similar to: low pass filter analysis in R

Hello, I have a big number lets say of around hundred digits. I want to subset that big number into consecutive number of 5 digits and find the product of those 5 digits. For example my first 5 digit number would be 73167. I need to check the product of the individual numbers in 73167 and so on. The sample number is as follows:

Dear R-users, I have a dataset as like below, and I want to subtotal the values of rice,wheat and maize by year for each fid. fid      year     rice     wheat      maize ------------------------------------------------ 1        1995      5        NA           NA 1        1995      NA        3           NA 1        1995      NA       NA           2 1        1996      4        NA           NA 1  

Hi , I am trying to convert the date as factor to date using "as.date" function in R. I have the date in the following format 2008-01-01 02:30 I tried to use the following command : as.Date(mydata$Date, format="%y-%m-%d ") Can somebody help me with this ? I was able to convert the format with no hour but getting difficulty with hour included. Thank you.

Dear R people, In typing names of functions (built in or from a package) I often guess wrong, and have to look the name up. In other words, I don't understand the logic in naming functions (if there is any): - most names are plain, lower case: cos, plot, sapply, t, toupper, unserialize, (etc) - some are capitalized: Filter, Machine, Map, NCOL, RNGversion, T (etc) -

Hello All, I have a data with two columns. In one column it is date and in another column it is flow data. I was able to read the data as date and flow data. I used the following code: creek <- read.csv("creek.csv") library(ggplot2) creek[1:10,] colnames(creek) <- c("date","flow") creek$date <- as.Date(creek$date, "%m/%d/%Y") The link to my data

I have created a graph with basic R plot with 2 rows and 3 columns. With the basic plot feature of R I had to write several lines of code to come up with the graph https://www.dropbox.com/s/f7d6ei6krtcrtti/hello.png I was wondering whether we can plot multiple series in each plot using ggplot as created in the above link. If anyone could give me any suggestion then I could try on ggplot. I

Hi I am trying to find the relationship between two variables. First I fitted a linear model between two variables and I found the following results: Residual standard error: 0.03253 on 2498 degrees of freedom Multiple R-squared: 0.5551, Adjusted R-squared: 0.5549 F-statistic: 3116 on 1 and 2498 DF, p-value: < 2.2e-16 Then I used the cor function to see the correlation between two variable

Hello All, I have plotted a scatter plot in ggplot2 and added a regression line and a regression equation. But the processing is very very slow. One reason might be because I have so many data pairs. Is there any way to speed up this code ? I need to create a multiple layout as well. The code I have used is as follows: setwd("C:/Users/jzd0009/Documents/R software") mydata <-

Hello All, I have a data file in a text format and there are two data sets. The data set are continuous. For each data set there is a header which has the number of data rows and the name of data series. For example first data set has "6240 Terry Cove-Model". Then the data for that series follows upto 6240 rows. Then another data would start and it will have the header such as

Hello All, I have a discontinuous dataset and I used spplot to plot the points. I was wondering whether it is possible to show the legend of the plot as color ramp. I saw that on continuous data. If anyone could tell me that would be great. Another thing I would like to know is how can we create the horizontal legend. By default, the legend is vertical. I was able to shift the legend inside

hi everybody I wonder if there is a simple way, but not simple would be ok too, to customize info/welcome page at session start time? what I'd like to do is to put together simple short howto / dos & don'ts page for users, I'm thinking it would be great if it was possible many thanks [[alternative HTML version deleted]]

every time I read the R release notes for the next release, I see many functions that I had forgotten about and many functions that I never knew existed to begin with. (who knew there were bibtex facilities in R? obviously, everyone except me.) I wonder whether there is a complete list of all R commands (incl the standard packages) somewhere, preferably each with its one-liner AND

Hello All, I am trying to do the time series analysis in R and I want to assign a vector as a time series. The data I provided is hourly. The data is from Jan 1 2008 to Dec 31 2009. How can I assign the data such that the first year is leap year and second is not ? airtemp <- read.csv("airtemp.csv",header=T,sep="") aw <- ts(airtemp,start=2008,frequency=8784,end=2009)

I am trying to read a csv file using the code; contol <- read.csv("RBS.csv") This is the error message I got; Error in file(file, "r") : unable to open connection In addition: Warning message: In file(file, "r") : cannot open file 'RBS.csv', reason 'No such file or directory' Where was the mistake? -- OYEYEMI, Gafar Matanmi (Ph.D) Senior

Dear R users, I am working on a data-set with 3 species. They are apple, orange and banana. I want to annotate the facets only on the bottom panel. However, by default I am getting annotations on all the plots. I was able to get text annotation only on the desired plot. However, I am confused what I need to do for the arrows / segments. Here is my code: library(ggplot2) library(grid) tempobs

Hi, I have 35 data files for reading. I would like get a program for performing reading of 35 files at once. All are of the type: Dados1.raw, Dados2.raw and so on. If the files have the same number of columns, I can read with the following commands: rm(list=ls()) filenames = list.files(path="~/Silvano/Arq", pattern="Dados+.*raw") names = substr(filenames, 1, 7) for(i in

I am trying to solve an integral in R. However, I am getting an error when I am trying to solve for that integral. The equation that I am trying to solve is as follows: $$ C_m = \frac{{abs{x}}e^{2x}}{\pi^{1/2}}\int_0^t t^{-3/2}e^{-x^2/t-t}dt $$ [image: enter image description here] The code that I am using is as follows: a <- seq(from=-10, by=0.5,length=100) ## Create a function to compute

Dear R Users, I have data for more than 3 years. For each year I want to find the day corresponding to Jaunary 1 of that year. For example: > x <- c('5/5/2007','12/31/2007','1/2/2008') > #Convert to day of year (julian date) - > strptime(x,"%m/%d/%Y")$yday+1 [1] 125 365 2 I want to know how to do the same thing but with time added. But I still

I have a data set for different time intervals. The data has three comment lines before data for each time interval. For each time interval there are 500 data points. I want to change the dataset such that I have the following format: t1 t2 t3 ................ 0.00208 0.00417 0.00625 ................. a1 a2 a3 ...................

Hi all, I'm working with a bunch of large graphs, and stumbled across something useful. Probably many of you know this, but I didn't and so others might benefit. Using pch="." speeds up plotting considerably over using symbols. > x <- runif(1000000) > y <- runif(1000000) > system.time(plot(x, y, pch=".")) user system elapsed 1.042 0.030 1.077