similar to: Problems with tunnel: Got late or replayed packet, packet is 150 seqs in the future, expiring symmetric keys

I get a lot of these in my log, especially when I am moving lots of traffic across the vpn: Sep 20 10:45:11 titan tinc.tdvpns[16152]: Got late or replayed packet from holden (xx.yy.zz.ww port 655), seqno 37609, last received 37610 (sequence numbers displayed generally differ by only one) What exactly is this trying to say? Surely this doesn't simply mean that the udp packets arrived in a

Author: elowe Repository: /hg/zfs-crypto/gate Revision: 9af913595d90ad9ae8878d0b0284e6b1acc55d3c Log message: 6378297 FMA page fault events not being replayed due to changes in page retire Files: update: usr/src/uts/common/vm/page_retire.c

With pleasure we announce the release of tinc version 1.1pre5. Here is a summary of the changes: * Fixed long delays and possible hangs on Windows. * Fixed support for the tunemu device on iOS, the UML and VDE devices. * Small improvements to the documentation and error messages. * Fixed broadcast packets not reaching the whole VPN. * Tincctl now connects via a UNIX socket to the tincd

With pleasure we announce the release of tinc version 1.1pre5. Here is a summary of the changes: * Fixed long delays and possible hangs on Windows. * Fixed support for the tunemu device on iOS, the UML and VDE devices. * Small improvements to the documentation and error messages. * Fixed broadcast packets not reaching the whole VPN. * Tincctl now connects via a UNIX socket to the tincd

Hi! I have compiled and installed tinc 1.1pre5 on a ubuntu machine. With the tinc 1.0.x version that is included in the ubuntu repository I am used to having the config files in /etc/tinc/ and where each vpn has a own directory. The file nets.boot placed in /etc/tinc where I can specify which vpn tunnels that is going to start automatically. How can I get the vpn tunnels to start automatically

Dear R users, Has anyone implemented the weighted symmetric estimator, as inaugurated by Park,H. J. and Fuller,W. A,"Alternative estimators and unit root tests for the autoregressive process"? Is there a package that supports such estimation? Any idea how to perform it it R? Regards, Martin Ivanov ----------------------------------------------------------------- ?????? ??? - ??

Hi list, are there any functions or ideas to compute random numbers with a specific population mean and standard deviation from symmetric (but not normal) and asymmetric distributions? My first idea was to use e.g. rf() (and other R-functions for random number generation) and then scale the random numbers (for example: mean 300 and standard deviation 40), but I don't know if I'm wrong...

Is there a function in r that let's you efficiently invert a positive definite symmetric Block Toeplitz matrix? My matrices are the covariance matrices of observations of a multivariate time series and can be 1000*1000 or larger. I know the package 'ltsa' which seems to use the Trench algorithm to compute the inverse of a Toeplitz matrix. I am looking for a so to say

Hi, Can anyone please point to how to decompose BCCB (Block-Circulant-Circulant-Block) matrices? I am interested in the derivations: I do know that this can be numerically done using 2-dimensional FFTs. Many thanks and best wishes!

DeaR all, The stripchart function (graphics) is provides jittered and stacked univariate scatterplots, but I wonder if anyone has implemented a *symmetric* version of this - as in the lower panel of Wilkinson's paper: http://www.jstor.org/stable/2686111 I have looked through several functions in contributed packages that do similar things, but not found one that can do this. What am I

Dear list, I hope it is not a FAQ, but I searched the archives and Google, and found nothing. The question is simple : I do not understand why, starting from a symmetrical correlation matrix, heatmap produces an asymmetrical image. Best, Charles -- Charles Plessy, Ph.D. - Genome Science Laboratory The Institute for Physical and Chemical Research (RIKEN) 2-1 Hirosawa, Wako, Saitama 351-0198,

Can someone confirm that the EISPACK routines for eigenvalues of symmetric matrix are in base R. They seem to be, but I can't seem to locate where they are in the src tree. Thanks. Chong Gu -.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.- r-help mailing list -- Read http://www.ci.tuwien.ac.at/~hornik/R/R-FAQ.html Send "info", "help", or

Dear Reseacher, i find this modified version of SMAPE at pag 13 formula "msSMAPE" to to avoid the possibility of an inflation caused by zero values in the series using a Si component in the denominator of the symmetric MAPE http://www.stat.iastate.edu/preprint/articles/2004-10.pdf I wrote a function but I wish eventually correct error, change or improve with your suggestions. Please

Hello, I have a problem with a Grandstream being behind a symmetric nat. The box which does the nat is a german "Fritz Box". This one does nat for the internal network. In the internal network is a Granstream BudgeTone 100. The nat router has a dial-up connection, so ip changes on every dial-in. |------------| |------------| |--------| |Grandstream

I have the following matrix: 1 2 3 4 5 2 0.7760856 3 2.0222216 1.6907899 4 0.6148687 0.2424415 1.593916 5 3.0227028 2.3636083 1.512634 2.426591 6 3.2104434 2.5334957 1.730422 2.608584 0.2184739 the diagonal is 0 and it is a symmetric matrix. Is there any

I have following matrix : a = matrix(rnorm(36), 6) Now I want to replace the lower-triangular elements with it's upper-triangular elements. That is I want to make a symmetric matrix from a. I have tried with lower.tri() and upper.tri() function, but got desired result. Can anyone please tell me how to do that?

Here's an easy question: I'd like to convert a symmetric matrix to a vector composed of the upper.tri() part of it plus the diagonal, and convert it back again. What's the best way to achieve this? I'm wondering if there are some built in functions to do this easily. I can encode fine: v <- c(diag(A),A[upper.tri(A)]) but I don't see an easy way to recover A from v

Hi, I have this symmetric matrix, at least I think so. col1 col2 col3 [1,] 0.20 0.05 0.06 [2,] 0.05 0.10 0.03 [3,] 0.06 0.03 0.08 or structure(c(0.2, 0.05, 0.06, 0.05, 0.1, 0.03, 0.06, 0.03, 0.08 ), .Dim = c(3L, 3L), .Dimnames = list(NULL, c("var1", "var2", "var3"))) But isSymmetric() doesn't agree. Any comment? I am on R 2.10.1 Thanks. Jun

Dear R experts, I really have difficulty when I try to deal with this question. suppose X is a square symmetric matrix. The exponent of X is defined by the matrix limit as following: exp(X) = lim (I + X/n)^n, note: the limit is from n to infinite. How can I write R function for the above? Thank you very much -- View this message in context:

So many matrices are square symmetrical (i.e. variance-covariance matrices), is there any way to get R to split the matrix on its diagonal and just return one diagonal? So if I have mat<-matrix(c(1,4,3,4,1,2,3,2,1), nrow = 3, ncol=3, byrow=TRUE) is there anyway to get the lower right diagonal instead of the entire symmetric matrix? -------------------------------------------