similar to: Pass vector as multiple parameters (as in python f(*x))

Displaying 20 results from an estimated 20000 matches similar to: "Pass vector as multiple parameters (as in python f(*x))"

2008 Apr 03
3
summary(object, test=c("Roy", "Wilks", "Pillai", ....) AND ellipse(object, center=....)
Dear All, I would be very appreciative of your help with the following 1). I am running multivariate multiple regression through the manova() function (kindly suggested by Professor Venables) and getting two different answers for test=c("Wilks","Roy","Pillai") and tests=c("Wilks","Roy",'"Pillai") as shown below. In the
2007 Dec 06
2
How can I plot this graph
Hi, I am having trouble plotting the graph I need given the follow kind of data > xxx <- data.frame( "x"=c(1,2,3,4,5), "y1"=c(2,4,3,5,6), "y2"=c(3,4,6,3,1), "y3"=c(1,3,5,7,3), "z1"=c(1,NA,3,5,NA), "z2"=c(2,NA,4,6,NA) ) > xxx x y1 y2 y3
2008 Sep 23
1
How to draw arrows or segment lines in 3 dimensional graph
Hi I have a dataset which is like this: ID X1 Y1 Z1 X2 Y2 Z2 1 32 127 85 31.7 121 85 2 37.9 153 88 34.6 137 90 3 36.8 134 88 36.1 155 97 4 31.4 136 87 29 113 70 I would like draw the arrow or segment line for each ID from (x1, y1, z1) to (x2, y2, z2) Is there a way to do this kind of 3-D graph. Thank you -- View this message in context:
2007 Oct 17
3
how to repeat the results of a generated probabilities
hello, I want to simulate 200 times the mean of a joint probability (y1) and 200 times the mean of another joint distribution (y2), that is I'm expecting to get 200 means of y1 and 200 means of y2. y1 and y2 are probabilities that I calculate from the marginal prob. (z1 and z2 respectively) multiple by the conditional prob. (x1 and x2 respectively), which I generaterd from the binomial
2003 Aug 13
2
putting NAs at the end
I have a matrix for which each row has 12 elements that represent the xyz coordinates of 4 points. So each row of M is (x1,y1,z1,x2,y2,z2,x3,y3,z3,x4,y4,z4). Some points have NA as z values. I want another matrix to be the same as M but with the coordinates of those points with z=NA placed last. For ezample if z1=NA then the new matrix row should be (x2,y2,z2,x3,y3,z3,x4,y4,z4,x1,y1,z1)
2004 Sep 22
3
loops: pasting indexes in variables names
I cannot figure out how, using R, I can paste indexes or characters to the variable names which are used within loops. I will explain this with a simple example: Immagine I have a huge series of variables, each one taken two times, say x1 x2 y1 y2 z1 z2..... Now, immagine that I want to compute a variable from the difference of each couple, say dx=x1-x2, dy=y1-y2, dz=z1-z2... In Stata, for
2017 Jun 25
2
Writing my 3D plot function
Hi all,I had a question last week on asking for a function that will help me draw three different circles on x,y,z axis based on polar coordinates (Each X,Y,Z circle are coming from three independent measurements of 1-360 polar coordinates). It turned out that there ?is no such function in R and thus I am trying to write my own piece of code that hopefully I will be able to share. I have spent
2017 Jun 25
0
Writing my 3D plot function
Please look at what I see in your code below (run-on code mush) to understand part of why it is important for you to send your email as plain text as the Posting Guide indicates. You might find [1] helpful. [1] https://wiki.openstack.org/wiki/MailingListEtiquette -- Sent from my phone. Please excuse my brevity. On June 25, 2017 2:42:26 PM EDT, Alaios via R-help <r-help at r-project.org>
2008 Mar 19
1
betabinomial model
Hi, can anyone help me fit betabinomial model to the following dataset where each iD is a cluster in itself , if i use package aod 's betabinom model it gives an estimate of zero to phi(the correlation coeficient ) and if i fix it to the anova type estimate obtained from icc( in package aod) then it says system is exactly singular. And when i try to fit my loglikelihood by
2012 Apr 07
1
Systemfit with structural equations and cross equation parameter interaction
Hi there, I want to estimate simultaneous equation model with panel data. The model looks as follows Y1=a0+a1*X1+a2*X2 Y2=b0+b1*X2+b2*X1 X1=Z1-(Y1/a1) X2=Z2-(Y2/b1) I In this model Y1, Y2, X1 and X2 are endogenous variables; Z1, Z2 are exogenous variables and a0, a1, a2, b0, b1 and b2 are parameters. Could any one please help me how to estimate this model in R. Thanking you in anticipation
