similar to: Copying a dataframe

Displaying 20 results from an estimated 2000 matches similar to: "Copying a dataframe"

2013 Mar 12
2
Troubleshooting code
Hi everyone, I am having trouble understanding where I went wrong with my code. It seems to logically be "all there" but the output says otherwise. I know this is a bit long but I can't seem to find the errors so I would appreciate your help :) This is my program : files<-Sys.glob("*.rescount.txt");length<-length(files);* #selecting all files of a particular
2013 Mar 25
3
nested 'while' loops
Hi everyone, I'm using the following code to go over every element of a data frame (row wise). The problem I am facing is that the outer 'x' variable is not incrementing itself, thus, only one row of values is obtained, and the program does not proceed to the next row. This is the code: while(x<=coln) { while(y<=rown) { n<-as.numeric(df[[y]][x]);
2013 Mar 19
4
Copying rows in data frames
Hi, I'm trying to copy the first row of one data frame to another. This is the statement I am using : df2[1,]<-df1[1,]; I have printed them out separately: df1[1,] = A C D E F But after copying: df2[1,] = 96 29 88 122 68 Why isn't it copying? They are both data frames, and "as.character" isn't working either. Thanks for your input :) [[alternative HTML version
2013 Feb 28
4
Iteration through a list in R
Hello :) I'm just starting out with R and would appreciate your help with a couple of problems I am running into. I have used Sys.glob to get a list of all filenames having a particular file extension (in my case, *.txt) I would now like to use this list in the following manner: I would like to use each filename from the list and open that file into a tab separated matrix and proceed. How can
2013 Mar 14
3
Equivalent of deal in R?
HI, I'm looking for a function that does the same as deal() in MATLAB, i,e, for an array x[1 2 3] [a,b,c]=x; such that a=1, b=2, c=3 Does R have any functions similar to this? [[alternative HTML version deleted]]
2003 Sep 14
1
reading in a file with multiple data types
Hi, I have a data file which contains multiple data types (char and numeric) alongside with line spaces, tabs and spaces. I hope to extract out the numeric blocks of the data, probably as matrices or dataframes where each line in the data block is a corresponding row in the dataframe/ matrix. I have tried using many R read functions but they do not seem to yield the appropriate structure that
2013 Mar 22
3
trouble with data frame
Hi everyone, I am trying to use the values from every cell of the data frame in a further calculation. This is the code that I am using to catch every element of the data-frame. while (a<=10) { while (b<=10) { n<-as.numeric(df[a,b)]; ...; } } The problem is that when I print out 'n' I get the following errors : "NULL" (if printed without as.numeric), and
2003 Aug 04
1
Error in calling stepAIC() from within a function
Hi, I am experiencing a baffling behaviour of stepAIC(), and I hope to get any advice/help on what went wrong or I'd missed. I greatly appreciate any advice given. I am using stepAIC() to, say, select a model via stepwise selection method. R Version : 1.7.1 Windows ME Many thanks and best regards, Siew-Leng ***Issue : When stepAIC() is placed within a function, it seems
2013 Mar 26
2
NaNS Error Message
Hi, I'm using R to do a series of calculation and I have gotten several warnings that say "NaNS produced". Whatever I could read on line gives me an idea that this warning is produced when the number is use is a negative log or otherwise mathematically problematic. I'm getting this error while using factorial() and gamma () on strictly positive numbers (always greater than zero).
