Displaying 20 results from an estimated 9000 matches similar to: "How to plot multiple datasets"
2011 Jan 19
2
Reshape
Hi - I'm up against a complicated reshape problem. I have data of the form
X1,Y1,hr1,hr2,hr3
X1,Y2,hr1,hr2,hr3
X1,Y3,hr1,hr2,hr3
X2,Y1,hr1,hr2,hr3
X2,Y2,hr1,hr2,hr3
X2,Y3,hr1,hr2,hr3
where X and Y are factors and the hr(1,2,3) are values. I need it as
,X1, X2
Y1,hr1,hr1
Y1,hr2,hr2
Y1,hr3,hr3
Y2,hr1,hr1
Y2,hr2,hr2
Y2,hr3,hr3
..,
Any hints? I've been at it for hours.
p
--
View
2006 Jun 21
4
help on ploting various lines
Dear All,
I tried to plot a variety of lines(curves) on same figure. What I did is,
plot(x=x1,y=y1)
lines(x=x2,y=y2)
lines(x=x3,y=y3)
...
In my data, the maximum of y1 is much smaller than those maximums of other y vectors. So, in the figure I got, there are some curves which are not complete, I mean, they were cut off at the maximum of y1 at the y axis. Could anybody point out some right
2010 Feb 28
4
Reducing a matrix
I wish to rearrange the matrix, df, such that all there are not repeated x values. Particularly, for each value of x that is reated, the corresponded y value should fall under the appropriate column. For example, the x value 3 appears 4 times under the different columns of y, i.e. y1,y2,y3,y4. The output should be such that for the lone value of 3 selected for x, the corresponding row entries
2005 Jan 21
2
Selecting a subplot of pairs
Hello,
I'm trying to plot a set of 3 dependant variables (y) against 4
predictors (x) in a matrix-like plot, sharing x- an y-axis for all the
plot on the same column/line :
y1/x1 y1/x2 y1/x3 y1/x4
y2/x1 y2/x2 y2/x3 y2/x4
y3/x1 y3/x2 y3/x3 y3/x4
In fact, this plot is a rectangular selection of the result of pairs(),
limited to the relations between x's and y's
2008 Dec 29
4
Merge or combine data frames with missing columns
Hi R-experts,
suppose I have a list with containing data frame elements:
[[1]]
(Intercept) y1 y2 y3 y4
-6.64 0.761 0.383 0.775 0.163
[[2]]
(Intercept) y2 y3
-3.858 0.854 0.834
Now I want to put them into ONE dataframe like this:
(Intercept) y1
2010 Nov 19
3
assigment
Hello R Users,
I have vectors
x <- c("a2","b7","c8")
y1 <- c(1,2,3,2)
y2 <- c(4,2,7,5,4,3,8)
y3 <- c(1:10)
and I want to assign values form vector y1 to a new variable which
name comes from the 1st value of the vector x etc. How to do it using
only vector x. As a result I should have:
a2 <- y1
b7 <- y2
c8 <- y3
More general problem: I have 2 txt
2011 Aug 15
1
update() ignores object
Hi all,
I'm extracting the name of the term in a regression model that
dropterm specifies as the least significant one, and I'm assigning
this name to an object. However, when I use update(), it ignores this
object. Is there a way I can make it not ignore it? A reproducible
example is below:
> lm(x1~1+y1*y2+y3+y4,data=anscombe)->my.lm
>
2010 Jul 12
3
Continuing on with a loop when there's a failure
Hi R sages,
Here is my latest problem. Consider the following toy example:
x <- read.table(textConnection("y1 y2 y3 x1 x2
indv.1 bagels donuts bagels 4 6
indv.2 donuts donuts donuts 5 1
indv.3 donuts donuts donuts 1 10
indv.4 donuts donuts donuts 10 9
indv.5 bagels donuts bagels 0 2
indv.6 bagels donuts bagels 2 9
indv.7 bagels donuts bagels 8 5
indv.8 bagels donuts bagels 4 1
indv.9
2004 Feb 26
2
Structural Equation Model
Hello all!
I want to estimate parameters in a MIMIC model. I have one latent
variable (ksi), four reflexive indicators (y1, y2, y3 and y4) and four
formative indicators (x1, x2, x3, x4). Is there a way to do it in R? I
know there is the SEM library, but it seems not to be possible to
specify formative indicators, that is, observed exogenous variables
which causes the latent variable.
