similar to: How to fit a linear model to data by minimizing the mean absolute percent error?

Peter You question is difficult to answer without more information about the distribution of your residuals. Different residual patterns call for different transformations to stabilize the variance. One very common form of heterocedasticity is increasing variance with increasing values of an independent predictor, i.e. the variance of the residuals of y=x increase as x increases. In this case a

Dear All My data consists in 96 groups, each one with 10 observations. Levene's test suggests that the variances are not equal, and therefore I have tried to apply the classical transformations to have homocedasticity in order to be able to use ANOVA. Unfortunately, no transformation that I have used transforms my data into data with homocedasticity. The histogram of variances is at

Dear List, I'm trying to interpret the results of the Kruskal's Non-metric Multidimensional Scaling algorithm (isoMDS, MASS package). The 'goodness of fit' is reported as "The final stress achieved (in percent)". What does this mean exactly? I've tried to google for an answer but I've not come up with a definitive answer. Regards, Dieter -- Dieter Vanderelst

I have searched this forum with keywords contour and percent, it only give one irrelevent result. My problems is how to plot contour in percent. In my figure, I have use kde2d to generate density of an array with two dimension point. Using image and contour could plot it. But the line contour generated represent absolute value of population, not how much pecent point within this cycle. So, i there

Hello, I am using the mail_crypt plugin with Dovecot 2.3 and have issues trying to use a mail crypt private password which contains a percent "%" character as you can see below: $ doveadm -o plugin/mail_crypt_private_password=SomethingWith\%Percent mailbox cryptokey generate -u email at domain.tld -URf doveadm(email at domain.tld): Error: Failed to expand plugin setting

What is the easiest way to calculate a percent rank “by” an index key? Foe example, I have a dataset with 3 fields: Year, State, Income , I wish to calculate the rank, by year, by state. I also wish to calculate the “percent rank”, where I define percent rank as rank/n. (n is the number of numeric data points within each date-state grouping.) This is what I am

Every once in awhile I see this horizontal percent bar flash up on the screen then disappear. What is that? CentOS 7.1, ? kde. -wes

Hi All - I have been using the windrose function found in the circular library to create great looking windroses.  But the dashed, circular percent interval lines that indicate the frequency at which each "pedal" occurs are not evenly spaced (the corresponding parameter is "cir.ind").  That is, the 5% interval closest to the heart of the windrose is wider than the 5-10 chuck,

Dear all, I'd like to get a percentage variable based on a group, but without creating a new data frame. For example: data(iris) iris$percent <-unlist(tapply(iris$Sepal.Length,iris$Species,function(x) x/sum(x, na.rm=TRUE))) This does not work, I should have only three standard values, respectively for setosa, versicolor, and virginica. How can I do this? MANY THANKS, Karine

How would I find the Percent of FuelTypeNum within the Band given AvailableMW? example: type 1 is 1% of PB0 type 2 is 54% of PB0 type 4 is 4% of PB0 type 5 is 42% of PB0 Note: the Bands and fuel types are not always constant. Data: FuelTypeNum Bands AvailableMW AvailableMWNewFormat 1 PB0 185319 185.319 2 PB0 18352000 18352 4 PB0 1338785 1338.785 5 PB0 14189756 14189.756 2 PB1

Hi I am a new fan of R after getting mad with the graphical functional in SPSS. I have been able to create a nice looking Kaplan Meyer graph using Survplot function. However I have difficulties in turning the y axis to percent instead of the default 0-1 scale. Further I have tried the function yaxt="n" without any results. Any help in this matter will be appreciated. The code is

Hi I am scratching my head on this not being a ruby person... I am turning my kickstart files into templates, but am having issues with percent signs in free form text. This returns a syntax error: %post OK, fine , let me escape it: %%post No error, but the end result is %%post Not quite what I wanted I''m missing something blindingly obvious - can someone point me to it? :-)

Dear List, I am trying include a lunar variable in a model and am having problems figuring out the correct way to include it. I want to convert the percent lunar illumination (fraction of moon showing) to a combination of sin and cos variables to account for the periodic nature of the lunar cycle. Would someone let me know if I am doing this correctly? I have included the first 20 variables

Hi, I am currently trying to do a GLMM on a dataset with percent cover of seagrass (dep. var) and a suite of explanatory variables including algal (AC) and epiphyte cover (EC), rainfall, temperature and sunshine hours. M2=glmer(SG~AC+EC+TP+SS+RF+(1|Location/fSi/fTr), family=binomial,data=data,nAGQ=1) As the dependent variable is percent cover, I used a binomial error structure. I also have a

Hello, I would like to annotate a graph with the expression 'alpha = 5%' (the alpha should be displayed as the greek letter). I tried > text(1,1,expression(alpha == 5%)) which gives a syntax error. escaping the percent sign (\%) or doubling (%%) does not help. What do I do? Thanks, Martin Keller-Ressel -- Martin Keller-Ressel Research Unit of Financial and Actuarial

R version: 2.7.0 Running on: WinXP I am trying to model damage from fire losses (given that the loss occurred). Since I have the individual insured amounts, rather than sampling dollar damage from a continuous distribution ranging from 0 to infinity, I want to sample from a percent damage distribution from 0-100%. One obvious solution is to use runif(n, min=0, max=1), but this does not seem to be

Hi Say I have some data, two columns in a table being a binary outcome plus a predictor and I want to plot a graph that shows the percentage positives of the binary outcome within bands of the predictor, e.g. Outcome predictor 0 1 1 2 1 2 0 3 0 3 0

Hello all, I'm new in R, and I have a data-frame like this (dput information below): Specie Fooditem Occurrence Volume 1 Schizodon vegetal 1 0.05 2 Schizodon sediment 1 0.60 3 Schizodon vegetal 1 0.15 4 Schizodon alga 1 0.05 5 Schizodon sediment 1 0.90 6 Schizodon

I was writing Rd documentation for a new package when I came across this issue. Here's the smallest example: > library(tools) > cat("\\examples{x <- '<%=rnorm(1)%>'}\n",file=file.path(tempdir(),'test.Rd')) > readLines(file.path(tempdir(),'test.Rd')) [1] "\\examples{x <- '<%=rnorm(1)%>'}" >

??????? Original Message ??????? On Tuesday, July 2, 2019 6:21 PM, Aki Tuomi <aki.tuomi at open-xchange.com> wrote: > Hi, you need to escape % with %%. We are aware of a bug affecting when % comes in from some field via userdb, and we are looking into how to fix this. Hi Aki, Thank you very much for your very fast answer. I will then simply double the percent character as workaround