similar to: how to control the environment of a formula

Dear List I am looking for the recommended way to create a formula inside a function with an empty environment. I tried several versions (see below), and one of them seemed to work, but I dont understand why there is a difference between .GlobalEnv and the environment inside a function. I would be greatful for any reference or explanation or advice. Thanks Thomas #+BEGIN_SRC R :results output

Thank you for your suggestion. I do know how to work around the issue. I usually build a fresh environment as a child of base-environment and then insurt the weights there. I was just trying to provide an example of the issue. emptyenv() can not be used, as it is needed for the eval (errors out even if weights are not used with "could not find function list"). For some applications

I was surprised just now to find out that `topenv(emptyenv())` equals ? `.GlobalEnv`, not `emptyenv()`. From my understanding of the description of `topenv`, it should walk up the chain of enclosing environments (as if by calling `e = parent.env(e)` repeatedly; in fact, that is almost exactly its implementation in envir.c) until it hits a top level. However, `emptyenv()` has no enclosing

On Tue, Oct 13, 2015 at 4:43 PM, Hadley Wickham <h.wickham at gmail.com> wrote: > Seems easy enough to write yourself: > > where <- function(x, env = parent.frame()) { > if (identical(env, emptyenv())) > return(NULL) > if (exists(x, envir = env, inherits = FALSE)) > return(env) > where(x, parent.env(env)) > } > > sample2 <-

Dear R-users, Is there a way to test whether a particular environment e is equal to emtyenv(), or for that sake whether two environments e1 and e2 are equal? I tried a couple of ways to compare environments, but neither seem to work: > e1 <- new.env() > e2 <- new.env() > e1 == e2 Error in e1 == e2 : comparison (1) is possible only for atomic and list types > all.equal(e1,

Hi, this relates to the question "How to set a former environment?" asked yesterday. What is the best way to to return a function with a minimal environment from a function? Here is a dummy example: foo <- function(huge) { scale <- mean(huge) function(x) { scale * x } } fcn <- foo(1:10e5) The problem with this approach is that the environment of 'fcn' does not

I wish I had started with "I am disappointed that lm() doesn't continue its search for weights into the calling environment" or "the fact that lm() looks only in the formula environment and data frame for weights doesn't seem consistent with how other values are treated." But I did not. So I do apologize for both that and for negative tone on my part. Simplified

On 10/08/2020 1:42 p.m., John Mount wrote: > I wish I had started with "I am disappointed that lm() doesn't continue its search for weights into the calling environment" or "the fact that lm() looks only in the formula environment and data frame for weights doesn't seem consistent with how other values are treated." Normally searching is done automatically by

Dear R-Devel subscriber, first, let me express my thank to the R-Core team for the new release! I appreciate their efforts and time spent to enhance R. In accordance with the 'NEWS' file (see excerpt of it below), [... o Changed the environment tree to be rooted in an empty environment, available as emptyenv(). baseenv() has been modified to return an environment with emptyenv() as

Dear R-Devel subscriber, first, let me express my thank to the R-Core team for the new release! I appreciate their efforts and time spent to enhance R. In accordance with the 'NEWS' file (see excerpt of it below), [... o Changed the environment tree to be rooted in an empty environment, available as emptyenv(). baseenv() has been modified to return an environment with emptyenv() as

I've just committed some changes to R-devel which affect environments. Specifically: - using NULL as an environment is now deprecated: use baseenv() instead. (baseenv() is already available in R 2.2.0, where it returns NULL. For most purposes it retains the same meaning in R-devel.) If you do use NULL, it will be converted to baseenv(), and a warning printed. For example: > f

the following is a trivialized version of some functional code i tried to use in r: (funcs = lapply(1:5, function(i) function() i)) # a list of no-parameter functions, each with its own closure environment, # each supposed to return the corresponding index when applied to no arguments sapply(funcs, function(func) func()) # supposed to return c(1,2,3,4,5) there is absolutely nothing unusual in

Is it possible to create an environment that has no parent (or an empty parent)? I would have thought e <- new.env(parent=NULL) would work, but it acts as though the parent is the base namespace: > get("close", envir = e) function (con, ...) UseMethod("close") <environment: namespace:base> I can use inherits = FALSE in this case: > get("close",

I would like to assign an value to an element of a list contained in an environment. The list will contain vectors and matrices. Here's a simple example: # create toy environment testEnv = new.env(parent = emptyenv()) # create list that will be in the environment, then assign() it x = list(a=1,b=2) assign("xList",x,testEnv) # create new element, to be inserted into xList c = 5:7

My understanding is that R will not make copies of lists if there is only one reference to the object. However, I've encountered a case where R does make copies, even though (I think) there should be only one reference to the object. I hope that someone could shed some light on why this is happening. I'll start with a simple example. Below, x is a list with one element, and changing that

For learning purposes mainly I attempted to implement hashes/maps/dictionaries (Python lingua) as S4 classes, see the coding below. I came across some rough S4 edges, but in the end it worked (for one dictionary). When testing ones sees that the dictionaries D1 and D2 share their environments D1 at hash and D2 at hash, though I thought a new and empty environment would be generated each time

Hello R-philes: I have the following function that gets the output of mget() and converts it to a data frame to return. What I am finding is that the dimensions are wrong. Basically, I get: bridesmaid wed u see m gt lt like love X.0 dress pagetrack one go X3 get 1 56 35 27 30 24 20 20 23 28 17 25 16 16 28 15 26 Instead, I want something like: [1] bridesmaid

Hi list, This looks similar to the problem reported here https://stat.ethz.ch/pipermail/r-devel/2006-April/037199.html by Henrik Bengtsson a long time ago. It is very sporadic and non-reproducible. Henrik, do you remember if your code was using reg.finalizer()? I tend to suspect it but I'm not sure. I've been hunting this bug for months but today, and we the help of other Bioconductor

Dear R gurus, I need to know the length of a variable (let's call that X) that is mentioned in a formula. So obviously I look for the environment from which the formula is called and then I have two options: - using eval(parse(text='length(X)'), envir=environment(formula) ) - using length(get('X'), envir=environment(formula) ) a bit of

>>>>> Konrad Rudolph >>>>> on Sat, 23 Mar 2019 14:26:40 +0000 writes: >>>>> Konrad Rudolph >>>>> on Sat, 23 Mar 2019 14:26:40 +0000 writes: > I was surprised just now to find out that `topenv(emptyenv())` equals > ? `.GlobalEnv`, not `emptyenv()`. From my understanding of the > description of `topenv`, it