similar to: holding argument(s) fixed within lapply

Dear R users, Let's say I have a list with components being 'm' matrices (as exemplified in the "mylist" object below). Now, I'd like to subset this list based on an index vector, which will partition each matrix 'm' in 2 sub-matrices. My questions are: 1. Is there an elegant way to have the results shown in mylist2 for an arbitrary number of matrices in mylist?

Dear List, Let's say I have a list whose components are 2 matrices (as exemplified in the "mylist" object below). I'd like to create a list with components being 4 matrices based on an logical index vector. is there a way to simplify what I'm doing to obtain the results in "mylist2"? I'd like something that would work on an arbitrary number of elements in

Hello All, I have multiple "list of lists" in the form of Mylist1[[N]][[K]]$Name_i, with N=1..6, K=1..3, and i=1..7. Each Name_i is a matrix. I have 30 of these objects Mylist1, Mylist2, ... I would like to merge these lists by each Name_i using rbind, but I couldn't figure out how to do it. What I want at the end is a single "list of lists", again in the form of

Hi, everybody: I asked about this in r-help last week and promised a summary of answers. Special thanks to the folks that helped me understand do.call and pointed me toward plyr. We face this problem all the time. A procedure generates a list of data frames. How to stack them together? The short answer is that the plyr package's rbind.fill method is probably the fastest method that is not

Hello Again Gurus and Lurkers: I?m trying to build a very user-friendly function which does aov without having the user type in a formula (which would be tedious in this case). The idea is to take the response from a PCA score matrix, and the factors from a list. A simple example is the function given below, along with test data and a sample call to the function. I'm certainly having

hello all, thank you for taking the time I have a matrix A that have column names (let say n columns), I want to reduce the matrix to have just a few of those column (p colums, this is trivial), but for the lines I want only the lines such that A(i,J) is part of a list (J is fixed and known) I am sure it is very easy but I don't find it (I tryed which but it doesn't seem to work) Surely

Hi all, I would like to iterate through a list with named elements and access the names within an lapply / sapply call. One way to do this is iterate through the names and index the list with the name. Is there a way to iterate through the list elements themselves and access the element names within in the function? For example, mylist <-

Hi Can someone help me with this? How can I apply a function to a list of variables. something like this listvar=list("Monday","Tuesday","Wednesday") func=function(x){x[which(x<=10)]=NA} lapply(listvar, func) were Monday=[213,56,345,33,34,678,444] Tuesday=[213,56,345,33,34,678,444] ... in my case I have a neverending list of vectors. Thanks!

Hello I want to unlist the attached element getting only the first element in each element of the list. The last element of the list looks as this: [[5065]] [[5065]]$Pluv3Meses [1] 274.4 [[5065]]$PluvMesesMedio [1] 378.2667 [[5065]]$Pluv2UltimosMeses [1] 23.33333 So I would like to get for each element of the list the element called Pluv3Meses. The whole list has 5065 elements but when I try to

I have a question regarding accessing the names of list components when applying a function with lapply. Here is an example that demonstrates what I'd like to do. I have a list like this one: mylist <- list(a=letters[1:10], b=letters[10:1], c=letters[1:3]) Now I would like to append the names of the list components to their corresponding vectors with the c() function. I thought this

Hi all, I'm trying to use lapply on a list with the following command: out<-lapply(mylist,myfun,par1=p,par2=d) (1) where myfun<-function(x,par1,par1) {.....} (2) now this function is in fact a wrapper for some Fortran code I have written so I think this might be the problem. When I call lapply() as in (1) I get the following message: Error in get(x,

I have split my original dataframe to generate a list of dataframes each of which has 3 columns of factors and a 4th column of numeric data. I would like to use lapply to apply the fitdistr() function to only the 4th column (x$isi) of the dataframes in the list. Is there a way to do this or am I misusing lapply? As a second solution I tried splitting only the numeric data column to yield a list

Hi everybody, I want to use macro in my R code. But defmacro was not in my libraries. So I installed it : > install.packages("gtools") Installing package(s) into ?C:/Program Files/R/R-2.13.2/library? (as ?lib? is unspecified) essai de l'URL 'http://cran.cict.fr/bin/windows/contrib/2.13/gtools_2.6.2.zip' Content type 'application/zip' length 102500 bytes (100 Kb)

Hello: Forgive me, this is surely a simple question but I can't figure it out, having consulted the help archives and "Data Manipulation With R" (Spector). I have a list of 11 data frames with one common variable in each (prov). I'd like to use lapply to go through and recode one particular level of that common variable. I can get the recode to work, but it only returns the

On Fri, Sep 22, 2017 at 4:02 AM, Jason Wang <jasowang at redhat.com> wrote: > This patch introduces vhost_prefetch_desc_indices() which could batch > descriptor indices fetching and used ring updating. This intends to > reduce the cache misses of indices fetching and updating and reduce > cache line bounce when virtqueue is almost full. copy_to_user() was > used in order to

On Fri, Sep 22, 2017 at 4:02 AM, Jason Wang <jasowang at redhat.com> wrote: > This patch introduces vhost_prefetch_desc_indices() which could batch > descriptor indices fetching and used ring updating. This intends to > reduce the cache misses of indices fetching and updating and reduce > cache line bounce when virtqueue is almost full. copy_to_user() was > used in order to

While working with sapply, the documentation states that the simplify argument will yield a vector, matrix etc "when possible". I was curious how the code actually defined "as possible" and see this within the function if (!identical(simplify, FALSE) && length(answer)) This seems superfluous to me, in particular this part: !identical(simplify, FALSE) The preceding

Hi It seems, I just miss something. I defined treshold <- function(pred) { if (pred < 0.5) pred <- 0 else pred <- 1 return(pred) } and want to use apply it on a vector sapply(mylist[,,3],threshold) but I get: Error in match.fun(FUN) : Object "threshold" not found thanks for help cheers chris -- Christoph Lehmann <christoph.lehmann at gmx.ch>

Hi, how to estimate a the following model in R: y(t)=beta0+beta1*x1(t)+beta2*x2(t)+...+beta5*x5(t)+beta6*y(t-1)+beta7*y(t-2)+beta8*y(t-3) 1) using "lm" : dates &lt;- as.Date(data.df[,1]) selection&lt;-which(dates&gt;=as.Date("1986-1-1") &amp; dates&lt;=as.Date("2007-12-31")) dep &lt;- ts(data.df[selection,c("dep")]) indep.ret1

On Fri, Sep 22, 2017 at 04:02:32PM +0800, Jason Wang wrote: > This patch introduces vhost_prefetch_desc_indices() which could batch > descriptor indices fetching and used ring updating. This intends to > reduce the cache misses of indices fetching and updating and reduce > cache line bounce when virtqueue is almost full. copy_to_user() was > used in order to benefit from modern cpus