Displaying 20 results from an estimated 100 matches similar to: "Splitting the Elements of character vector"
2013 Apr 25
1
Linear Interpolation : Missing rates
Dear R forum
I have data.frame as
df = data.frame(rate_name = c("USD_1w", "USD_1w", "USD_1w", "USD_1w", "USD_1m", "USD_1m", "USD_1m", "USD_1m", "USD_2m", "USD_2m", "USD_2m", "USD_2m", "GBP_1w", "GBP_1w", "GBP_1w", "GBP_1w",
2013 Apr 03
4
Better way of writing R code
Dear R forum,
(Pl note this is not a finance problem)
I have two data.frames as
currency_df = data.frame(current_date = c("3/4/2013", "3/4/2013", "3/4/2013", "3/4/2013"), issue_date = c("27/11/2012", "9/12/2012", "14/01/2013", "28/02/2013"), maturity_date = c("27/04/2013", "3/5/2013",
2005 Mar 16
2
how to draw xyplot figure like figure 4.18 of MASS (4th) ?
Dear All:
Could you please tell me how I can draw figure formatted like figure 4.18 of MASS (4th) with the attached data set?
Thanks
Zhongming Yang
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2013 Apr 23
0
Fw: Error with function - USING library(plyr)
Dear R forum,
Please refer to my query regarding "Error with function". I forgot to mention that I am using "plyr" library.
Sorry for inconvenience.
Regards
Katherine
--- On Tue, 23/4/13, Katherine Gobin <katherine_gobin@yahoo.com> wrote:
From: Katherine Gobin <katherine_gobin@yahoo.com>
Subject: [R] Error with function
To: r-help@r-project.org
Date:
2013 Apr 23
0
Error with function
Dear R forum,
I have a data.frame as given below:
df = data.frame(tran = c("tran1", "tran2", "tran3", "tran4"), tenor = c("2w", "1m", "7m", "3m"))
Also, I define
libor_tenor_labels = as.character(c("o_n", "1w", "2w",
"1m", "2m", "3m", "4m",
2013 Apr 23
0
Fw: " PROBLEM SOLVED" - Error with function
Dear R forum
Please refer to my query captioned Error with function.
I had missed in bracket ")" in the return statement and hence I was getting the error. I has struggled for more than 2 hours to find out the problem and only then has posted to the forum. I sincerely apologize to all for consuming your valuable time.
Thanks for the efforts at your end.
Regards
Katherine
--- On
2012 Feb 29
2
puzzling results from logistic regression
Hi all,
As you can see from below, the result is strange...
I would imagined that the bb result should be much higher and close to 1,
any way to improve the fit?
Any other classification methods?
Thank you!
data=data.frame(y=rep(c(0, 1), times=100), x=1:200)
aa=glm(y~x, data=data, family=binomial(link="logit"))
newdata=data.frame(x=6, y=100)
bb=predict(aa, newdata=newdata,
2006 Jan 27
1
about lm restrictions...
Hello all R-users
_question 1_
I need to make a statistical model and respective ANOVA table
but I get distinct results for
the T-test (in summary(lm.object) function) and
the F-test (in anova(lm.object) )
shouldn't this two approach give me the same result, i.e
to indicate the same significants terms in both tests???????
obs.
The system has two restrictions:
1) sum( x_i ) = 1
2) sum(
2004 Oct 21
3
1.0-test51
http://dovecot.org/test/
This release is built with autoconf 2.59 and libtool 1.9. We'll see how
it works out :) The required changes were done by Matthias Andree.
- The last fix for connection hanging made IDLE use 100% CPU
- We don't use Maildir/.INBOX/ directory anymore, indexes are stored
in Maildir-root
- Don't crash with FETCH BODY[n.MIME]
- Changed %p (protocol)
2009 Aug 13
4
lm coefficients output confusing
Hi all,
I have an issue with the lm() function regarding the listing of the
coefficients. My data are below, showing a list of hours (HR) relating to
the time spent resting (R) by an individual animal. Simply i want to run a
lm() to run in an anova() to see if there is a significant difference in
resting between hours.
