similar to: Percentiles with R for a big data.frame

Dear R users, I came up to a problem by taking means (or other summary statistics) of a big dataframe. Suppose we do have a dataframe: ID V1 V2 V3 V4 ........................ V71 1 6 5 3 2 ........................ 3 2 3 2 2 1 ........................ 1 3 6 5 3 2 ........................ 3 4 12 15 3 2 ........................ 100

Hey R users, suppose we have data: [1] 2010.12.26 00:00:52 688,88 11,69 43,00 [2] 11,69 43,00 [3] 11,69 43,00 [4] 11,69 43,00 [5] 11,69 43,00 [6] 11,69 43,00 [7] 11,69 43,00 [8] 11,69 43,00 [9] 11,69 43,00 [10] 11,69 43,00 [11] 11,69 43,00 [12] 11,69 43,00 [13] 11,69 43,00 [14] 11,69 43,00 [15] 11,69

Dear R users, First of all I would like to thank all of you who replayed to my previous questions and problems. Thank you a lot for being great and helpful community. I highly appreciate your suggestions and ideas even if I do not respond after my question! But it means that your help was exactly what I needed. Thank you again! Now the following question I need help: Suppose I do have a

Dear R users, Could you share your knowledge on following problem: Suppose we have dataframe: ID TIME Data1 Data2 Data3 ........... Data700 1. 2013-01-01 00:00:00 34 53 66 ............ 55 2. 2013-01-01 00:00:01 333 4 5 ............ 50 3. 2013-01-01 00:00:02 and so

Hola, Please, mira si esta vez funciona: #---------------------------------------------- ID <- c(1, 2, 3, 4, 5, 6, 7, 1, 2, 3, 8, 9, 10, 11, 12, 1, 2, 3, 4, 5, 6, 1, 2, 6, 8, 12, 7, 15, 16, 17, 18, 19, 20, 1, 21, 22, 19 ) Year <- c (1, 1, 1, 1, 1, 1, 1, 2, 2, 2, 2, 2, 2, 2, 2, 3, 3, 3, 3, 3, 3, 4, 4, 4, 4, 4, 5, 5, 5, 5, 5, 5, 5, 5, 6, 6, 6) df <- data.frame (ID, Year) df ID <- c(1,

Hola, Antes de nada, muchas gracias por tu ayuda. El código se ha acercado bastante, pero no termina de funcionar porque considera cada captura de un individuo como años consecutivos aunque haya pasado más tiempo entre ellos. Por ejemplo el individuo 4 es capturado por primera vez el año 1 y por segunda vez el año 3, por lo que debería de ser renombrado ya que en este ejemplo en concreto

Dear List, I have some discrete data and want to calculate the percentiles and the percentile ranks for each of the unique scores. I can calculate the percentiles with quantile(). I know that "ecdf" can be used to calculate the empirical cumulative distribution. However, I don't know how to exact the cumulative probabilities for each unique element. The requirement is similar

Hi folks, I am having trouble accessing sub-functions when the main function is stored in an array. For example, the following test code works fine: fcns = c(abs, sqrt) fcns[[1]](-2) fcns[[2]](2) However, when I try to access sub-functions declared within list() in a function, this only works directly. When I try to access these within an array only the first declared sub-function is run.

Hello, I'm trying to get percentiles (PERCENTRANK for excel users) by factor in the following data.frame: myExample <- data.frame(Ret=seq(-2, 2.5, by=0.5),PE=seq(10,19),Sectors=rep(c("Financial","Industrial"),5)) myExample <- na.omit(myExample) Thanks to Patrick I I managed to put together the following lines which does it for the "Ret" column: myecdf

Hi All, I am looking at applications of percentiles to time sequenced data. I had just been using the quantile function to get percentiles over various periods, but am more interested in if there is an accepted (and/or R-implemented) method to apply weighting to the data so as to weigh recent data more heavily. I wrote the following function, but it seems quite inefficient, and not really very

Hola a todos, Quería preguntar si alguno sabe como puedo identificar registros con un mismo ID en el tiempo, pero que hacer referencia a objetos o individuos diferentes. En mi caso en particular estoy estudiando un animal que tiene una vida media cercana 2 años, y tengo una serie longitudinal de 25 años. El problema es que durante el muestreo en algunos casos durante la recoleccion de los datos,

I was hoping to calculate the percentile for each date. So group all of one date together, calculating the value of the 2.5 and 97.5 percentile. -- View this message in context: http://r.789695.n4.nabble.com/Calculating-percentiles-for-multiple-dates-tp4638183p4638378.html Sent from the R help mailing list archive at Nabble.com.

Dear R users, I use: mapImageData<- get_map(source="google", c(lon=21, lat=57), zoom=6, maptype="terrain") to get ggmapTemp.png file in the directory. The problem is - some city and park names overlay with my data points I want to plot on this map. Is there a way to get the map without city, country and park names? I get this using maptype="satellite", but I

Hi All: I am working with a dataset on Arsenic toxicity, and I am trying to calculate the 20th, 40th, 60th, 80th, and highest percentiles for a variable, dietary Moisture (variable name dMoist). The inbuilt function quantile(dMoist) would print 0, 25th, 50th, 75th, and 100th percentile. Does there exist a function that can calculate xth percentile (where x = 10th, 20th, ... etc) values?

Hi, I am using the package "demography" from Rob Hyndman for the Lee-Carter-Model. It is an amazing powerful tool but I am struggling with one issue: I want to compute different percentiles of the survival probability distribution derived from the Lee-Carter-Forecast (e.g. the 50%tile, 60%tile, 75%tile and 99%tile) for each of the next 10 years. Is there any possibility to retrieve

Hi there! Still struggling to translate Matlab code into R's tsDyn package. Here is my question: Is there in R an equivalent function to Matlab's prctile()? To the moment I thought it was quantile(), but I just realized I was wrong. The definition of the Matlab function: prctile Percentiles of a sample SyntaxY = prctile(X,p) Description Y = prctile(X,p) calculates a value that is

On Tue, 2018-05-29 at 21:00 +0100, Rowland Penny via samba wrote: > On Tue, 29 May 2018 15:50:44 -0400 > lingpanda101 via samba <samba at lists.samba.org> wrote: > > > Hello, > > > > I'm developing a script to create a user and pass along all the > > necessary unix attributes required. I'm successful except when I go > > to increment

Hello R users, For the last few days I am struggling with the following task: my data.frame: A1 A2 A3 B1 B2 B3 58.81 53.292 54.501 13.013 17.39 19.407 56.02 56.251 54.033 20.099 13.15 10.411 55.376 53.099 57.625 13.396 21.031 13.22 58.584 53.194 54.218 13.038 16.854 19.289 55.7 55.921 53.847 19.942 13.153 9.828 55.093 52.934

Hi all, I'm just getting started with R and I would appreciate some help. I'm having trouble creating a boxplot with whiskers at the 95th and 5th percentiles instead of at 1.5 * IQR. I have read the relevant documentation, and checked existing mails on this topic. I found a small modification that should work : https://stat.ethz.ch/pipermail/r-help/2001-November/016817.html and tried to

Dear Researchers, I have a data.frame with 2 columns like this: mydf <- data.frame(value=c(1,2,3,4,5),ID=c("Area_1","Area_2","Area_3","Area_4","Area_5")) > mydf value ID 1 1 Area_1 2 2 Area_2 3 3 Area_3 4 4 Area_4 5 5 Area_5 I need to convert the *ID *in the following version > mydf value ID newID