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Hi all, Why subscripting a one column matrix drops one dimension? > x<- matrix(rnorm(100), ncol=1) > str(x) num [1:100, 1] -0.413 -0.845 -1.625 -1.393 0.507 ... > str(x[20:30,]) num [1:11] -0.315 -0.693 -0.771 0.448 0.204 ... > str(x[20:30]) num [1:11] -0.315 -0.693 -0.771 0.448 0.204 ... This breaks: > cov(x) [,1] [1,] 0.9600812 >

Hi all, I want to approximate te shape of an area defined by a set of points. The convex hull is not good enough, but I think that an alpha shape would be fine. I did an RSiteSearch(), google search, RSeek.org search, looked at the CRAN Views, but was unable do find a function in R that computes the alpha shape. Does anyone know if there is such a function in R? Theank you very much. Moacir

All, I'm having problems w/ a simple attempt to subset an xyplot. The first plot below is a plot of y versus x for certain values of a third categorical variable z. Now I'd like to further restrict this to certain values of variable y. Neither of the two attempts below work. Any suggestions much appreciated. (note: I don't want to merely use ylim since I have a loess plot and I

Another question on functions - I have something that looks like plotter<-function(i){ temp.i<-rwb[rwb$vector1 <=(i*.10),] with(temp.i, plot(vector2, vector3, main=(i*.10),)) mod<-lm(vector3~vector3-1,data=temp.i) r2<-summary(mod)$adj.r.squared rsqrd[i]<-r2 legend("bottomright", legend=signif(r2), col="black") abline(mod) rsqrd<<-rsqrd } I'd

All, In the function below I have 24 individuals and 6 calculations per individual. The 6 calculations are collected each time in a 1:24 loop when calculating "delta". I'd like to collect all 144 = 24*6 calculations in one vector ("delta.patient.comb"). The function works as is via indexing, but is there an easier way to collect the measurements via appendinng the 6

hi i've configured a Beronet BN8S0 Card with misdn beronet utility. the card is configured with all lines in TE and P2P mode, and it is connected with the special cable with an ISDN connection. i've turned on debugging to level 4, this is the output from the asterisk cli when i receive a call: P[ 5] MGMT: Short status dinfo 1000001 P[ 5] MGMT: SSTATUS: L1_ACTIVATED P[ 5] handle_frm:

All, How does one replace plot symbols with say subject IDs when using xyplot? Or superimpose them next to plot symbols? I searched the archives under various key words but haven't had much. Any suggestions or links much appreciated. Sample code below. David junk.frm = data.frame(ID = rep(1:16, each = 2), x, y, z = rep(c("D", "P"), 16)) y = c( 0.4, 0.6, -0.1,

I''ve built the slackware packages of rails. rails path is: /frm/ruby/1.8.6/lib/ruby/site_ruby/1.8 RUBYLIB : /frm/ruby/1.8.6/lib/ruby/site_ruby/1.8:/frm/ruby/1.8.6/lib/ ruby/site_ruby/1.8/i686-linux/ I could created the rails application, but files are missing. Config - boot.rb, database.yml, environment.rb and routes.rb Public -

Hi, I have a working asterisk 1.4.0 with Mysql Realtime configuration, and today I encountered this error. Now, I have no acces to any information in mysql realtime, so nothing work now !!!!! [Jan 24 10:32:40] DEBUG[31070] res_config_mysql.c: MySQL RealTime: Everything is fine. [Jan 24 10:32:40] DEBUG[31070] res_config_mysql.c: MySQL RealTime: Retrieve SQL: SELECT * FROM extensions

All, When saving plots to a pdf file via the pdf function, I would like to be able to automatically expand the graphics device to achieve the same result as when one does this manually (e.g., clicking the green expand button on the upper left of the graph on Mac OS). Consider simple example below: library("lattice") foo.frm = data.frame(Subject = rep(c(1:4), each = 9), Y =

Hi Guys, I''m having serious troubles resizing a dialog with a ListCtrl. The ctrl will not resize horizontally no matter what I''m doing. I''ve attached a sample code below. Any help will be greatly appreciated, as I really like wxRuby :) I''ve also tried to copy from the example from listtest.rbw, but that also doesn''t seem to work. Another thing

Dear all, Through the following code, I wanted to perform correlation test repetedly (through loop) on different combinations of variables of a data set. Code: x=read.table("sample.txt",header=T,sep="\t") out="corout.txt" sink(out) nm = names(x) print(nm) nvr=3 # nvr=Total no. of variables in the input data file for (i in 1:(nvr-1)) { for(j in (i+1):nvr) { frm=

Guys, i know i saw this somewhere but i cant seem to locate that info now... Scenario: ............... I have a simple two interface firewall. The firewall machine also provides some services to the LAN and to the NET. What i would like to do is allow only a particular range of IPs frm the internet to access those services. What do i need to do with my ''rules'' file. Ideally

Hi. I have a strange problem. I installed cacti, and set it up. When I click on the Plugins Management, I noticed Error "FATAL: Database or Table does not exist" Further testing revealed that at the moment MySQL can not create temporary files in /tmp. It is same for ANY database! SELinux is disabled. I logged to mysql as root and error is same. Command used is: CREATE TEMPORARY

I''ve built the slackware packages of rails. rails path is: /frm/ruby/1.8.6/lib/ruby/site_ruby/1.8 RUBYLIB : /frm/ruby/1.8.6/lib/ruby/site_ruby/1.8:/frm/ruby/1.8.6/lib/ruby/site_ruby/1.8/i686-linux/ I could created the rails application, but files are missing. Config - boot.rb, database.yml, environment.rb and routes.rb Public -

Ok, and if I would just like to force my slope coefficients to be inside an interval, let's say, between 0 and 1? Is there a way in R to formulate such a constraint regression? Thanks in advance and kind regards, Aljosa Aljosa Aleksandrovic, FRM, CAIA Quantitative Analyst - Convertibles aljosa.aleksandrovic at man.com Tel +41 55 417 7603 Man Investments (CH) AG Huobstrasse 3 | 8808

Have you tried web searching on " R constrained linear regression" or similar. There seemed to be resources related to your issues when I looked. You might also search on rseek.org . There are apparently several packages that do regression with constraints, but I don't know if they fit your situation. Cheers, Bert Bert Gunter "The trouble with having an open mind is that

I had to put a new HD in, and now I''m reinstalling everything, and can''t get mysql to fully work. I can''t remember how I fixed it. I''ve searched everywhere online and can''t find anything. when I try to use the >mysql command I get this: Can''t connect to local MySQL server through socket ''/tmp/ mysql.sock'' (2) My first

Hi Gabor, Thanks a lot for your help! I tried to implement your nonlinear least squares solver on my data set. I was just wondering about the argument start. If I would like to force all my coefficients to be inside an interval, let?s say, between 0 and 1, what kind of starting values are normally recommended for the start argument (e.g. Using a 4 factor model with b1, b2, b3 and b4, I tried

If the slope coefficients sum to a constant, the regressors are dependent and so a unique solution is impossible (an infinity of solutions would result). So I think you have something going on that you don't understand and should consult a local statistician to help you formulate your problem appropriately. Cheers, Bert Bert Gunter "The trouble with having an open mind is that people