Displaying 20 results from an estimated 300 matches similar to: "Histogram plot spacing"
2008 Aug 05
1
xyplot key issue - line colors
I have a problem regarding the colors assigned to the lines in the key
to an xy plot. I specify the plot like this:
xyplot(numbers~sqrt(breaks)|moltype+disttype, groups = type, data = alldata,
layout = c(3,2), type = "l" , lwd = 2, col = c("gray", "skyblue"),
key = simpleKey(levels(alldata$type), points = FALSE, lines = TRUE,
columns = 2, lwd = 2,
2014 May 11
2
questions about process_limit
Hello all!
# dovecot --version
2.1.17
Sometimes I have this in the logfile:
May 11 16:55:52 master: Warning: service(imap-login): process_limit (100) reached, client connections are being dropped
May 11 17:35:03 master: Warning: service(imap-login): process_limit (100) reached, client connections are being dropped
May 11 17:36:27 master: Warning: service(imap-login): process_limit (100)
2018 Jan 22
1
what does the within component of varcomp (ape library) output indicate?
I am trying to use varcomp to obtain the variance partitioning across
different nested levels of random effects (say x,y and z). I get the
three variance components (for each of my along with an additional one
called 'within' from varcomp output. I am using the 'scale total
variance to 1' option and though the within component is small, it
does form a part of what explains the
2017 Aug 08
2
how to extract individual values from varcomp?
Hello,
I am trying to use varcomp to decompose the variance across multiple
nested levels on a lme object. I am able to successfully do this and
when I view the varcomp object I can see the individual values /
estimates for the variance at different levels.
However, I want to be able to extract each of them separately, as I
need to build a confidence interval using bootstrapping on the sample
2012 May 14
1
Extract Variance Components
Hi,
I'm still having problems putting the variance components of my model in to
a data frame, it is a continuation of this discussion,
http://r.789695.n4.nabble.com/ANOVA-problem-td4609062.html, but now focussed
on the problem of extracting variance components. I have got my mixed
effects model now
/narrow$line<-as.factor(narrow$line)
rg.lmer <- lapply(split(narrow,
2003 Nov 27
2
lme v. aov?
I am trying to understand better an analysis mean RT in various
conditions in a within subjects design with the overall mean RT /
subject as one of the factors. LME seems to be the right way to do
this. using something like m<- lme(rt~ a *b *subjectRT, random=
~1|subject) and then anova(m,type = "marginal"). My understanding is
that lme is an easy interface for dummy coding
2017 Aug 08
0
how to extract individual values from varcomp?
Hi
try
str(varcompobject)
to see structure of this object. You can extract parts by standard R means.
Cheers
Petr
> -----Original Message-----
> From: R-help [mailto:r-help-bounces at r-project.org] On Behalf Of Sharada
> Ramadass
> Sent: Tuesday, August 8, 2017 3:33 PM
> To: r-help at r-project.org
> Subject: [R] how to extract individual values from varcomp?
>
>
1999 Apr 21
0
varcomp?
Hello R experts,
I haven't found anything like the S function 'varcomp' as described in
W.N. Venables & B.D. Ripley's 'Modern Applied Statistics ...' for R;
does something comparable exist for R, or is planned for future
releases?
More generally, are there libraries with post-anova test procedures,
like Student-Newman-Keuls? Or do those of you who frequently use
2008 Jan 28
0
(no subject)
Hi all
I am trying to generate a normal unbalanced data to estimate the coefficients of LM, LMM, GLM, and GLMM and their standard errors. Also, I am trying to estimate the variance components and their standard errors. Further, I am trying to use the likelihood ratio test to test H0: sigma^2_b = 0 (random effects variance component), and the t-test to test H0:mu=0 (intercept of the model Yij = mu
2012 Jan 30
1
Linear Mixed Model set-up
Hello,
I have some data covering contaminant concentrations in fish over a time
period of ~35 years. Each year, multiple samples of fish were taken (with
varying sample sizes each year). Ultimately, I want an estimation of the
variance between years, and the variance within years + random effects. I
used a linear mixed model to estimate these variances, but after reading a
number of different
2006 Aug 10
5
Variance Components in R
Hi,
I'm trying to fit a model using variance components in R, but if very
new on it, so I'm asking for your help.
