Displaying 20 results from an estimated 100 matches similar to: "Extract letters from a column"
2010 Oct 13
4
Change global env variables from within a function
Hi,
I've looked all over for a solution to this, but haven't had much look 
in specifying what I want to do with appropriate search terms.  Thus I'm 
turning to R-help.
In the process of trying to write a simple function to rename individual 
column names in a data frame, I ran into the following problem: When I 
rename the columns within my function, I can't seem to get it to
2011 Jun 28
1
lattice multiple y-scale possible?
Hi
I am attempting to use the lattice bwplot function to generate boxplots 
of numerous parameters (1-panel/parameter) by site (x-axis). The 
parameters have quite different ranges of values, so it would be best to 
have a separate y-axis range for each panel. Below is a basic example of 
what I am trying to do. As is seen, the y-axes need to be scaled 
individually to make this useful. Any
2011 May 19
1
Creating a "shifted" month (one that starts not on the first of each month but on another date)
Hello!
I have a data frame with dates. I need to create a new "month" that
starts on the 20th of each month - because I'll need to aggregate my
data later by that "shifted" month.
I wrote the code below and it works. However, I was wondering if there
is some ready-made function in some package - that makes it
easier/more elegant?
Thanks a lot!
# Example data:
2007 May 12
1
function similar to "get" that works for both an object, and elements of an object?
#Is there a single function similar to "get" that works for both an object, and elements of an object ?  
#(I want the function to be able to return objects, and/or the deeper elements of an object.)
#(i.e. elements of a dataframe and/or list)?
#e.g.
tempdf = data.frame(a=c(4,5,6) , b=c(10,11,12) )
templist= list(x=tempdf, y=c(1,2))
get('tempdf') #works as desired
2012 Aug 03
2
Recursive function calls
My apologies, I know that this is not a new problem, but I'm not sure how
to find the answer
I want to recursively loop over an object and trim trailing white space.
When I use this function on a list of data.frame I get output like this:
[1] "c(\"   many spaces   \", \"   many spaces   \")" "c(\"   many spaces
\", \"   many spaces  
2009 Dec 08
1
Printing 'k' levels of factors 'n' times each, but 'n' is unequal for all levels ?
Dear List,
I need to print out each of 'k' levels of a factor 'n' times each, where 
'n' is the number of elements belonging to each factor.
I know that this can normally be done using the gl() command,
but in my case, each level 'k' has an unequal number of elements.
Example with code is as below:
vc<-read.table("P:\\Transit\\CORRECT 
2016 Jan 14
2
JDataFrame API
Hi Folks,
If you need to send data from Java to R you may consider using the
JDataFrame API -- which is used to convert data into JSON which then
can be converted into a data frame in R.
Here's the project page:
https://coherentlogic.com/middleware-development/jdataframe/
and here's a partial example which demonstrates what the API looks like:
String result = new JDataFrameBuilder()
 
2016 Jan 15
2
JDataFrame API
Hi Simon,
Thanks for your feedback. -- this is an observation that I wasn't
considering when I wrote this mainly because I am, in fact, working
with rather small data sets. BTW: There is code there, it's under the
bitbucket link -- here's the direct link if you'd still like to look
at it:
https://bitbucket.org/CoherentLogic/jdataframe
Re "for practical purposes is
2011 Jan 14
4
test
Hi, i have that table
Thesis	Day	A	B	C
1	0	83.43	90.15	22.97
1	0	85.50	94.97	16.62
1	0	83.36	95.38	20.70
1	0	84.47	92.16	23.58
1	0	83.98	95.33	19.39
1	0	82.86	93.78	24.55
1	0	83.39	92.67	19.56
1	0	85.17	95.24	17.95
1	0	81.62	93.32	28.49
1	0	82.99	92.85	19.73
1	0	81.11	95.67	27.20
1	0	83.39	94.69	16.51
1	0	79.56	89.87	30.39
1	0	80.54	93.32	21.76
1	0	82.11	92.58	22.17
1	14	85.65	94.00	19.19
1	14
2007 Jul 15
1
Looping through a series of (csv) files
Dear Colleagues.
This should be a very common operation and I believe there should be a nice
way in R to handle it.  I couldn't find it in the manual or by searching
online. I am wondering if I could ask for some help in this community.
I have 48 csv files; each stores the data for a specific month. The 48
corresponding months are consecutively from January, 2001 to December, 2004.