2008 Jun 24
2
persp plot
I have a set of data in the form x1, y1, z1 x1, y2, z2 ... x1, yN, zN x2, y1, z(N+1) x2, y2, z(N+2) ... x2, yN, z(2N) ...and so on... xM, yN, val(M*N) I have been trying to figure out how to get R to use this data in a persp plot. So far the only thing that I can figure out to do is to break the data file into three different files. The first file contains the x-coordinate data: x1 x2
2003 Feb 11
1
mean function on correlation matrices (PR#2540)
Full_Name: Raymond Salvador Version: R 1.6.2 OS: Windows ME Submission from: (NULL) (131.111.93.195) The mean function applied on individual components of several correlation matrices gives a wrong result (gives the first value instead of the mean). Here there is a simple example x1 <- rnorm(10,1,1) y1 <- rnorm(10,1,1) z1 <- cbind(x1,y1) w1 <- cor(z1) x2 <- rnorm(10,1,1) y2
2007 May 29
1
rgl.postscript
Hi, I am having an issue when creating a postscript file from RGL window. It seems to cut off some of the axis labels. Here is the code I am using. I created a 3D plot using RGL_0.71 with R 2.5 on Windows XP. z1<-c(5,4,1,4.5,2,3,2,1,1) z2<-c(6,8,7,7.5,5,3.5,4,1,1) z3<-c(3,2,4,7,3,4.5,6,2,3) x1<-seq(1,9) x2<-seq(1,9) x3<-seq(10,18) y1<-seq(8,0) y2<--1*y1
2013 Apr 23
2
Frustration to get help R users group
Dear R users/developers I requested help to solve the problem of formulating Multivariate Sample selection model by using Full Information Maximum Likelihood (FIML)estimation method. I could not get any response. I formulated the following code of FIML to analyse univariate sample selection problem. Would you please advise me where is my problem library (sem) library(nrmlepln) Selection
2006 Jun 29
1
Help needed understanding eval,quote,expression
I am trying to build up a quoted or character expression representing a component in a list in order to reference it indirectly. For instance, I have a list that has data I want to pull, and another list that has character vectors and/or lists of characters containing the names of the components in the first list. It seems that the way to do this is as evaluating expressions, but I seem to
2012 Apr 20
1
lines on persp plot - proper depth ordering
Hello R-help! I am trying to draw series of lines in 3d, and I am not sure how to get the depth set up properly - lines that are in front of other lines appear to be behind and vice versa. I've been doing this by first generating an empty persp plot, then adding lines via the data into trans3d followed by lines (this is probably a bad approach, but it was the first one I could get working).
2018 Feb 25
2
include
HI Jim and all, I want to put one more condition. Include col2 and col3 if they are not in col1. Here is the data mydat <- read.table(textConnection("Col1 Col2 col3 K2 X1 NA Z1 K1 K2 Z2 NA NA Z3 X1 NA Z4 Y1 W1"),header = TRUE,stringsAsFactors=FALSE) The desired out put would be Col1 Col2 col3 1 X1 0 0 2 K1 0 0 3 Y1 0 0 4 W1 0 0 6 K2 X1
2005 May 04
3
Multivariate multiple regression
I'd like to model the relationship between m responses Y1, ..., Ym and a single set of predictor variables X1, ..., Xr. Each response is assumed to follow its own regression model, and the error terms in each model can be correlated. My understanding is that although lm() handles vector Y's on the left-hand side of the model formula, it really just fits m separate lm models. What should
2013 Jul 22
1
Error with sem function df = -6
Hello all, I have an issue where I am generating data and trying to confirm the estimates using a sem. I keep getting an error about the degree of freedom being negative "Error in sem.default(ram, S = S, N = N, raw = raw, data = data, pattern.number = pattern.number, : The model has negative degrees of freedom = -6" Can someone explain this error or tell me what is wrong with my
2011 Jun 29
3
4D data acsess
Hi, I have a 4D data file from MATLAB, call it X, that I want to analyze in R. The first 3 dimensions are x y z coordinates and the forth is a value in time. If you took a sample vector in matlab it would look like vec1 = X(x1, y1, z1, :) vec2 = X( x2, y2, z2, :) this would give you all values (I have 300 of them) corresponding to this (x1,y1,z1) point of X. Now I read the MATLAB datafile 4D