I have imported the SPSS database onto R, but I don't know how to
convert the commands... the SPSS commands I'm trying to convert are:
VARCOMP
RATING BY CHAIN SECTOR RESP ASPECT ITEM
/RANDOM = CHAIN SECTOR RESP ASPECT ITEM
/METHOD = MINQUE (1)
/DESIGN
2005 Oct 27
2
Extracting Variance Components
Dear List,
Is there a way to extract variance components from lmeObjects or
summary.lme objects without using intervals()? For my purposes I don't
need the confidence intervals which I'm obtaining using parametric
bootstrap.
Thanks,
Mike
[[alternative HTML version deleted]]
2006 Jan 30
3
handling NA by mean replacement
Hello
I am sorry fuch such a stupid question. Suppose I have a table of data having a
lot of NAs and I want to replace those NAs by the mean of the column before NA
replacement. How is it possible to do that efficiently ?
Thanks in advance,
Julie
--
Julie Bernauer
Yeast Structural Genomics
http://www.genomics.eu.org
2001 Oct 18
1
tapply problem
Hello everybody.
I have a question that has stumped me and the usual "apply" tricks
don't seem to work. I run a course where each student's performance
is marked by one or more assessors.
I have a data frame containing students' names, assessors' names and
their marks, arranged as follows:
ID student assessor Q1A Q1B Q1C Q2A Q2B Q3
1 2152833
2009 Jul 18
1
apply/return and reuse
Hi,
Is it possible to make something like the following code actually
work? My goal in this example would be that I'd see results like
1 10000 10100
2 10100 10200
3 10200 10300
4 10300 10400
In real usage the function would obviously do a lot more work, but the
question I cannot answer myself yet is whether the apply can return a
value from the work on one row and then use
2019 Jun 27
4
Reverse DNS
Hai Praveen,
> -----Oorspronkelijk bericht-----
> Van: Praveen Ghimire [mailto:PGhimire at sundata.com.au]
> Verzonden: donderdag 27 juni 2019 13:46
> Aan: samba at lists.samba.org
> CC: 'L.P.H. van Belle'
> Onderwerp: RE: [Samba] Reverse DNS
>
> Hi Guys,
>
> Thank you for your emails. Here is the info
>
> /etc/apparmor.d/local/usr.sbin.dhcp
>
2011 Jun 25
1
Quota (and disk usage) is incorrectly reported on nfs client mounting XFS filesystem
hi all,
I hope you can help me with a strange quota/nfs/XFS behavior...
I'm using Centos 5.6 on both a nfs server and client. Both are
64-bit, and using a recent kernel:
NFS server:
Linux fs2.priv 2.6.18-238.12.1.el5 #1 SMP Tue May 31 13:22:04 EDT 2011 x86_64 x86_64 x86_64 GNU/Linux
NFS client:
Linux nx8.priv 2.6.18-238.12.1.el5 #1 SMP Tue May 31 13:22:04 EDT 2011 x86_64 x86_64 x86_64
2007 Aug 17
0
superposing lattice plots
Hello everyone,
I am sorry if this has already been asked but I can't find it. I want
to superpose two lattice plots, namely a levelplot and a contourplot
of two different variables with the same x-y scale. I found
information about panel.superpose but it does not seem to correspond
to what I want (I have two different variables, not groups of the
same variable)
How can I do this?
2004 May 04
2
Superposing data on boxplot
Hi folks,
I have a vaiable Y and an associated factor Z at several (13)
levels.
boxplot(Y~Z)
produces a nice array of boxplots, one for each level of Z,
and each duly labaelled with its level of Z.
I would like to superpose on each boxplot the actual data
points which it represents, i.e. do something conceptually
(though not in real R) expressed as
points(Y~Z)
or
points(Z,Y)
It can
2004 Jul 08
7
Problem with the grep function
Let me present to you my problem :
I have a character vector x and I would like to obtain the indices of the
elements of
this vector that yielded exactly a match.
For example, x=nom, pattern="b", I would to obtain 2 because "b" is on the
second position.
First program :
nom <- c("a","b","ab")
grep("b",nom)
2 3
Then I try the