similar to: Compare each element of a list to a vector

'barplot' doesn't seem to work with vcd library. Am I supposed to detach vcd when I want to use barplot? Here's an example. Say I have the following matrix, > m <- matrix(c(1,2,3, 4,5,6, 3,4,5, 2,3,4), ncol=4) > m [,1] [,2] [,3] [,4] [1,] 1 4 3 2 [2,] 2 5 4 3 [3,] 3 6 5 4 Then > barplot(m) gives a barplot of the data. However,

Dear R gurus, I trying to convert a list of data frames to one data frame, but one of the values within the list is NULL, so I get the error "arguments imply differing number of rows." Do you know of a quick way to tell R to combine all that are not null? Here is a simple example: >

I have been writing some S4 classes and have a problem about how I might pass a signature to "c()". Take the following example: setClass("collection", representation("list", date="POSIXt")) x <- new("collection", list(1,2,3), date=Sys.time()) y <- new("collection", list(4,5,6), date=Sys.time()) obviously, I can do c(x,y), but

Dear R-helpers, I have split a dataframe into a list with five elements, with the following code: > datalist<-split(data,data$UNIT) I would now like to run some code (below) on each element of the list to extract rows from the list elements; then I would like to rbind the extracted rows into a new dataframe containing all of the extracted rows from all of the list elements. I don't

Hi. Can anyone suggest a simple way to obtain in R a list of vector coordinates of the following form? The code below is Mathematica. In[5]:= Flatten[Table[{i,j,k},{i,3},{j,4},{k,5}], 2] Out[5]= {{1,1,1},{1,1,2},{1,1,3},{1,1,4},{1,1,5},{1,2,1},{1,2,2},{1,2,3},{1 ,2,4},{1,2, 5},{1,3,1},{1,3,2},{1,3,3},{1,3,4},{1,3,5},{1,4,1},{1,4,2},{1,4,3}, {1,4,

I want to generate a list (called "dataList" below) where each of its levels is named. These names are assigned to nameList, which contains all possible permutations of size two taking letters from a larger alphabet, e.g., "aa",...,"Fd",..,"Z1",... One of these permutations is the character string "NA". It seems that when I try to name one

Dear all, I have a function that for a variable number of inputs plots them to the same plot I am doing this quite simply by plot(seq(from=start, to=stop, length.out=np), datalist[[1]]$dataset                                                                  xlim=c(start, stop), ylim=c(0, 1), type="l")                                                                                      

Hello, i only got a small problem. i try to create automatic new dataframes, or png?s. the main problem i got is: how can i create automatic a new name for a file (read out by simply "for") - i tried to use "(paste...) but theres an errormessage, about a wrong declination. R told it is as.character, but need as.Real. Should i use another method than "paste"? i tried as

Dear all, I have a code that looks like the following (I am sorry that this is not a reproducible example)     indexSkipped<-NULL  ....code Skipped that might alter indexSkipped     if (length(indexSkipped)==0)         spatial_structure<-spatial_structures_from_measurements(DataList[[i]]$Lon,DataList[[i]]$Lat,meanVector)     else        

First, here's the problem I'm working on so you understand the context. I have a data frame of travel activity characteristics with 70,000+ records. These activities are identified by unique chain numbers. (Activities are part of trip chains.) There are 17,500 chains. I use the chain numbers as factors to split various data fields into lists of chain characteristics with each element of

useR's, I want to apply this function to the columns of a data frame: u[u >= range(v)[1] & u <= range(v)[2]] where u is the n column data frame under consideration and v is a data frame of values with the same number of columns as u. For example, v1 <- c(1,2,3) v2 <- c(3,4,5) v3 <- c(2,3,4) v <- as.data.frame(cbind(v1,v2,v3)) uk1 <- seq(min(v1) - .5, max(v1) + .5,

Hi, The following is a cut/paste from http://developer.r-project.org/200update.txt: ... 3) When a package is installed, all the data sets are loaded to see what they produce. If this is undesirable (because they are enormous, or depend on other packages that need to be installed later, ...), add a `datalist' file to the data subdirectory as described in `Writing R

Hi, I've built a function to generate plots and would like to be able pass in column names as a parameter. Here's a boiled down version of what I have right now: pmts <- data.frame(date=c(1,2,3), all=c(5,6,7),maj=c(4,5,6),ind=c(3,4,5)) perc.mktshare <- function(df){ range1 <- floor(min(with(df, 100*ind/all))) range2 <- ceiling(max(with(df, 100*ind/all)))

Dear developeRs, my package FrF2.catlg128 holds large catalogues and is supposed to gain additional ones. All the catalogues are intended for the user. So far, the catalogues were stored in the data directory, and LazyData was "no". I understand that this is not considered wise any more (if it ever was), so that I want to change to LazyData "yes" with the next release

I have a dataframe called "data" with 5 records (in rows) each of which has been scored on each of many variables (in columns). Five of the variables are named var1, var2, var3, var4, var5 using headers. The other variables are named using other conventions. I can create a new variable called var6 with the value 15 for each record with this code: > var6=var1+var2+var3+var4+var5

Hi all, I had some trouble in?regrouping factor levels for a variable. After some experiments, I have figured out how I can recode to modify the factor levels. I would now like some help to understand why some methods work and others don't. Here's my code : rm(list=ls()) ###some trials in recoding factor levels char<-letters[1:10] fac<-factor(char) levels(fac) print(fac) ##first

hi all, I have a simple problem that i am not able to solve. I've a list called datalist with the following structure: [...] [[10]] [[10]]$a -1 0 1 -1 31 5 2 0 6 7 5 1 1 7 36 [[10]]$b -1 0 1 -1 31 5 2 0 6 7 5 1 1 7 36 [[10]]$c [1] 0.855 [[10]]$d [1] 0.855 [...] with [[1]] ... [[100]]. How can i get the mean value of datalist[[x]]$d, where x

I wonder if there is a more efficient way to do this task. Suppose I have two data frames, such as d1 <- data.frame(x = c(1,2,3), y = c(4,5,6), z = c(7,8,9)) d2 <- d1[, c('y', 'x')] The first dataframe d1 has more variables than d2 and the variable columns are in a different order. So, what I want to do is compare the two frames on the variables that are common between

The generic rule is that R is not a macro language, so looping of names of things gets awkward. It is usually easier to use compound objects like lists and iterate over them. E.g. datanames <- paste0("aa_", 2000:2007) datalist <- lapply(datanames, get) names(datalist) <- datanames col1 <- lapply(datalist, "[[", 1) colnum <- lapply(col1, as.numeric) (The 2nd

Dear all, My question how is it possible to define a matrix A with 10 rows 1 column, so that its elements are vectors of undefined length. I need to have a possibility later to add elements like A[1,1] <- c(A[1,1],3,4,5) Thanks a lot for the help! [[alternative HTML version deleted]]