Thanks,
2008 Aug 13
1
summary.manova rank deficiency error + data
Dear R-users;
Previously I posted a question about the problem of rank deficiency in
summary.manova. As somebody suggested, I'm attaching a small part of
the data set.
#***************************************************
"test" <-
structure(.Data = list(structure(.Data = c(rep(1,3),rep(2,18),rep(3,10)),
levels = c("1", "2", "3"),
class =
2007 Dec 02
3
Help with a Loop
I am having trouble getting a loop to work for the following problem. Any
help would be much appreciated. Thanks.
I need to find the slope and intercept from the linear regression of Drug
Level on Day by Participant. There are a total of 37 Participants. I need to
store the Participant, Label, Slope, and Intercept in a new data frame.
This data is ordered by Participant number 37 total
2005 Dec 08
2
how to change a dataframe with characters to a numeric matrix?
hi netters,
i have a dataframe TEST like this:
Y1 Y2 Y3
X1 4 7 8
X2 6 2 Z
X3 8 0 1
i would like to change it to a numeric matrix, replacing "Z" with NA
Y1 Y2 Y3
X1 4 7 8
X2 6 2 NA
X3 8 0 1
i've tried the function data.matrix but it didn't work. is there any easy
way to do this?
thanks a lot!
2004 Dec 09
4
Scatterplot question
Dear list members,
I have a probably simple question concerning scatterplots: I want to
draw a plot with one X but several Y columns, so that every group
of samples gets a different symbol. My table looks like this:
X Y1 Y2 Y3
1 1
2 3
3 5
4 7
5 9
6 11
7 13
8 15
Simple in Excel or StarOffice, but how do I do it in R?
Thanks a lot
Judith
2010 Oct 21
1
All other variables in upper scope arg for stepAIC
Hi - I am trying to substitute for "the_other_y" in the code below. I want
y2 and y3 to be there when i is 1, y1 and y3 to be there when i is 2 and y1
and y2 to be there when i is 3. I'm sure it's to do with what format the
data should be in and I've tried alldata[,-i], but it fits all the columns
of alldata except i rather than each column one at a time. I've tried
2011 May 12
2
group length
Hi
I have four groups
y1=c(1.214,1.180,1.199)
y2=c(1.614,1.710,1.867,1.479)
y3=c(1.361,1.270,1.375,1.299)
y4=c(1.459,1.335)
Is there a function that can give me the length for each, like the made up
example below?
>function(length(y1:y2)
[1] 3 4 4 2
[[alternative HTML version deleted]]
2010 Feb 25
2
Rearranging entries in a matrix
I have a matrix, called data. I used the code below to rearrange the data such that the first column remains the same, but the y value falls under either columns 2, 3 or 4, depending on the value of z. If z=1 for example, then the value of y will fall under column 2, if z=2, the value of y falls under column 3, and so on.
data
x y z
[1,] 50 13 1
[2,] 14 8 2
[3,] 3 7 3
[4,] 4 16 1
[5,] 6
2017 Jun 25
2
Writing my 3D plot function
Hi all,I had a question last week on asking for a function that will help me draw three different circles on x,y,z axis based on polar coordinates (Each X,Y,Z circle are coming from three independent measurements of 1-360 polar coordinates). It turned out that there ?is no such function in R and thus I am trying to write my own piece of code that hopefully I will be able to share. I have spent
2007 Dec 06
2
How can I plot this graph
Hi,
I am having trouble plotting the graph I need given the follow kind of data
> xxx <- data.frame(
"x"=c(1,2,3,4,5),
"y1"=c(2,4,3,5,6),
"y2"=c(3,4,6,3,1),
"y3"=c(1,3,5,7,3),
"z1"=c(1,NA,3,5,NA),
"z2"=c(2,NA,4,6,NA) )
> xxx
x y1 y2 y3
2009 Oct 28
5
re gression with multiple dependent variables?
i have a series of regressions i need to run where everything is the same
except for the dependent variable, e.g.:
lm(y1 ~ x1+x2+x3+x4+x5, data=data)
lm(y2 ~ x1+x2+x3+x4+x5, data=data)
lm(y3 ~ x1+x2+x3+x4+x5, data=data)
is it possible to run all these regs with a single command? given that the
bulk of the work for linear regressions is inverting a matrix that depends
only on the independent
2010 Jun 02
4
Draw text with a box surround in plot.
text() can draw text on a plot.
Do we have a way/function to draw text with a box surround it?
Thanks,
-james