similar to: Make a matrix from two lists

Displaying 20 results from an estimated 7000 matches similar to: "Make a matrix from two lists"

2018 Mar 22
2
how to add a child to a child in XML
Big thanks. newXMLNode works great. Wonder why it is not included in the documentation. There is newXMLDoc and newXMLNamespace, but no mention of newXMLNode. Stephen From: Ben Tupper [mailto:btupper at bigelow.org] Sent: Wednesday, March 21, 2018 6:18 PM To: Bond, Stephen Cc: r-help Subject: Re: [R] how to add a child to a child in XML Hi, XML doesn't use the `$` to access child nodes.
2018 Mar 22
0
how to add a child to a child in XML
Hi, It's a reasonable question. The answer is that it actually is included, but there are many instances across packages where multiple functions are documented on a single help page. The following brings up such a page... (for XML_3.98-1.9) > library(XML) > ?newXMLNode You can see the same on line... https://www.rdocumentation.org/packages/XML/versions/3.98-1.9/topics/newXMLDoc
2018 Mar 22
1
how to add a child to a child in XML
Just to clarify and hopefully catch the attention of the maintainer: The newXMLNode function is not mentioned in: https://cran.r-project.org/web/packages/XML/XML.pdf which supposedly describes all functions in the package. Stephen From: Ben Tupper [mailto:btupper at bigelow.org] Sent: Thursday, March 22, 2018 10:40 AM To: Bond, Stephen Cc: r-help Subject: Re: [R] how to add a child to a
2018 Jan 02
1
httr::content without message
Thanks to all that replied. I had just looked through the httr code and sure enough for a .csv mime time it calls readr::read_csv(). The httr::content docs suggest not using automatic parsing in a package, rather to determine mime type and parse yourself and Ben's suggestion also works if I do: junk <- readr::read_csv(r1$content, col_types = cols()) Perfect. Using httr rather than
2018 Mar 21
2
how to add a child to a child in XML
I am trying to add a child to a child using XML package in R. the following fails library(XML) node1 <- c("val1","val2","val3") names(node1) <- c("att1","att2","att3") root <- xmlNode("root", attrs=node1) node2 <- LETTERS[1:3] names(node2) <- paste("name",1:3,sep="") root <-
2016 Apr 30
3
Could not find function "pointsToRaster"
Dear All, I have a script that draws longitude and latitude of lightning occurrence. This script was running fine before. But when I changed my system and do a fresh install on another laptop, this error persist. source("script") Error in eval(expr, envir, enclos) : could not find function "pointsToRaster" I have tried to see if there is any other package I need to install
2017 Sep 06
1
rgdal error when trying to import raster
Indeed, Ben, but the question was something more like it is not a Dependency, just Suggested, so why the error... John: If you read the Introduction to the 'raster' package vignette, it indicates that some input formats are supported within the raster package and some rely on other packages. Clearly the attempt to read a TIFF was an example of the latter. Had you used a different input
2017 Apr 05
2
as.POSIXct character string is not in a standard unambiguous format
Hi I have lots of issues when I try to install R 3.3.3 during the "make check" step. Every time a call to as.POSIXct is done in test scripts, I got the same error message: e.g. x <- as.POSIXct("2002-02-02 02:02") Error in as.POSIXlt.character(x, tz, ...) : character string is not in a standard unambiguous format It looks to be linked to localtime but when I compiled
2017 Dec 16
0
Generating help files for a function
Hi, If you are using roxygen-style function documentation then why not use devtools::document()? Ben > On Dec 16, 2017, at 9:00 AM, Erin Hodgess <erinm.hodgess at gmail.com> wrote: > > Hello everyone! > > I'm in the process of writing a package, and I'm using the lovely "R > Package" book as a guideline. > > However, in the midst of my
2017 Dec 16
5
Generating help files for a function
