Displaying 20 results from an estimated 300 matches similar to: "Can package plyr also calculate the mode?"
2012 Aug 31
2
Conditional merging in R & if then statement
1)I am wandering how the following SQL statement can be written in R language
w/o using sqldf:
create table detail2 as
select a.*
from detail a,
pdetail b
where a.TDATE=b.TDATE
and (a.STIM >= b.STIM and a.STIM <=b.MAXTIM)
2) when try if then in R it only applies to the 1st row & not to whole
dataset like in SAS. How do you get round that?
in SAS:
data summary;
set all1;
2013 Apr 05
2
How to perform a grouped shapiro wilk test on dataframe
Hello,
I was wandering if it is possible to perform on a dataframe called 'all' a
shapiro wilk normality test for COUNTS by variable Group
ACTIVITY? Could it be done using plyer? I saw an eg that applies to an
array but not to a dataframe:
lapply(split(dataset1$Height,dataset1$Group),shapiro.test)
Any thoughts would be much appreciated.
My dataframe is in shape:
dat ACTIVIT
2013 May 23
3
Removing rows w/ smaller value from data frame
Hello,
I have a column called max_date in my data frame and I only want to keep the
bigger values for the same activity. How can I do that?
data frame:
activity max_dt
A 2013-03-05
B 2013-03-28
A 2013-03-28
C 2013-03-28
B 2013-03-01
Thank you for your help
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2008 Apr 03
1
prettyR 25% quartile, 75% quartile
I am using the describe function in prettyR. I would like to add the
25% 75% quartiles to the summary table
how do I do this
I have tried
describe(x.f, num.desc=c("mean", "median", "sd", "min", "max",
"skewness", "quantile(x.f, na.rm=T, probs=seq(0.25, 0.75))",
"valid.n"))
help
--
Let's not spend our time
2012 Nov 30
5
subset data frame by variable with missing value
Hello,
I have a variable in a data frame that contains NA values. I just want to
subset so that I get the obs where that variable is missing.
In SAS I would do:
data missing;
set test;
if myvalue=' ';
run;
How can I perform this simple task in R?
Thanks in advance for your help.
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2008 Jun 19
1
PrettyR (describe)
#is there a way to get NA in the table of descriptive statistics instead of
the function stopping Thank you in advance
#data
x.f <- structure(list(Site = structure(c(9L, 9L, 9L, 9L, 9L, 9L, 9L,
9L, 9L, 9L, 9L, 9L, 9L, 9L, 9L, 9L, 9L, 9L, 9L, 9L, 9L, 9L, 9L,
9L, 9L, 9L, 9L), .Label = c("BC", "HC", "RM119", "RM148", "RM179",
"RM185",
2012 Oct 10
3
How to replicate SAS by group processing in R
Hello,
I am trying to re-code all my programs from SAS into R.
In SAS I use the following code:
proc sort data=upper;
by tdate stock_symbol expire strike;
run;
data upper1;
set upper;
by tdate stock_symbol expire strike;
if first.expire then output;
rename strike=astrike;
run;
on the following data set:
tdate stock_symbol expiration strike
9/11/2012 C 9/16/2012
2012 Sep 18
4
Conditional operations in R
Hello,
I am a newbie to R coming from SAS background. I am trying to program the
following:
I have a monthly data frame with 2 variables:
client pct_total
A 15%
B 10%
C 10%
D 9%
E 8%
F 6%
G 4%
I need to come up w/ a monthly list of clients that make 50% or just above
it every month so I can pass them to the rest of the program.
2013 Sep 10
1
Error: BUG: Worker sent reply with id 393, expected 394
hi dovecot:
when i login 100 users with imap protocol ,Someusers appeared a BUG in maillog like :
Sep 10 09:05:22 auth(default): Error: BUG: Worker sent reply with id 393, expected 394
Sep 10 09:05:22 auth(default): Error: worker-server(q82 at t.com,10.12.80.3): Aborted: Worker is buggy
Sep 10 09:05:22 auth(default): Error: BUG: Worker sent reply with id 31, expected 32
Sep 10 09:05:22
2012 Oct 19
4
Creating a new by variable in a dataframe
Hello,
I have a dataframe w/ 3 variables of interest: transaction,date(tdate) &
time(event_tim).
How could I create a 4th variable (last_trans) that would flag the last
transaction of the day for each day?