I name
2013 Aug 21
3
data import: strange experience
Dear List:
I had some strange experience in importing data.  I wonder if anyone of you
had the same problem before and would greatly appreciate your suggestion in
advance.
The original data set in excel format.
Here is a brief summary of the procedure I did:
1. I saved the original excel data as csv and txt formats, separately.
2. I imported two data using the following codes.  There were no
2016 Jan 15
0
JDataFrame API
Tom,
this may be good for embedding small data sets, but for practical purposes is doesn't seem like the most efficient solution.
Since you didn't provide any code, I built a test case using the build-in Java JSON API to build a medium-sized dataset (1e6 rows) and read it in just to get a ballpark (see
https://gist.github.com/s-u/4efb284e3c15c6a2db16
# generate:
time java -cp
2010 Oct 15
0
nomianl response model
Is there a way to estimate a nominal response model?
To be more specific let's say I want to calibrate:
\pi_{v}(\theta_j)=\frac{e^{\xi_{v}+\lambda_{v}\theta_j}}{\sum_{h=1}^m
e^{\xi_{h}+\lambda_{h}\theta_j}}
Where $\theta_j$ is a the dependent variable and I need to estimate
$\xi_{h}$ and $\lambda_{h}$ for $h \in {1...,m}$.
Thank you,
Mauricio Romero 
Quantil S.A.S.
Cel: 3112231150
2016 Jan 15
0
JDataFrame API
> On Jan 15, 2016, at 12:35 PM, Thomas Fuller <thomas.fuller at coherentlogic.com> wrote:
> 
> Hi Simon,
> 
> Thanks for your feedback. -- this is an observation that I wasn't
> considering when I wrote this mainly because I am, in fact, working
> with rather small data sets. BTW: There is code there, it's under the
> bitbucket link -- here's the direct
2011 Mar 04
1
grouping data
Hi R-list,
I have a data set with plot locations and observations and want to label
them based on locations.  For example, I have GPS information (x and y) as
follows:
> x
  [1] -87.85092 -87.85092 -87.85092 -87.85093 -87.85093 -87.85093 -87.85094
  [8] -87.85094 -87.85094 -87.85096 -87.85095 -87.85095 -87.85095 -87.85096
 [15] -87.85096 -87.85096 -87.85096 -87.85088 -87.85088 -87.85087
2024 Mar 08
0
The urban cruiser 20-inch fat tire e-Bike
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2004 May 26
1
Same Problem.... RE: Can see server, but can't see shares. Whazzup?
ok 
I did it, but *@ no success...
I used Smb with W2K for years without Problems, but now with this
eXPerimental OS....
Here comes my smb.conf I do not see an error... :
 Samba config file created using SWAT
# from 0.0.0.0 (0.0.0.0)
# Date: 2004/05/27 13:56:58
# Global parameters
[global]
workgroup = RESULT-THALIS
netbios name = MASTER
server string = Result-Thalis Server
encrypt passwords =
2004 Aug 06
0
Live from Mongolia
FYI...  A recent article I wrote regarding my streaming adventures.
===================
Hoov's Musings
===================
volume 6, number 7
Source:  http://www.acuitive.com/musings/
Live From Mongolia
Introduction from Mark Hoover
Acuitive people have all kinds of interesting hobbies, a few of which I can 
actually talk about.  In the case of Roy Harvey, his hobby is providing 
live or
2009 Jul 15
1
Error in simulation R-code
Dear List,
I have got error message when I run the R-code. Can anyone has a suggestion?
v.code <- df.bm7[,c(10:31)]; v.code[1:3,]
names(v.code)
CM = v.code # variable binomial code
sim.sp <- function(data,CM,n,N)
{
  C <- matrix(rep(NA,N),ncol=1)
    for(i in 1:N)
    {
        j <- n
        xx <- which(colSums(CM[j,])==1)
        V <- names(xx)
        V <- paste(V,
2009 Jul 15
1
Simulation code error
Dear List,
I have some problem with my simulation code. Here is output from R:
> sim.sp <- function(data,CM,n,N)
+ {
+   C <- matrix(rep(NA,N),ncol=1)
+ for(i in 1:N)
+ {
+ j <- n
+ xx <- which(colSums(CM[j,])==1)
+ V <- names(xx)
+ V <- paste(V, collapse="+")
+ V <- paste("SBA~", V)
+ rd <- round(nrow(data)*(2/3))
+ d <-