similar to: Convert to date and time of the year

Hi , I am trying to convert the date as factor to date using "as.date" function in R. I have the date in the following format 2008-01-01 02:30 I tried to use the following command : as.Date(mydata$Date, format="%y-%m-%d ") Can somebody help me with this ? I was able to convert the format with no hour but getting difficulty with hour included. Thank you.

Hello All, I have a data with two columns. In one column it is date and in another column it is flow data. I was able to read the data as date and flow data. I used the following code: creek <- read.csv("creek.csv") library(ggplot2) creek[1:10,] colnames(creek) <- c("date","flow") creek$date <- as.Date(creek$date, "%m/%d/%Y") The link to my data

Hello, I have a big number lets say of around hundred digits. I want to subset that big number into consecutive number of 5 digits and find the product of those 5 digits. For example my first 5 digit number would be 73167. I need to check the product of the individual numbers in 73167 and so on. The sample number is as follows:

Hello R users, I am trying to use R to do the low pass filter analysis for the tidal data. I am a novice in R and so far been doing only simple stuffs on R. I found a package called signal but couldn't find the proper tutorial for the low pass filter. Could anyone point me to the proper tutorial or starting point on how to do low pass filter analysis in R ? Thank you so much. Janesh

I have created a graph with basic R plot with 2 rows and 3 columns. With the basic plot feature of R I had to write several lines of code to come up with the graph https://www.dropbox.com/s/f7d6ei6krtcrtti/hello.png I was wondering whether we can plot multiple series in each plot using ggplot as created in the above link. If anyone could give me any suggestion then I could try on ggplot. I

Hello All, I have plotted a scatter plot in ggplot2 and added a regression line and a regression equation. But the processing is very very slow. One reason might be because I have so many data pairs. Is there any way to speed up this code ? I need to create a multiple layout as well. The code I have used is as follows: setwd("C:/Users/jzd0009/Documents/R software") mydata <-

Hello All, I have a discontinuous dataset and I used spplot to plot the points. I was wondering whether it is possible to show the legend of the plot as color ramp. I saw that on continuous data. If anyone could tell me that would be great. Another thing I would like to know is how can we create the horizontal legend. By default, the legend is vertical. I was able to shift the legend inside

Dear R-users, I have a dataset as like below, and I want to subtotal the values of rice,wheat and maize by year for each fid. fid      year     rice     wheat      maize ------------------------------------------------ 1        1995      5        NA           NA 1        1995      NA        3           NA 1        1995      NA       NA           2 1        1996      4        NA           NA 1  

Hello All, I am trying to do the time series analysis in R and I want to assign a vector as a time series. The data I provided is hourly. The data is from Jan 1 2008 to Dec 31 2009. How can I assign the data such that the first year is leap year and second is not ? airtemp <- read.csv("airtemp.csv",header=T,sep="") aw <- ts(airtemp,start=2008,frequency=8784,end=2009)

Hello All, I have a data file in a text format and there are two data sets. The data set are continuous. For each data set there is a header which has the number of data rows and the name of data series. For example first data set has "6240 Terry Cove-Model". Then the data for that series follows upto 6240 rows. Then another data would start and it will have the header such as

Dear R users, I am working on a data-set with 3 species. They are apple, orange and banana. I want to annotate the facets only on the bottom panel. However, by default I am getting annotations on all the plots. I was able to get text annotation only on the desired plot. However, I am confused what I need to do for the arrows / segments. Here is my code: library(ggplot2) library(grid) tempobs

Hi I am trying to find the relationship between two variables. First I fitted a linear model between two variables and I found the following results: Residual standard error: 0.03253 on 2498 degrees of freedom Multiple R-squared: 0.5551, Adjusted R-squared: 0.5549 F-statistic: 3116 on 1 and 2498 DF, p-value: < 2.2e-16 Then I used the cor function to see the correlation between two variable

Hi, I have done the interpolation for my data and I was able to create the contours in multipanel with the help of Pascal. Now, I want to clip the contour with the shapefile. I want only the portion of contour to be displayed which falls inside the boundary of the shapefile. The data mydata.csv can be found on https://www.dropbox.com/s/khi7nv0160hi68p/mydata.csv The data for shapefile can be

I have a data set for different time intervals. The data has three comment lines before data for each time interval. For each time interval there are 500 data points. I want to change the dataset such that I have the following format: t1 t2 t3 ................ 0.00208 0.00417 0.00625 ................. a1 a2 a3 ...................

I am trying to solve an integral in R. However, I am getting an error when I am trying to solve for that integral. The equation that I am trying to solve is as follows: $$ C_m = \frac{{abs{x}}e^{2x}}{\pi^{1/2}}\int_0^t t^{-3/2}e^{-x^2/t-t}dt $$ [image: enter image description here] The code that I am using is as follows: a <- seq(from=-10, by=0.5,length=100) ## Create a function to compute

Hi there, I set up my company's back up server using rsync. And I've got a strange problem. I searched in the archives of this list, but none of them seems not giving me an idea to solve the problem. If anyone can help, it would be grateful. I'm using cron by a user (non wheel/admin) to rsync everyday during the night. The cron is set in the server to transfer the backing-up

Full_Name: John Brzustowski Version: R-devel-trunk OS: linux (problem under Windows too) Submission from: (NULL) (74.101.124.238) (This bug was discovered by Phil Taylor, Acadia University.) I'm not sure from reading the documentation whether strptime(x, "%j") is meant to be supported, but if so, there is a bug which prevents it from working on the first day of months after

Hello, I am having trouble figuring out how to convert a Day of Year integer back into a Date format. For example I have the following: date <- c('2008-01-01','2008-01-02','2008-01-03','2008-01-04','2008-01-05','2008-01-06','2008-01-07',

Hi, I have a dataframe column of the form v<-c("Fri Feb 05 20:00:01.43000 2010","Fri Feb 05 20:00:02.274000 2010","Fri Feb 05 20:00:02.274000 2010","Fri Feb 05 20:00:06.34000 2010") I need to convert this to datetime form. I did the following.. lapply(v,function(x){strptime(x, "%a %b %d %H:%M:%OS %Y")}) This gives me a list that looks like

Hi all, Is there a simple function already implemented for getting the ISO weeks of a Date object? I couldn't find one, and so wrote my own function to do it, but would appreciate a pointer to the "default" way. If a function is not yet implemented, could the code below be of interest to submit to CRAN? Best Regards, Gustaf --------------------