In SAS I use:
proc sort data=all6;
by tdate event_tim;
run;
/*Create last transaction flag per day*/
data all6;
set all6;
by tdate event_tim;
last_trans=last.tdate;
Thanks
2012 Nov 13
1
Using lubridate to increment date by business days only
Hello,
I know how to increment a date by calendar date:
ticker$ldate <- ticker$tdate + days(5)
How do I increment it by business days only so that week-ends are not
counted?
So for example friday november 2 + 5days becomes friday november 9 & not
wednesday nov 7.
Thanks for your help.
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2012 Aug 24
1
if then in R versus SAS
I am new to R and I have the following SAS statements:
if otype='M' and ocond='1' and entry='a.Prop' then MOC=1;
else MOC=0;
How would I translate that into R code?
Thanks in advance
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2012 Sep 13
1
Paasing values to sqlQuery like SAS macro
Hello,
We lost our SAS licence & I am busy transfering my old SAS programs to R
environment. I am very new to R. In 1 program I was creating SAS macro
vars & passing them into a SQL query to run against the server. There are 3
variables firm, begindt, enddt. # of values for each varies month to month.
Is there anyway I could do the same thing in R & pass the afore mentioned
values
2013 Apr 12
2
Stat question: How to deal w/ negative outliers?
Hello all,
I have a question: I am using the interquantile method to spot outliers &
it gives me values of say 234 & -120 or for the higher & lower benchmarks.
I don't have any issues w/ the higher end. However I don't have any
negative values. My lowest possible value is 0. Should I consider 0 as an
outlier?
Thanks ahead for your thoughts
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2012 Sep 13
3
Cannot install package xlsx
I get following error message:
trying URL
'http://cran.stat.ucla.edu/bin/windows/contrib/2.15/xlsx_0.4.2.zip'
Content type 'application/zip' length 365611 bytes (357 Kb)
opened URL
downloaded 357 Kb
Error in read.dcf(file.path(pkgname, "DESCRIPTION"), c("Package", "Type")) :
cannot open the connection
In addition: Warning messages:
1: In
2010 Nov 17
3
Fatal Error R
Hello.
First, I'm thankful about your wonderful project.
However, I have serious worries about the reliability of R. I found
the next bug which I consider important because in my job everytime We
work with datanames like next. Please see below:
b=data.frame(matrix(1:9,ncol=3))
names(b)=c("q99","r88","s77")
>b
q99 r88 s77
1 1 4 7
2 2 5 8
3
2017 Jun 12
2
plotting gamm results in lattice
Dear all,?
I hope that you can help me on this. I have been struggling to figure this out but I haven't found any solution.
I am running a generalised mixed effect model, gamm4, for an ecology project. Below is the code for the model:
model<-gamm4(LIFE.OE_spring~s(Q95, by=super.end.group)+Year+Hms_Rsctned+Hms_Poaching+X.broadleaved_woodland? ? ? ? ? ? ?+X.urban.suburban+X.CapWks,
2010 Aug 01
3
remove extreme values or winsorize – loop - dataframe
Hi everyone!
#I need a loop or a function that creates a X2 variable
that is X1 without the extreme values (or X1 winsorized)
by industry and year.
#My reproducible example:
firm<-sort(rep(1:1000,10),decreasing=F)
year<-rep(1998:2007,1000)
industry<-rep(c(rep(1,10),rep(2,10),rep(3,10),rep(4,10),rep(5,10),rep(6,10),rep(7,10),rep(8,10),rep(9,10),
rep(10,10)),1000)
X1<-rnorm(10000)
2008 Jul 23
4
Using PrettyR to produce LaTeX output
Hello everyone. I am new to R, so please bear with me. I am trying to find
an easy way to export descriptive statistics and other information about my
data frame to a LaTeX format.
I have found the describe function in PrettyR to be very helpful in
producing results in the exact format I'm looking for. However, the value
of the describe function is a LIST (rather than a data frame) which I
2017 Jun 12
0
plotting gamm results in lattice
Hi Maria
If you have problems just start with a small model with predictions and then plot with xyplot
the same applies to xyplot
Try
library(gamm4)
spring <- dget(file = "G:/1/example.txt")
str(spring)
'data.frame': 11744 obs. of 11 variables:
$ WATERBODY_ID : Factor w/ 1994 levels "GB102021072830",..: 1 1 2 2 2 3 3 3 4 4 ...
$ SITE_ID