Hello everyone! I'm in the process of writing a package, and I'm using the lovely "R Package" book as a guideline. However, in the midst of my work, I discovered that I had omitted a function and am now putting in it the package. Not a problem. But the problem is the help file. What is the best way to generate a help file "after the fact" like that, please? Thank
2016 Apr 30
0
Could not find function "pointsToRaster"
Hi, A terrific resource for this type of issue (and pretty much anything related to R) is http://rseek.org/ I'm sure I use it at least daily. Check out ... http://rseek.org/?q=pointsToRaster The first hit is about pointsToRaster() - it has been replaced by raster::rasterize() Cheers, Ben > On Apr 30, 2016, at 4:28 AM, Ogbos Okike <giftedlife2014 at gmail.com> wrote: > >
2017 Sep 06
2
rgdal error when trying to import raster
Dear useRs, I am trying to import a raster with the line: nlcd <- raster("/home/jpolo/NRI/nlcd_nri5000.tif") And I keep getting an error like this: "Warning message: In library(package, lib.loc = lib.loc, character.only = TRUE, logical.return = TRUE,? : ? there is no package called 'rgdal' Error in .rasterObjectFromFile(x, band = band, objecttype =
2018 Mar 21
0
how to add a child to a child in XML
Hi, XML doesn't use the `$` to access child nodes. Instead use either `[name]` to get a list of children of that name or `[[name]]` to get the just the first child of that name encountered in the genealogy. Thus for your example... > root$child1 NULL > root[['child1']] <child1 name1="A" name2="B" name3="C"/> On the other hand, you might
2017 Aug 06
1
Nested for loop
Hi Ben, That's exactly right! Except for each set it's the sample population that is 400, 800 or 300. I want to take 3 samples, each of 100, where only the population differs. I can do this separately, but I'm having trouble putting them all on the same graph. I'd like to have sample on the x axis (1-300) and estimate on the y axis. I want to show how population affects the
2018 Jan 02
0
httr::content without message
Ahoy! That's a message generated by the readr::read_table() function (or it's friends). You can suppress it a number of ways, but this should work as httr::content() will pass through arguments, like col_types = cols(), to the file reader. junk <- httr::content(r1, col_types = cols()) See more here... https://blog.rstudio.com/2016/08/05/readr-1-0-0/
2018 Mar 28
0
netCDF to GeoTIFF by layer in r
Hi Ahmed, When reading from a ncdf file you can use the 'varname', 'lvar' and 'level' arguments - see the 'Details' section in the docs https://www.rdocumentation.org/packages/raster/versions/2.6-7/topics/raster <https://www.rdocumentation.org/packages/raster/versions/2.6-7/topics/raster> We can't tell what is in the ncdf file from what you report other
2018 Jan 02
4
httr::content without message
Hi All: I am using httr to download files form a service, in this case a .csv file. When I use httr::content on the result, I get a message. Since this will be in a package. I want to suppress the message, but haven't figured out how to do so. The following should reproduce the result: myURL <-
2017 Sep 06
0
rgdal error when trying to import raster
Hi, The message "there is no package called 'rgdal'" means that you don't have rgdal installed. https://cran.r-project.org/web/packages/rgdal/index.html Also, you will get very good patial-centric help if you subscribed to r-sig-geo here https://stat.ethz.ch/mailman/listinfo/r-sig-geo Cheers, Ben > On Sep 6, 2017, at 2:52 PM, john polo <jpolo at mail.usf.edu>
2010 Nov 29
1
map() and pdf clipping
Hello, Below is a function (test.map) that permits drawing the same map using three different devices. The "pdf" device doesn't clip polygons to the plot region as I see it does by both the native device (in my case "Quartz") and the "png" device. test.map("pdf") # produces "test-map.pdf" with no clipping test.map("png") #
2013 Mar 19
1
Convert to date and time of the year
Dear R Users, I have data for more than 3 years. For each year I want to find the day corresponding to Jaunary 1 of that year. For example: > x <- c('5/5/2007','12/31/2007','1/2/2008') > #Convert to day of year (julian date) - > strptime(x,"%m/%d/%Y")$yday+1 [1] 125 365 2 I want to know how to do the same thing but with time added. But I still