similar to: How to plot this simple step function?

I work for a school dist, and I am having a bit of trouble with the "Student Server" We have about 3000 students all with their own accounts. I had the samba server setup to share their home directories but their home directories are the same as their login name. So jamie.mcparland would be an example of a share name. But in Win 9X it gets truncated to jamie.mcparla then we get the error

Dear all, i try to plot with ggplot2. Therefor I have an matrix with 3 colums. With cbind I add an additional column called "col". I need this column "col" because in a later step and want to specify here some plot details which I will get from another analysis If I want to plot with this code, I have the problem that the legend is wrong. Blue changed to green and green to

I doubt your actual file looks like the mess that made it to my email software (below) because you posted HTML-format email. Read the Posting Guide, and in particular figure out how to send plain text email. You might try the "anytime" contributed package, though I suspect it too will choke on your mess. Otherwise, that will pretty much leave only a brute-force series of regular

Hi,? I have a data set with various date formats in one column and not sure how to unify it.Here is a few formats: 02091702/22/170221201703/17/160015-08-239/2/1500170806May-2-201522-March-2014 I tried parse_date_time from lubridate library but it failed.Thanks so much.?Best,Farnoosh [[alternative HTML version deleted]]

I got a .dta extension file by e-mail, but I can't save it in my computer and open it in R. How can I do it? [[alternative HTML version deleted]]

Thanks Jeff. This is a nice way of solving this problem. What about the cases with 0015-02-21?Many thanks.?Best,Farnoosh On Wednesday, June 28, 2017 10:49 PM, Jeff Newmiller <jdnewmil at dcn.davis.ca.us> wrote: I doubt your actual file looks like the mess that made it to my email software (below) because you posted HTML-format email. Read the Posting Guide, and in particular

Hi all, New user here - I include the following command in the prompt read.csv("document.csv", header = TRUE ) and the output shows up. But when I include the following command summary(data) I get the following message "Error in object[[i]] : object of type 'closure' is not subsettable" Can someone please advise why R is not reading my data? Thanks

Hello, I'm having problems working with date values in POSIXct format. Here is what I got (eg.lig attached): x <- read.table("eg.txt", sep = ',', col.names=c("ok","time","secs","lig")) # it gives time as factor z <- cbind(x,colsplit(x$time, split="\\s", names=c("date", "clock")))

Hi Experts, I am newbie in R. Could you please share your idea to create a stack with no value or zero value? Nrow=1,Ncol=1, Ncell=1, I aim to work with looping, I want to make a first layer with zero values to add other layers further. Thanks. Best Regards, ..................Anup KhanalNorwegian Institute of science and Technology (NTNU)Trondheim, NorwayMob:(+47) 45174313

Dear All, Suppose I have a dataframe like this with many thousands rows all with different names: data.frame(gene=c("a","b","c","d","c","d","c","f"),value=c(20,300,48,55,9,2,100,200)), I want to set column "gene" as row.names, but there are duplicates (c, d), which I want to transform into this as row names:

Thanks. I think nabble is good for programming questions. Bear with me if I'm incorrect. Data: Genomics SNP information Goal: I need to add Chromosome and SNP position to the data frame I'm using through apply. I'd like to add new column from text processed through apply function. For example: 10:60523:T:G (Column 2) CHR: 10 Position: 60523 Dataset: chr rs ps n_miss allele1

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I have a matrix like this Name 1 2 3 4 5 NM_001039514 1.033557047 0.7469879518 0.9004524887 0.8613861386 0.7952499048 NM_001039723 1.0759493671 1.2315789474 0.8666666667 1.1142857143 0.9428011471 NM_001042605 0.9897435897 0.8870431894

Dear All I have a lot of files in a directory as follows: "02-03.txt" "03-04.txt" "04-05.txt" "05-06.txt" "06-07.txt" "07-08.txt" "08-09.txt" "09-10.txt" "G0.txt" "G1.txt" "raw_ped.txt" .......................... I want to read them into different objects according

Hello R people, I have a data file with 101 numeric variables: one variable called IDN (the individual's unique id number, which I need to retain, and which ranges from 1000 to 1320; some numbers are obviously skipped), and V1 to V100 (each has a value of 0 or 1; these 100 variables represent sequentially ordered days and whether a characteristic was present or absent--e.g., v1 is day 1 and a

I am trying to create a barplot displaying the sums of 2 columns of data grouped by a variable. the data is set up like this: "city" "n" "y" <br> mon 100 200 <br> tor 209 300 <br> edm 98 87 <br> mon 20 76 <br> tor 50 96 <br> edm 62 27 <br> the resulting plot should have city as the x-axis, 2 bars per city, 1 representing

On Tue, 19 Sep 2017 13:13:45 -0700 Jamie McParland via samba <samba at lists.samba.org> wrote: > Thanks for everyone chiming in on my problem. I really do appreciate > it. > > Just to clarify, I’m working on a share called Edwards_Public. I’m > trying to get it so the members of the AD group called > do_superintendent are the only people able to read and write any >

On Wed, 28 Feb 2018, Stephen HonKit Wong wrote: > Dear All, > Suppose I have a dataframe like this with many thousands rows all with > different names: > data.frame(gene=c("a","b","c","d","c","d","c","f"),value=c(20,300,48,55,9,2,100,200)), > > I want to set column "gene" as row.names, but

Comments interspersed, and some code at the end. On Mon, 5 Mar 2018, Sariya, Sanjeev wrote: > Thanks. I think nabble is good for programming questions. Bear with me > if I'm incorrect. You may have found R-help archives at Nabble, but R-help has nothing to do with Nabble. > > Data: Genomics SNP information I know almost nothing about using R for genomics. > Goal: I need

Hi there, I wrote a function that wraps MASS::boxcox as: bc <- function(vec) { lam <- boxcox(lm(vec ~ 1)) lam <- lam$x[which.max(lam$y)] (vec^lam - 1)/lam } When I invoke it as: > x <- runif(20) > bc(x) Error in eval(predvars, data, env) : object 'vec' not found I have googled, and rewrote the above function as: bc <- function(vec) { dat <<-