similar to: merge 2 data.frames

Dear R-List, I am sure there must be a very simple way to do this - I just do not know how... This is what I want to do: #my dataframe df<-data.frame(id=c("x01","x02","x03","x04","x05","x06"),a=c(1,2,NA,4,5,6),b=c(2,4,6,8,10,NA),c=c(NA,3,9,12,NA,NA),sum=c(3,9,15,24,15,6))    id    a     b     c   sum 1 x01  1     2    NA   3 2

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Hello, This is very basic and very frustrating. Suppose this: >A=5 >B=5 >C=10 > ls() "A" "B" "C" I would like this >xpto() 5 5 10 How can I do xpto()? Thanks Rui [[alternative HTML version deleted]]

Hello, I drew a plot of weight and height of people and fitted it with a polynominal regression x^2. (using curve()) Now I would like to draw the confidence interval line for the fitted curve. Please kindly advise the code for the purpose. Thank you. Elaine [[alternative HTML version deleted]]

Cam anyone tell me why the condition x[i] == "DISCONECTED" looks like producing an NA instead of TRUE/FALSE I would like to rename "DISCONNECTED" those factors inside the variable "dataset$STATUS.x" that are named "DISCONECTED" thank you > summary(dataset$STATUS.x) ACTIVE DISCONECTED PENDING SUSPENDED TERMINATED 158869 169181

Dear R users - I have a list of patient identifiers and diagnoses from inpatient admissions. I would like to reorganize the list, presently in a long format to a wide format in reshape, but in the absence of a "time" element, I am uncertain how to do this - any help greatly appreciated. ID Dx A nausea A diabetes A kidney failure A heart attack A fever B fever B

Hi all, I'm new on this list so I greet all. My question is: does exist in R a plot similar to candlestick plot but not based on xts (time series)? I have to plot a range of 4 value: for every item I have min value, max value and 2 intermediate values. I would like plot this like a candlestick, i.e. with a box between 2 intermediate values and 1 segment between box and min value and a segment

Dear All, This is a simple question, but I'm stumped about the simplest way to search a list object such as the following: This randomish snippet: n <- c(round(runif(round(runif(1,1,10),0),1,10),0)) alist <- new("list") for (i in seq_along(n)) { alist[[i]] <- c(round(runif(round(runif(1,1,10),0),1,10),0)) } names(alist) <- sample(letters[1:length(n)]) rm(n);c(alist)

Dear R fellows, Assume I define a <- expression(fn+tp) sen <- expression(tp/a) Now I'd like to know, which variables are necessary for calculating sen all.vars(sen) This results in a vector c(tp,a). But I'd like all.vars to evaluate the sen-object down to the ground level, which would result in a vector c(tp,fn) (because a was defined as fn+tp). In other words, I'd like

Hello, I'm writing a program that takes a tree in input (nested lists) and returns a copy of it replacing the leaves with something else (eg: a computation done on the original leaves). In the example below, the tree is composed by countries and cities, and the leaves (children of the cities) are vectors of numbers. The program takes this tree and replaces the vectors at the bottom by their

Hello again, I was looking for some way on How to delete repeated appearance in a String. Let say I have following string: Text <- "ahsgdvasgAbcabcsdahj" Here you see "Abc" appears twice. But I want to keep only 1 occurrence. Therefore I need that: Text_result <- "ahsgdvasgAbcsdahj" (i.e. the first one). Can somebody help me if it is possible using some R

Hi, I am trying to write a function which defines some arguments, then uses those arguments as arguments of other function calls. It's a bit tricky to explain, so a simple example will have to suffice. I imagine this has a simple solution, but perusing through environments and other help lists has not helped. Suppose I have two functions: f1 = function(a) {     b = a + 1     b } f2 =

Hello, I have a very data matrix and I have a file which has the names that I need to subset. However I cannot manage to subset the main file. ANy idea? bg <- read.table (file.choose(), header=T, row.names) bg Otu00022 Otu00029 Otu00039 Otu00042 Otu00101 Otu00105 Otu00125 Otu00131 Otu00137 Otu00155 Otu00158 Otu00172 Otu00181 Otu00185 Otu00190 Otu00209 Otu00218 Gi20Jun11 0.001217

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Hi All, I am trying to lable the y-axis on my scatterplot with the following: "Soil moisture content (m3m-3)" I am using the following coding for plotting the graph: plot(soilmoisture~gradientlevel, xlab="Levels of droughting gradient", ylab="Soil moisture content (m3m-3)", bty="l", font.main="2", pch=16, las=1, cex.lab="1.13") I have

Hi all, I have two vectors (columns) called "efinal" and "efinal 2". I want to plot them on the same plot and "draw" a shaded area beween the two lines using function polygon I have tried all but I don ?t understand the polygon area, can you help me with examples? plot(efinal,type="l",ylim=range(min(efinal2),

Hey all, In order to test if a marker is a risk factor, I built two models (using cox proportional hazard model). One model included this marker, and the other is not. Then, I use R package risksetROC to test how much predictive value did the marker add to this model. I get two C statistics by analyzing the linear predictors of the two models into this package. The qustion is How to test if two

Hi, When I create an environment object with new.env() and populate it with values then how can I save it into an .RData file properly, so it can be loaded later on in a new session? Saving an environment object with save() or save.image() results in an error message when loading again: Error: protect(): protection stack overflow Regards, benjamin ======================================

Hi, How do I retrieve the var.test() function code? I had a similar problem once before with another function but getMethods() solved the problem then. Now I tried several combinations for var.test() without success. Regards benjamin -- Benjamin Otto Universitaetsklinikum Eppendorf Hamburg Institut fuer Klinische Chemie Martinistrasse 52 20246 Hamburg [[alternative HTML

Dear List members, I really, like the feature that one can call R functions with mathematical expressions, e.g. curve(x^2, 0, 1) I wonder, how I can construct in a simple way a function like mycurve = function (expr) {...} such that that a call mycurve(x^2) has the same effect as the call curve(x^2, -100,100) Below is some code that works, but it seems much to complicated: it first