HR R
1 2 0.6666667
2 2 0.4666667
3 2 0.8000000
4 2
2013 Jan 12
2
Interpreting coefficients in linear models with interaction terms
Hi,
I am trying to interpret the coefficients in the model: RateOfMotorPlay ~
TestNumber + Sex + TestNumber * Sex where there are thee different tests and
Sex is (obviously) binary. My results are: Residuals:
Min 1Q Median 3Q Max
-86.90 -26.28 -7.68 22.52 123.74
Coefficients:
Estimate Std. Error t value Pr(>|t|)
(Intercept) 29.430 6.248
2010 Feb 04
2
help needed using t.test with factors
I am trying to use t.test on the following data:
date type INTERVAL nCASES MTF SDF MTO SDO
nFST MF nOBS MO MB BIASCV BIASEV ME MAE
RMSE CRCF
2001-06-15 avn GE1.00 4385 0.246 0.300 1.502
0.556 1367 1.373 4385 1.502 1.471 0.285 0.164
-1.256 1.266 1.399 0.056
2001-06-15 avn
2012 Feb 03
1
ordering of factor levels in regression changes result
I was surprised to find that just changing the base level of a factor variable changed the number of significant coefficients in the solution.
I was surprised at this and want to know how I should choose the order of the factors, if the order affects the result.
Here is the small example. It is taken from 'The R Book', Crawley p. 365.
The data is at
2011 Aug 29
1
MuMIn Problem getting adjusted Confidence intervals
Hello R users
I'm using MuMIn but for some reason I'm not getting the adjusted confidence
interval and uncoditional SE whe I use model.avg().
I took into consideration the steps provided by Grueber et al (2011)
Multimodel inference in ecology and evolution: challenges and solutions in
JEB.
I created a global model to see if malaria prevalence (binomial
distribution) is related to any
2017 Jun 24
3
Help please
Hello,
I need some help on a regression I am running please. I am running a multiple regression in R and I am getting weird outputs and would like your help in resolving it.
This is the code I run:
Reg = lm (Final$Y.t.-Final$Y.t.1. ~ Final$ Y.t.1. + Final$Cor + Final$Gov+ Final$Inv+ Final$TrOp + Final$Pop+ Final$Sch , data = Final)
summary(Reg)
And the output I get is pasted below. As
2010 Sep 08
4
coxph and ordinal variables?
Dear R-help members,
Apologies - I am posting on behalf of a colleague, who is a little puzzled
as STATA and R seem to be yielding different survival estimates for the same
dataset when treating a variable as ordinal. Ordered() is used to represent
an ordinal variable) I understand that R's coxph (by default) uses the Efron
approximation, whereas STATA uses (by default) the Breslow. but we
2010 Aug 26
2
Speeding up transpose
I've looked at how to speed up the transpose function in R
(ie, t(X)).
The existing code does the work with loops like the following:
for (i = 0; i < len; i++)
REAL(r)[i] = REAL(a)[(i / ncol) + (i % ncol) * nrow];
It seems a bit optimistic to expect a compiler to produce good code
from this. I've re-written these loops as follows:
for (i = 0, j = 0; i<len; i +=
2010 Jun 19
3
[Bug 1784] New: ssh-keygen fails when filename of key file contains multiple slashes
https://bugzilla.mindrot.org/show_bug.cgi?id=1784
Summary: ssh-keygen fails when filename of key file contains
multiple slashes
Product: Portable OpenSSH
Version: 5.2p1
Platform: All
OS/Version: Linux
Status: NEW
Severity: normal
Priority: P2
Component: ssh-keygen
AssignedTo:
2017 Jun 26
0
Help please
Hi Rabby,
Before you run your regression, try this:
is.factor(Final$Cor)
If this returns TRUE, then this variable is a factor and it will be
treated as a number of levels rather than a set of numeric values.
This usually happens when a text file is read in and there is at least
one value that cannot be converted to numeric. So if you are doing
something like this:
2001 Nov 05
1
Problem to transfer Splus functions
Hello
I would like to transfer some Splus functions in R.
But I have a problem first about this assignation in Splus :
xnom <- deparse(substitute(x))
I am a bad programmer : I don't understand the R help
How to modify these functions ?
Thank you very much for your help
Here are the four functions and a data test