similar to: context of runif()

Aha... Hadn't noticed that stringsAsFactors only works via as.is in read.table. Yes, the doc should probably be fixed. The code probably not -- packages loading different data sets depending on user options is an even worse idea than hav?ng the option in the first place... (I don't mean having the possibility, I mean the default.stringsAsFactor thing). In general, read.table() gets

Hi Peter, Sorry if I was not clear. Perhaps an example will make my point: > data(iris) > class(iris$Species) [1] "factor" > write.table(iris,'data/myiris.tab') > data(myiris) > class(myiris$Species) [1] "factor" > rm(myiris) > options(stringsAsFactors = FALSE) > data(myiris) > class(myiris$Species) [1] "factor" >

I tried it using file and it seems to work for saving: > data(iris) > con <- file("clipboard","w") > save(iris,ascii=T,file=con) > close(con) > readLines("clipboard") ... lengthy output follows which seems correct ... but not for loading: > con <- file("clipboard","r") > load(con) Error in load(con) : loading from

Hi all, I would like to do cross validation in random forest using rfcv function. As the documentation for this package says: rfcv(trainx, trainy, cv.fold=5, scale="log", step=0.5, mtry=function(p) max(1, floor(sqrt(p))), recursive=FALSE, ...) however I don't know how to build trianx and trainy for my data set, and I could not understand the way trainx is built in the package

Hi all, I would like to do cross validation in random forest using rfcv function. As the documentation for this package says: rfcv(trainx, trainy, cv.fold=5, scale="log", step=0.5, mtry=function(p) max(1, floor(sqrt(p))), recursive=FALSE, ...) however I don't know how to build trianx and trainy for my data set, and I could not understand the way trainx is built in the package

Is this a bug? I thought that "clipboard" could always be substituted for a filename when dealing with ASCII files. > data(iris) > save(iris,ascii=TRUE,file="clipboard") Error in file(file, "wb") : `mode' for the clipboard must be `r' or `w' Also this (where gclip is a utility found at unxutils.sourceforge.net that copies its standard input to the

Any responds?! On Wednesday, August 23, 2017 5:50 AM, Elahe chalabi via R-help <r-help at r-project.org> wrote: Hi all, I would like to do cross validation in random forest using rfcv function. As the documentation for this package says: rfcv(trainx, trainy, cv.fold=5, scale="log", step=0.5, mtry=function(p) max(1, floor(sqrt(p))), recursive=FALSE, ...) however I

Greetings, I have been exploring the use of the caret package to conduct some plsda modeling. Previously, I have come across methods that result in a R2 and Q2 for the model. Using the 'iris' data set, I wanted to see if I could accomplish this with the caret package. I use the following code: library(caret) data(iris) #needed to convert to numeric in order to do regression #I

On Thu, Feb 18, 2016 at 6:03 PM, Cook, Malcolm <MEC at stowers.org> wrote: > Hi Peter, > > Sorry if I was not clear. Perhaps an example will make my point: > >> data(iris) >> class(iris$Species) > [1] "factor" >> write.table(iris,'data/myiris.tab') >> data(myiris) >> class(myiris$Species) > [1] "factor" >>

Hi, > Aha... Hadn't noticed that stringsAsFactors only works via as.is in read.table. > > Yes, the doc should probably be fixed. The code probably not Agreed. Is someone on-list authorized and willing to make the documentation change? I suppose I could learn what it takes to be a "player", but for such a trivial fix, it probably is overkill. Dissenting opinions?

Hello, Simple question that I am stuck on and can't seem to find an answer in the help files currently. I have a list which contains repeated ID's. I would like to have R count the number of ID's. For example: ID=c(1,1,1,1,2,2,2,2,3,3,3,3) as.data.frame(ID) Clearly, there are 3 groups. How would I have R give me the summary: ID 3 Many thanks, Charles [[alternative HTML

A general question that I have been pursuing for some time but have set aside. When finishing some analysis, I can have multiple matrices that have specific column names. Ideally, I would like to combine these separate matrices for a final output as a csv file. A generic example: Matrix 1 var1A var1B var1C x x x x x

Hello, I am trying to reformat some data so that it is organized by group in the columns. The data currently looks like this: group X3.Hydroxybutyrate X3.Hydroxyisovalerate ADP 347 4 4e-04 3e-04 5e-04 353 3 5e-04 3e-04 6e-04 359 4 4e-04 3e-04

Hello R users, This is more of a convenience question that I hope others might find useful if there is a better answer. I work with large datasets that requires multiple parsing stages for different analysis. For example, compare group 3 vs. group 4. A more complicated comparison would be time B in group 3 of group L with B in group 4 of group L. I normally subset each group with the

Hiya, Probably been debated elsewhere.... I note that R's `data` function does not respect default.stringsAsFactors By my lights, it should, especially as it is documented to call read.table, which DOES respect. Oh, but: http://r.789695.n4.nabble.com/stringsAsFactors-FALSE-tp921891p921893.html Compelling. I have to agree. So, I change my mind. By my lights, `data` should then be

Generic question... I am familiar with generic power calculations in R, however a lot of the data I primarily work with is multivariate. Is there any package/function that you would recommend to conduct such power analysis? Any recommendations would be appreciated. Thank you for your time, Charles [[alternative HTML version deleted]]

To R users, I am trying to use cut2 function from the 'Hmisc' library. However, when I try and run the function on the following variable, I get an error message (displayed below). I suspect it is because of the NA but I have no idea how to address the error. Many thanks to any insights. structure(list(var1 = c(97, 97, 98, 98, 97, 99, 97, 98, 99, 98, 99, 98, 98, 97, 97, 98, 99, 98,

Hello everyone, I'm having some trouble interpreting the results of a Wilcoxon (Mann-Whitney U) test. Hope you can help. This is the R script that I am running: a <- c(1, 1, 1, 1, 1, 1, 1, 1, 3, 1, 1, 1, 2, 1, 5, 1, 1, 1, 3, 1, 1, 1, 1, 1, 1, 3, 1, 1) b <- c(1, 2, 1, 1, 2, 3, 2, 2, 1, 2, 1, 1, 1, 2) wilcox.test(a, b, alternative="t", mu=0, exact=FALSE, paired=FALSE) #1st

Greetings R users, I am trying to renumber my groups within the file shown below. The groups are currently set as 8,9,10,etc. I would like to renumber this as 1,2,3,etc. I have searched the help files and only come across using the rownames to renumber the values but I need to match values. Any assistance is always appreciated, Regards, Charles structure(list(Group = structure(c(1L, 1L, 1L,

Greetings R users, I have a curious problem. I read in a csv file (subset shown below) as normal data=read.table("C:/Users/Chaz/Desktop/test.csv",sep=",",header=TRUE, na.strings=".") However, the numbers from the dataset are not registered as numeric: is.numeric(data$Mesh) [1] FALSE When I try as.numeric, it converts all the values to different integers. This