similar to: Copying rows in data frames

Hi everyone, I'm using the following code to go over every element of a data frame (row wise). The problem I am facing is that the outer 'x' variable is not incrementing itself, thus, only one row of values is obtained, and the program does not proceed to the next row. This is the code: while(x<=coln) { while(y<=rown) { n<-as.numeric(df[[y]][x]);

Hello :) I'm just starting out with R and would appreciate your help with a couple of problems I am running into. I have used Sys.glob to get a list of all filenames having a particular file extension (in my case, *.txt) I would now like to use this list in the following manner: I would like to use each filename from the list and open that file into a tab separated matrix and proceed. How can

HI, I'm looking for a function that does the same as deal() in MATLAB, i,e, for an array x[1 2 3] [a,b,c]=x; such that a=1, b=2, c=3 Does R have any functions similar to this? [[alternative HTML version deleted]]

Hi everyone: This may be trivial but I just have not been able to figure it out. Imagine the following dataframe: a b c d TRUE TRUE TRUE TRUE FALSE FALSE FALSE TRUE FALSE TRUE FALSE FALSE I would like to create a new dataframe, in which TRUE gets 0 but if false then add 1 to the cell to the left. So the results for the example above should be something like: a b c

Hi everyone, I am trying to use the values from every cell of the data frame in a further calculation. This is the code that I am using to catch every element of the data-frame. while (a<=10) { while (b<=10) { n<-as.numeric(df[a,b)]; ...; } } The problem is that when I print out 'n' I get the following errors : "NULL" (if printed without as.numeric), and

Hi, I am trying to create a data frame using the dimensions of another data frame that I have input. This is the code I am using: tab is the data frame that is input. c.leng<-length(tab[,1]); r.leng<-length(tab[1,]); opdf<-data.frame(ncol=c.leng, nrow=r.leng); a<-1; while(a<=c.leng) { opdf[[1]][a]<-tab[[1]][a]; a<-a+1; } This is the error message I am getting: Error in

Hi, I'm using R to do a series of calculation and I have gotten several warnings that say "NaNS produced". Whatever I could read on line gives me an idea that this warning is produced when the number is use is a negative log or otherwise mathematically problematic. I'm getting this error while using factorial() and gamma () on strictly positive numbers (always greater than zero).

Hi all, I am Sahana. I am currently working on Libtheora for windows platform and very new to it. I am getting a lot of compiling errors. Since Libtheora depends on libogg and libvorbis i have added these as well to my workspace in VC++ 6. I have a doubt regarding the x86 and x86_vc folders described in the libtheora software.Since both these folders have the same set of files which one do we

Hello, I have a column called max_date in my data frame and I only want to keep the bigger values for the same activity. How can I do that? data frame: activity max_dt A 2013-03-05 B 2013-03-28 A 2013-03-28 C 2013-03-28 B 2013-03-01 Thank you for your help -- View this message in context:

Hello R Help! I would like to make a legible boxplot of tree growth rates for each of seven tree species at each of seven different sites. It's a lot of data to put on one figure, I know. I made a beautiful, interpretable figure using color, but my target journal can't deal with color figures. I can use seven shades of grey to fill the boxes, but the figure then becomes uninterpretable -

Hello. I need to know how can R compute AIC when I study a regression model? For example, if I use these data: growth tannin 1 12 0 2 10 1 3 8 2 4 11 3 5 6 4 6 7 5 7 2 6 8 3 7 9 3 8 and I do model <- lm (growth ~ tannin) AIC(model) R responses: 38.75990 I know the following formula to compute AIC: AIC=

Hi, I am not sure I understand your question correctly. dat1<- read.table(text=" id??????????? responsed_at???????????????? number_of_connection????????????????? scores 1????????????????? 12-01-2010?????????????????????????????????? 1????????????????????????????????????????????? 2 1????????????????? 15-02-2010??????????????????????????????????

On Mon, Nov 30, 2009 at 7:22 PM, Javier Martinez <javier at jmartinez.org> wrote: > Hello, > > I'm working in adding support for 64-bit integers to my target. I'm using > LLVM to decompose the 64-bit integer operations by using 32-bit registers > wherever possible and emulating support where not. When looking at the bit > shift decomposition I saw what seems to be a

Hi all, I have multiple textboxes containing numbers. I want to add up all the numbers and show the sum. Can I select the textboxes by class and sum the content? This also has to happen realtime: when a number is changed ina textbox the sum should also change. can this be done? regards, Stijn --~--~---------~--~----~------------~-------~--~----~ You received this message because you are

I was trying to write a wrapper for number_to_currency to return currency in pounds. I used a helper class to do this. def number_to_pounds(amt) number_to_currency(amt, :unit => "£") end This works fine, but I am trying to understand why I can''t use a symbol to pass the values. I thought symbols were like pointers. (you now know I am a newbie). def

Hello, I'm working in adding support for 64-bit integers to my target. I'm using LLVM to decompose the 64-bit integer operations by using 32-bit registers wherever possible and emulating support where not. When looking at the bit shift decomposition I saw what seems to be a bug in the implementation. The affected function is ExpandShiftWithUnknownAmountBit in LegalizeIntegerTypes.cpp.

Hi Duncan, The problem is the implementation of the expansion. Perhaps an example can help illustrate better. Take the case of a 64-bit integer shifted left by say 6 bits and is decomposed using 32-bit registers. Because 6 is less than the 32 (the register size) the resulting low part should be equal to the source low part shifted left by 6 bits. The current implementation places a zero

Dear list, This may sound silly. What is the right way to change the names of a dataframe? Let's say I have this data frame (dose) with four columns with names "ID", "DOSE", "TIME" "CMT". I want to change "DOSE" to "AMT". So I did names(dose[2])<-'AMT' But nothing happened. The name of the second column is still

Hi Javier, > The problem is the implementation of the expansion. Perhaps an example > can help illustrate better. Take the case of a 64-bit integer shifted > left by say 6 bits and is decomposed using 32-bit registers. Because 6 > is less than the 32 (the register size) the resulting low part should be > equal to the source low part shifted left by 6 bits. The current >

I thought I''d pass along a few tips for getting the Intel DQ35JO motherboard to play nice with Xen: 1. The dom0 kernel won''t boot with CONFIG_PCI_MMCONFIG enabled. If you get a hang during boot after seeing this message: ACPI: PCI Root Bridge [PCI0] (0000:00) ...then MMCONFIG is your problem. Some kernels seem to support a pci=nommconfig option, but my Gentoo 2.6.21 Xen