2010 Jun 03
2
deduplication
Colleagues, I am trying to de-duplicate a large (long) database (approx 1mil records) of diagnostic tests. Individuals in the database can have up-to 25 observations, but most will have only one. IDs for de-duplication (names, sex, lab number...) are patchy. In a first step, I am using Andreas Borg's excellent record linkage package (), that leaves me with a list of 'pairs' looking
2004 Dec 12
2
Help : generating correlation matrix with a particular structure
Hi, I would like to generate a correlation matrix with a particular structure. For example, a 3n x 3n matrix : A_(nxn) aI_(nxn) bI_(nxn) aI_(nxn) A_(nxn) cI_(nxn) aI_(nxn) cI_(nxn) A_(nxn) where - A_(nxn) is a *specified* symmetric, positive definite nxn matrix. - I_(nxn) is an identity matrix of order n - a, b, c are (any) real numbers Many attempts have been unsuccessful because a
2004 May 16
2
Error in using coxph()
Hi, I am getting errors of the following kind. I can't seem to point the source of the error. I would greatly appreciate any advice. Many thanks and good day, -Melinda Error message : ---------------- "Ran out of iterations and did not converge in: fitter(X, Y, strats, offset, init, control, weights = weights,..." Details : --------- E is a vector of survival times (or censored
2004 Dec 13
1
Re: Help : generating correlation matrix with a particular
************************************************************ Important: We would draw your attention to the notices at the bottom of this e-mail, particularly before opening and reviewing any file attachment(s). ************************************************************ Here is some code we have used. a<-array(c(1,.9,.7,.9,1,.3,.7,.3,1),dim=c(3,3)) a s<-eigen(a)$vectors
2012 Jul 11
4
Help with loop
Hi, I have two dataframes: The first, df1, contains some missing data: cola colb colc cold cole 1 NA 5 9 NA 17 2 NA 6 NA 14 NA 3 3 NA 11 15 19 4 4 8 12 NA 20 The second, df2, contains the following: cola colb colc cold cole 1 1.4 0.8 0.02 1.6 0.6 I'm wanting all missing data in df1$cola to be replaced by the value of df2$cola.
2008 Sep 14
5
difference of two data frames
Hello I have 2 data frames DF1 and DF2 where DF2 is a subset of DF1: DF1= data.frame(V1=1:6, V2= letters[1:6]) DF2= data.frame(V1=1:3, V2= letters[1:3]) How do I create a new data frame of the difference between DF1 and DF2 newDF=data.frame(V1=4:6, V2= letters[4:6]) In my real data, the rows are not in order as in the example I provided. Thanks much Joseph [[alternative HTML version
2005 Jun 29
3
return NA
A<-c(1,2,NA,7,5) B<-c(3,4,1,4,1) C<-c(6,5,6,NA,9) D<-c(8,7,4,6,2) df1<-cbind(A,B,C,D) for(i in seq(1,ncol(df1)-1, by=2)) { ifelse(df1[,i]=="NA",df1[,i+1]=="NA",df1[,] ) } Tried several variations but none worked. I wish to find any NA's in column's 1 or 3 and change the numerical value to the right of the " NA"'s . In this case I
2011 Aug 18
2
Best way/practice to create a new data frame from two given ones with last column computed from the two data frames?
Dear expeRts, What is the best approach to create a third data frame from two given ones, when the new/third data frame has last column computed from the last columns of the two given data frames? ## Okay, sounds complicated, so here is an example. Assume we have the two data frames: df1 <- data.frame(Year=rep(2001:2010, each=2), Group=c("Group 1","Group 2"), Value=1:20)
2008 Feb 10
11
data frame question
Hello I have 2 data frames df1 and df2. I would like to create a new data frame new_df which will contain only the common rows based on the first 2 columns (chrN and start). The column score in the new data frame should be replaced with a column containing the average score (average_score) from df1 and df2. df1= data.frame(chrN= c(“chr1”, “chr1”, “chr1”, “chr1”, “chr2”, “chr2”, “chr2”),
2012 Nov 22
4
Data Extraction
Hello, I would appreciate if someone could help me resolve the following: 1. df1[!is.na( X1 | X2 | X3 | X4 | X5),][,1:5] # This does not work 2. Is these message harmful? The following object(s) are masked from 'df1 (position 3)': X1, X2, X3, X4, X5 Thanks, Pradip Muhuri #Reproducible Example set.seed(5) df1<-data.frame(matrix(sample(c(1:10,NA),100,replace=TRUE),ncol=5))
2009 Nov 19
5
Accessing list names in lapply
Hi, When using lapply (or sapply) to loop over a list, can I somehow access the index of the list from inside the function? A trivial example: df1 <- split( x=rnorm(n=100, sd=seq(from=1, to=10, each=10)), f=letters[seq(from=1, to=10, each=10)] ) str(df1) #List of 10 # $ a: num [1:10] -0.801 0.418 1.451 -0.554 -0.578 ... # $ b: num [1:10] -2.464 0.279 4.099 -2.483 1.921 ... # $ c: num