similar to: loop in a data.table

Hi everyone: This may be trivial but I just have not been able to figure it out. Imagine the following dataframe: a b c d TRUE TRUE TRUE TRUE FALSE FALSE FALSE TRUE FALSE TRUE FALSE FALSE I would like to create a new dataframe, in which TRUE gets 0 but if false then add 1 to the cell to the left. So the results for the example above should be something like: a b c

Hi. This is likely a trivial problem but have not found a solution. Imagine the following dataframe: Lat Lon x1 x2 x3 01 10 NA NA .1 01 11 NA .2 .3 01 12 .4 .5 .6 I want to generate another column that consist of the first value in each row from columns x1 to x3. That is NewColumn .1 .2 .4 Any input greatly appreciated, Thanks, Camilo Camilo Mora, Ph.D.

Hi everyone, Imagine that I have a data frame with four columns: data<- a b c d 0 1 1 0 1 1 1 1 1 0 0 1 I want to replace the zeros in columns a:b for NA only for the rows in which column d are zero. So a b c d NA 1 1 0 1 1 1 1 1 0 0 1 I am trying

Hi everyone, I wonder if anyone knows the reason why the outputs of the same reprojection in r and arcgis are different?. The magnitude of the change can be up to 40 km in the poles. Basically, I have a database of points equally separated by one degree over the globe. In ARCGIS, I am projecting the data in GCS-WGS-1984 and then reprojected it to Berhmann to ensure equal area

Hi everyone, I wonder if I can get your help using a custom function in apply. Imagine the following dataframe called "data": LowLim HighLim A1 A2 A3 A4 4 6 3 4 5 6 4 6 4 5 5 6 2 3 1 4 2 3 2 3 NA NA NA NA We have created a custom function (see below) that takes the values in a given row between columns A1 to A4 to see if they are outside the limits in the same

Hi everyone: Is there a function in R to calculate the confidence intervals for the predictions of a GLS(Generalized Least Square) model? The function "predict" gives confidence intervals for the predictions of other types of models (lm, glm, etc) but not gls. Any input will be much appreciated, Best, Camilo Camilo Mora, Ph.D. Department of Biology Dalhouisie University

Hello, I would like to be able to write all files produced on one day to an output directory with that date stamp, or alternatively stamp the date in the filename. So that if i run the same code the next day the files will not be overwritten. here's what i have to start with: baseDir = getwd() outputDir = paste(baseDir,"/OutputData-", Sys.Date(),sep="") and lets say i

Hello R-devel, I am currently attempting to implement an API similar to data.table wherein single bracket subsetting can accept an unquoted expression to be evaluated in the context of my object. A simple example from the data.table package looks like this: DT <- data.table(col1 = c('a', 'b', 'c'), col2 = c('x', 'y', 'z')) DT[col1 ==

Cordial saludo adjunto la base de datos y el script: eu60<- read.csv(file.choose(), header=T, sep=";", dec=".", row.names=1) eu60.pca <- PCA(eu60, quali.sup=19) eu60.data <- cbind.data.frame(eu60[,19], eu60.pca$ind$coord) eu60.ellipse <- coord.ellipse(eu60.data, bary=TRUE) plot.PCA(ellipse=eu60.ellipse, cex=0.8) El 4 de diciembre de 2013 17:35, Camilo Calle

I am starting to BDD. When specing the controller I want to test for object creation: it "deberia crear una nueva persona en post create" do Usuario.should_receive(:create).with({:nombre => "camilo", :clave => "secreta", :tipo => "administrador"}).and_return(@usuario) post ''create'', {:usuario => {:nombre =>

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Hola a todos Me gustaría saber si me pueden ayudar con lo siguiente. Realicé un Boxplot usando ggplot2 para visualizar el comportamiento de dos variables. Visualmente no se notan las diferencias porque la gráfica de la derecha (parásitos en el abdomen) llega hasta 20 en el eje y. ¿Cómo puedo hacer para que las dos gráficas muestren la misma escala en el eje Y, es decir, que las dos lleguen a 60?

Hola, ¿qué tal? Tu problema es que tienes agrupaciones de países (p.e., ASIA_MERIDIOL) con un solo respresentante. Las matrices con las que construyes las elipses son degeneradas (más bien, no existen: sospecho que tienen que ver con la covarianza... ¿de un único caso?). Elimina las agrupaciones triviales. Un saludo, Carlos J. Gil Bellosta http://www.datanalytics.com El día 4 de diciembre de

Hi there, There is some special reason to require a virConnectPtr param in virDomainRestore ? Regards, Camilo -------------- next part -------------- An HTML attachment was scrubbed... URL: <http://listman.redhat.com/archives/libvirt-users/attachments/20100609/69932c54/attachment.htm>

Estoy trabajando en dos archivos .txt con el comando setdiff. Infortunadamente se me produce un resultado que no he podido controlar a pesar de cargar el comando system("defaults write org.R-project.R force.LANG en_US.UTF-8") para normalizar el sistema UTF-8 [85]"geomorfolog\222a" [91] "habitu\216s" [121] "\352ndice" Mil

Hi, I am trying to use a CGI service (Pubchem PUG) via RCurl and am running into a problem where the data must be supplied via POST - but I don't know the keyword for the argument. The data to be sent is an XML fragment. I can do this via the command line using curl: I save the XML string to a file called query.xml and then do curl -d @query.xml

Dear R users; Ive got two questions concerning nlme library 3.1-65 (running on R 2.2.0 / Win XP Pro). The first one is related to augPred function. Ive been working with a nonlinear mixed model with no problems so far. However, when the parameters of the model are specified in terms of some other covariates, say treatment (i.e. phi1~trt1+trt2, etc) the augPred function give me the following

I'm writing a function that needs an optional variable. If the variable is given, then a subset must be made using that variable, but if the variable is not given the subset must be done using all the values for that variable (ignoring that variable). Something like this: *band <- function(file, fruit = "apple", optional=TRUE) {* *data <- read.csv(file)* *a <-

Dear list i am using Asterisk 1.2.5 with A@H . here is my problem. if i dial a number (consider 79) i have to wait around 20 seconds before my Asteisk box response. now i want to decrease this waiting time . any idea how to do that ? thanks Salaque

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