similar to: summarize dataframe based on multiple cols, not their combinations

Hi Folks, I'm trying to find a way to remove all terms in a formula that contain a particular interaction. For example, in the formula below, I'd like to remove all terms that contain the b:c interaction. > attributes(terms( ~ a*b*c*d))$term.labels [1] "a" "b" "c" "d" "a:b" "a:c" [7]

I have searched help topics but don't know exactly what to search for. Need to use my_num to find any matching STREPs in my_df my_num <- c("101","102","103","104","105","107","108","112","113","114","115") ## "my_df" has 8,000 different STREPS in it. ## I have a

In trying to use as.Date(), I've come across the conversion of POSIXlt to POSIXct when a POSIXlt variable is included in a data frame: my_POSIX <- strptime(c("11-09-2006", "11-10-2006", "11-11-2006", "11-12-2006", "11-13-2006"), "%m-%d-%Y") str(my_POSIX) my_Date <- as.Date(my_POSIX) str(my_Date) data <- format(my_Date)

Dear R users, I have got the following data frame, called my_df: gender day_birth month_birth year_birth labour 1 F 22 10 2001 1 2 M 29 10 2001 2 3 M 1 11 2001 1 4 F 3 11

I am sorry if this is a faq or tutorial somewhere, but I am unable to solve this one. What I am looking for is a count of how many different categories(numbers in this case) that appears for a given factor. Example: > l <- c("Yes", "No", "Perhaps") > x <- factor( sample(l, 10, replace=T), levels=l ) > m <- c(1:5) > y <- factor( sample(m, 10,

Hello, I'm trying to extract the independent variables from a formula. The closest I've been able to come, aside from rolling my own, is the following: > a = y ~ b * x > attr(terms(formula(a)),"variables") The reason I'm doing this is that I'm building a grid of points that I use to construct a 3-d model prediction surface in rgl. If there are more than two

Hi Folks, I'm trying to extract just the backreferences from a regex. > temp = "abcd1234abcd1234" > regmatches(temp, gregexpr("(?:abcd)(1234)", temp)) [[1]] [1] "abcd1234" "abcd1234" What I would like is: [1] "1234" "1234" Note: I know I can just match 1234 here, but the actual example is complicated enough that I have to

R-Help Community How do I add a numeric class to a data .frame. For example, I have calculated the following probabilities 1 2 3 0.0011566127 0.0009267028 0.0081623324 How would I add them back into my data.frame for example My_df <- data.frame(col_1 = c('A', 'B', 'C')) such that I end up with col_1

Hello folks, I've been on a journey trying to figure out how to manage documents that are amenable to sharing and editing, but that contain dynamic content generated by R. I've come to the following solution: I use Sweave to generate labeled png & pdf figures, and I "Insert & Link" those figures as "Pictures" in a Word 2010 doc. Thus, when data or code

Hello All, I'm getting my workflow switched over to Sweave, which is very cool. However, I collaborate with folks (as many of you must as well) who use Word to Track Changes amongst a group while crafting a paper. In the simplest case, there will just be two people (one Sweave user and one Word user) editing a paper. I'm wondering, how do Sweave users go about this? I could convert a

> is.na(strptime("5/2/1992", format="%m/%d/%Y")) [1] FALSE > is.na(strptime("5/3/1992", format="%m/%d/%Y")) [1] TRUE Any idea what's going on with this? Running strptime against all dates from around 1946, only 5/3/1992 was converted as "NA". Even stranger, it still seems to have a value associated with it (even though is.na thinks

Hello all, What is your preferred method to export tables (from ftable()) to Word? Do you just export to a text file and then copy/paste? Or perhaps via HTML output? Thanks, Allie

Hi Folks, I'm trying to cut my data inside the summaryBy function. Perhaps formulas don't work that way? I'd like to avoid adding another column if possible, but if I have to, I have to. Any ideas? Thanks, Allie require(doBy) df = dataframe(a <- rnorm(100), b <-rnorm(100)) summaryBy(a ~ cut(b,c(-100,-1,1,100)), data=df) # preferred solution, but it throws an

Hi Folks, I've been bumping my head against the 4GB limit for 32-bit R. I can't go to 64-bit R due to package compatibility issues (ROBDC - possible but painful, xlsReadWrite - not possible, and others). I have a number of big dataframes whose columns all sorts of data types - factor, character, integer, etc. I run and save models that keep copies of the modeled data inside the model

Hello All, I am trying to write a function which would operate on columns of a dataframe specified in parameters passed to that function. f = function(dataf, col1 = "column1", col2 = "column2") { dataf$col1 = dataf$col2 # just as an example } The above, of course, does not work as intended. In some languages one can force evaluation of a variable, and then

Hello Folks, As some of my old code broke when an updated package changed its interface, I started thinking about reproduction of analyses. It's not good enough to save our code - we have to save the package versions those analyses used as well as the R-core. I saw a couple references to "reproduction archives" around, but nothing specific. Is there any good way to package up

Hello Folks, When I run the document below through sweave, rgui.exe/rsession.exe leaves a file handle open to the sweave-001.pdf graphic (as verified by process explorer). Pdflatex.exe then crashes (with a Permission Denied error) because the graphic file is locked. This only seems to happen when there is an error in the sweave document. When there are no errors, no file handles are left open.

Hello, I need to take a dot product of each row of a dataframe and a vector. The number of columns will be dynamic. The way I've been doing it so far is contorted. Is there a better way? dotproduct <- function(dataf, v2) { apply(t(t(as.matrix(a)) * v2),1,sum) #contorted! } df = data.frame(a=c(1,2,3),b=c(4,5,6)) vec = c(4,5) dotproduct(df, vec) thanks,

Hello All, Searched around, haven't found a decent solution. I'd like to translate a vector of numbers to a matrix (or to a list of vectors) such that the vector values would serve as indicies of the 1's in an otherwise-zero-filled matrix (or list of vectors). For example: > a = c(1,3,3,4) # perform operation [,1] [,2] [,3] [,4] [1,] 1 0 0 0 [2,] 0 0 1

>>> Did you read this? >>> https://cran.r-project.org/doc/contrib/Leisch-CreatingPackages.pdf >>> >>> Maybe it could give you some insight in how to create package. >> >> That resource is ~9 years old. There are more modern treatments available. You >> can read mine at http://r-pkgs.had.co.nz. >> >> Hadley >> Thanks both.