similar to: R 3.0.0 memory use

Dear all, When I coerce a vector into a multi dimensional array, I would like R to start filling the array along the last dimension, then the 2nd last etc. Let's jump straight into an example. x <- 1 : 24 y <- array(dim=c(2,2,6)) I would like to have: y[1,1,1] = 1 y[1,1,2] = 2 ... y[1,1,6] = 6 y[1,2,1] = 7 y[1,2,2] = 8 ... y[2,1,1] = 13 ... y[2,2,1] = 19 if I do y<- array(x,

Dear list, I have a list of three matrices : i = list(matrix(1:4,2,2), matrix(3:6,2,2), matrix(9:12,2,2)) I would like to sum the matrices, as follows : [,1] [,2] [1,] 13 19 [2,] 16 22 I used this code : k <- i[[1]] for (j in (2:length(i))) { k <- k + i[[j]]} But, is it possible to sum without a loop ? Thanks in advance, Carlos [[alternative HTML version deleted]]

Buenas tardes a todo el mundo, El motivo de que me dirija al foro es que no sé cómo añadir unas determinadas filas en un data table de una forma eficaz y según el identificador de sujeto. Además, quisiera hacerlo sin tener que recurrir a ningún paquete de R adicional del tipo plyr, dplyr, etc. (no sé si esto es posible). EJEMPLO: require(data.table) DT <- data.table( id =

Hi, all. Given an array, I'd like to add elements whose location vectors are permutations of one another. For example, in a 3-dimensional array, I'd add the elements in positions (1,2,3), (1,3,2), (2,1,3), (2,3,1), (3,1,2) and (3,2,1); those in positions (1,2,4), (1,4,2), (2,1,4), (2,4,1), (4,1,2), and (4,2,1); and so on. Elements with repeated positions -- (1,1,2) or (1,4,4), for

-----BEGIN PGP SIGNED MESSAGE----- Hash: SHA1 Hi list, please forgive cross posting, but I cannot specify the problem enough to say whether list it fits perfectly, so I'll ask on both. I have some machines based with following specs (see at the end of the email). They run CentOS 5.4 x86_64 with the latest patches applied, Xen-enabled and should host one or more domUs. I put the domUs'

-----BEGIN PGP SIGNED MESSAGE----- Hash: SHA1 Hi list, please forgive cross posting, but I cannot specify the problem enough to say whether list it fits perfectly, so I'll ask on both. I have some machines based with following specs (see at the end of the email). They run CentOS 5.4 x86_64 with the latest patches applied, Xen-enabled and should host one or more domUs. I put the domUs'

Dear expeRts, How can I get ... (1) different y-axis scales for each row (2) while having the same y-axis scales for different columns? I coulnd't manage to do this with relation="free" [which gives (1) but not (2)]. I also tried relation="sliced", but it did not give the same y-axis scales within each row (see the fourth row). Further, it "separates" the

Hi everyone, I'm looking for a way to 'explode' a matrix like this: > matrix(1:4,2,2) [,1] [,2] [1,] 1 3 [2,] 2 4 into a matrix like this: > matrix(c(1,1,2,2,1,1,2,2,3,3,4,4,3,3,4,4),4,4) [,1] [,2] [,3] [,4] [1,] 1 1 3 3 [2,] 1 1 3 3 [3,] 2 2 4 4 [4,] 2 2 4 4 My current kludge is this:

Ehlo all, I've been working on a migration of about 240K users from one server with qmail, courier imap, maildrop and ldap to postfix, dovecot, lda +sieve. Before the migration the server and the storage were always on high load. Before migration: Storage IOPs = 4600 Read average = ?2800 ?Write average = 1800 Storage CPU (Raid5) Crl0 = 50% Crl1 = 50% Server Load = 120 %user = 35

Hi, > match(c(3,4), c(3,2,1)) [1] 1 NA The above result has 'NA' in. Is there a way to make 'match' does not produce any 'NA's? Regards, Peng

Dear mailing list, may some one be kind to help me solve following problem. I am trying to write a code that will combine two tables "x" and "y". The first columns of both tables are unique identification for the rows. The first column of table "X" is a sub set of the first column of "Y". I need to find the matching rows in both tables by looking on their

Hi all, it seems that there is problem with function "adaptIntegrate", when the integration limits is infinity. Please see the code below. The second integration does not seem to work. Can anyone familiar with this give some help? Thank you with much. Hanna library(mnormt) library(cubature) ff <- function(x, rho){ mu <- rep(0,3) Sigma

Sorry for starting another topic, this is actually a reply to Segher's post on Sun Oct 22 on the 'mdct question' topic. I wasn't subscribed properly and so I didn't get email confirmation and thus can't add to that thread. So Segher, if the equation is indeed what you say it is, then replacing mdct_backward with this version should work, but it doesn't. Am I applying

Dear R-helpers, for the purpose of plotting a dataframe, i am trying to sort a dataframe by one column, for example tester <- data.frame(one=c(3,2,1), two=c(2,3,1)) #> tester # one two #1 3 2 #2 2 3 #3 1 1 # I want to sort "tester" by column "one", so that i get a dataframe # that looks like: #one two #1 1 #2 3 #3 2 I know of 'sort' but

Dear All I'm trying to sort a matrix using function order, Some thing really odd: e.g. abc<-cbind(c(1,6,2),c(2,5,3),c(3,2,1))## matrix I want to sort if I do abc[ order(abc[,3]), increasing = TRUE] the result is correct [,1] [,2] [,3] [1,] 2 3 1 [2,] 6 5 2 [3,] 1 2 3 But if I want to sort in decresing order: abc[ order(abc[,3]), decreasing = TRUE] the

Dear List, why does this not work? df <- data.frame(var1 = c(3,2,1), var2 = c(6,5,4), var3 = c(9,8,7), fac = c('A', 'A', 'B')) tapply(cbind(df$var1, df$var2, df$var3), df$fac, mean) Thank you, Stefan

Hi, I wanted to read in a table that had hyphens in the header / column names. When I read it in however, it replaces the hyphens with a dot. Which parameter in the read.table function do I need to set to change this behaviour? Example code: jm <- matrix(1:4,2,2) rownames(jm) <- c('a','b') colnames(jm) <- c('a-1','a-2')

I'd like to have a three dimensional array of matrices. I thought I could construct a five dimensional array to have the three dimensional array of matrices. However, not all of the matrices in the array have the same dimensions, which seems to mean I can't use a five dimensional array. What I'd like is this: A = matrix(1:4,2,2) B = matrix(1:25,5,5) C = matrix(1,3,3) D =

Hi. Can anyone suggest a simple way to obtain in R a list of vector coordinates of the following form? The code below is Mathematica. In[5]:= Flatten[Table[{i,j,k},{i,3},{j,4},{k,5}], 2] Out[5]= {{1,1,1},{1,1,2},{1,1,3},{1,1,4},{1,1,5},{1,2,1},{1,2,2},{1,2,3},{1 ,2,4},{1,2, 5},{1,3,1},{1,3,2},{1,3,3},{1,3,4},{1,3,5},{1,4,1},{1,4,2},{1,4,3}, {1,4,

Hi I am posting in the topic related to the "non-numeric argument to binary operator" as I got similar problem while running the netcdf code. I have attached the file with this post. It is a climate data from NOAA site. The code follows as: library(survival) library(RNetCDF) library(ncdf) setwd("c:/projects/netcdfcsfiles") Conn42 =