc", open="w") :> writeLines(c("uno dos tres", "cuatro cinco", "seis"), f) :> close(f)

I read a table as follows: > F1 <- read.table("Rtext3.txt") > F1 Price Floor Area Rooms Age Cent.heat a 52.00 111 830 5 6.2 no b 54.75 128 710 5 7.5 no c 57.50 101 1000 5 4.2 no d 57.50 131 690 6 8.8 no e 59.75 93 900 5 1.9 yes As it is seen, the rows have a name. However I don't know how to access a

I'm trying to figure out about factors, however the on-line documentation is rather sparse. I guess, factors are intended for grouping arrays members into categories, which R names "Levels". And so we have: * state <- c("tas", "sa", "qld", "nsw", "nsw", "nt", "wa", "wa",

When I was studying the function cut I found this example: > x <- rep(0:8, tx0) > x [1] 0 0 0 0 0 0 0 0 0 1 1 1 1 2 2 2 2 2 2 3 3 3 3 3 4 4 4 5 5 5 5 5 5 5 5 5 5 6 [39] 6 6 6 6 7 7 7 8 8 8 8 8 > cut(x, b = 8) [1] (-0.008,0.994] (-0.008,0.994] (-0.008,0.994] (-0.008,0.994] (-0.008,0.994] [6] (-0.008,0.994] (-0.008,0.994] (-0.008,0.994] (-0.008,0.994] (0.994,2] [11] (0.994,2]

I have a data frame whose first colum contains the names of the variables and whose second colum contains the values to assign to them: : kkk <- data.frame(vars=c("var1", "var2", "var3"), vals=c(10, 20, 30), stringsAsFactors=F) If I do : assign(kkk$vars[1], kkk$vals[1]) it works : var1 [1] 10 However, if I try with mapply

I'm studying lists and I came to an example where > L $name [1] "Fred" $wife [1] "Mary" $no.children [1] 4 $child.ages [1] 4 7 9 then following the instructions to extend the list with a new component, I executed: > L[5] <-list(NewName="something") and the new list I got was: > L $name [1] "Fred" $wife [1] "Mary"

I have an ordered "set" of numbers, represented by a vector, say > X <- c(10:13, 17,18) > X [1] 10 11 12 13 17 18 then I have a "sub-set" of X, say > Y <- c(11,12,17,18) Is there a simple way in R to have a logical vector (parallel to X) indicating what elements of X are in Y, i.e., > Inclusion [1] FALSE TRUE TRUE FALSE TRUE TRUE I'm

Is there any way to issue operating system commands and geting back the results, in R? I mean, for instance, in Linux, to execute from R the 'ls' command and getting back a list of files in the current directory, or, equivalently, in Windows/DOS, the 'dir' command? I'm not interested in the 'ls' or 'dir' commands it is just an example. Do you have any

I'm trying to read a data file that contains characters from the Spanish language: > Station <- read.fwf("LosDatos.txt",widths=c(7,7,25,8,8,5),header=FALSE, + skip=3,n=separ[1]-4) Then the R interpreter issues the following message: Error en substring(x, first, last) : invalid multibyte string at '<d1>A, S.' Calls: read.fwf ->

I'm trying to produce a series of powers of a number as follows: |> 0.05^0:5 [1] 1 2 3 4 5 This is not the result I expected. I guess some kind of coercion happened, since, |> class(0.05^0:5) [1] "integer" Could anyone explain me what is happening here? Thanks, -Sergio.

I learnt that functions can be handled as objects, the same way the variables are. So, the following is perfectly valid: > f = function(a, b) { + print(a) + print(b) + } > > f1 = function(foo) { + foo(1,2) + } > > f1(f) [1] 1 [1] 2 > I also know that operators are functions, so, I can call: > '+'(1,2) [1] 3 > However, when I want to pass the

I wonder if there exists some kind of inverse of the "names" primitive in R. Let me explain what do I mean: If I create a list: -> li <- list(a=1, b=2, c=3, d=4) then I can have: -> names(li) [1] "a" "b" "c" "d" which is, I guess, some kind of vector, since -> typeof(names(li)) [1] "character" however, I haven't

I'm trying to write a Rscript program capable of reading several tables from the standard input. The problem is that the tables aren't in files because they are coming from another process that is generating them. From the R-console the following works pretty well: |> f <- stdin() |> t <- read.table(f) |> t2 <- read.table(f) |> t uno dos 01 3 4

Because I didn't find in R any functions similar to the function 'reduce' from Python, I'm writing a function "freduce" as follows: freduce <- function(f, vec, ValIni=NULL, StopIn=NULL) { # f: is any function that takes two arguments of the same type # vec: is a vector of n values accepted by 'f' # # Initially f starts with ValIni, if it's given

I thought the curve function was a very flexible way to draw functions. So I could plot funtions like the following: # I created a function to produce functions, for instance: fp <- function(m,b) function(x) sin(x) + m*x + b # So I can produce a function like this ff <- fp(-0.08, 0.2) ff(1.5) # Is the same as executing sin(1.5) - 0.08*1.5 + 0.2 # Let's plot this

HI Elisa, You could use ?cut() vec1<-c(33,18,13,47,30,10,6,21,39,25,40,29,14,16,44,1,41,4,15,20,46,32,38,5,31,12,48,27,36,24,34,2,35,11,42,9,8,7,26,22,43,17,19,28,23,3,49,37,50,45) label1<-unlist(lapply(mapply(c,lapply(seq(0,45,5),function(x) x),lapply(seq(5,50,5),function(x) x),SIMPLIFY=FALSE),function(i) paste(i[1],"<x<=",i[2],sep="")))

I would like to know whether there is a faster way to do the below operation (updating vec1). My objective is to update the elements of a vector (vec1), where a particular element i is dependent on the previous one. I need to do this on vectors that are 1 million or longer and need to repeat that process several hundred times. The for loop works but is slow. If there is a faster way, please let

Hello R-users, I need to create a vector inserting an 1 after each value of another vector. For example: vec1<-c(2,3,4) I need to create a vector with the values 2,1,3,1,4 Does anyone know how create this vector without loops (vec1 could have 1000 elements) Thank you, Juan -.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.- r-help mailing list -- Read

This can be vectorized. Try ix <- seq_along(vec2) S_diff2 <- sapply(seq_len(N1-(N2-1)*ratio_sampling), \(j) sum((vec1[(ix-1)*ratio_sampling+j] - vec2[ix])**2)) On Sun, Jun 16, 2024 at 11:27?AM Laurent Rhelp <laurentRHelp at free.fr> wrote: > > Dear RHelp-list, > > I try to use the package comprehenr to replace a for loop by a list > comprehension. > > I

Hello R specialists, I have a base vector called vBase with 102 elements. I have another vector vec1 which elements are only part of vBase but is shorter. I transform vec1 so I get a vector with the same size as vBase and with each common element on the same indexed row. If a value is missing in vec1 then I put a Na like this: vec1 vBase Amsterdam Amsterdam Na