similar to: thanks -- Re: syntax for identifying more than one

Dear R users, I have issues regarding latex() from Hmisc and numSummary() from Rcmdr. Here's an example: > library(Rcmdr) > data(Angell, package="car") > numSummary(Angell[,"hetero"], statistics=c("mean", "sd", "quantiles"), quantiles=c( 0,.25,.5,.75,1 )) > .numSummary <- popOutput() > latex(as.table(.numSummary$table),

Hello everyone, I have several problems with exporting to LaTeX the output of numSummary() from the abind package. > numSummary(finance[,"Cash_flow"], statistics=c("mean", "sd", "quantiles")) mean sd 0% 25% 50% 75% 100% n NA 188070.9 414771.9 -426804 26743 53866 150975.5 1871500 54 4 >

I know that my question is like a very newbie question, but at the moment I stacked with it and I need a quick solution. I need to make an overall statistical overview of various datasets, the summary() and numSummary() functions are fully sufficient. My question is, how can I export results to a spreadsheet-like file, as a .csv. For the summary() with an "x" dataset I can use this way:

Hello there, when using the function numSummary in Rcmdr and selecting more than one variable (without grouping), the grand mean across all variables is returned for each variable instead of the mean of each single variable. However, this happens only for the mean, and not for sd, quantiles and na. This is the output: > numSummary(dataset1 [,c("var1", "var2")],

Hello everyone, The thread title speaks for itself. Here's the code that worked for me: > numSummary(finance[,"Employees"], statistics=c("mean", "sd", "quantiles")) mean sd 0% 25% 50% 75% 100% n NA 11492.92 29373.14 1777 3040 4267 6553 179774 53 5 > str(numSummary(finance[,"Employees"],

Hi Every one, I have a dataframe "class" with "name", "sex", "age", "height", "Weight". if i caluclate summary statistics with the below code numSummary(class[,c("Height", "Weight")], groups=class$Name, statistics=c("mean", "sd", "quantiles"), quantiles=c(0, .25,.5,.75,1)) iam getting

I issued the following command to obtain the std dev for each month. psd<-numSummary(Sal, groups=month, statistics=c("sd")) which resulted in > psd sd n NA 1 6.930340 9367 2319 2 7.847003 10827 1008 3 5.962308 12988 404 4

I'm new using R im trying to do a tukey test, but when i see the results the p value results in NA im guessing its because i have missing values but im not sure how to fix it AnovaModel.2 <- aov(area ~ trat, data=apilados) > summary(AnovaModel.2) Df Sum Sq Mean Sq F value Pr(>F) trat 4 11847 2961.76 9.9905 1.500e-06 *** Residuals 76 22531 296.46

Hi For first question, maybe I am completely wrong but cor(swiss[,-1], swiss[,1]) should give you what you want in one step. Second question Without an example it is hard to say but maybe aggregate is the way forward. > aggregate(iris[,1:4], list(iris$Species), function (x) c(mean=mean(x), sd=sd(x))) Group.1 Sepal.Length.mean Sepal.Length.sd Sepal.Width.mean Sepal.Width.sd 1

I've submitted a new, and substantially enhanced, version (1.2-0) of the Rcmdr package to CRAN. Some highlights (from the CHANGES) file: o Added ability to import from Excel, Access or dBase files (contributed by Samir Messad, Renaud Lancelot and Matthieu Lesnoff). o Added ability to read data from the clipboard (suggested by Graham Smith). o Added "Data -> Active data

I've submitted a new, and substantially enhanced, version (1.2-0) of the Rcmdr package to CRAN. Some highlights (from the CHANGES) file: o Added ability to import from Excel, Access or dBase files (contributed by Samir Messad, Renaud Lancelot and Matthieu Lesnoff). o Added ability to read data from the clipboard (suggested by Graham Smith). o Added "Data -> Active data

Hola a tod en s, me gustaría usar solo un(os) comando(s) específico(s) de una librería pero sin cargarla entera a la manera: library(laquesea) ¿se puede hacer de alguna manera? Y saludos y gracias jm~ _______________________________ J. Miguel Marin http://www.est.uc3m.es/jmmarin Dep. of Statistics University Carlos III of Madrid Spain (E.U.)

Dear list, I have the following how-to-do it in R, questions. Suppose I have ten independent variables, and one dependent variable. I want to find the Pearson correlation of all the IVs with the DV, but not the correlation between the IVs. What I know so far, about R, that I have to type the cor () function ten times, each time requesting for a correlation between one IV and the DV. I was

i just found the following list, i wondered if anybody could add to this as i have to characterize a large data set and am new to R...the list below was so helpful....can you add to this??? Just to forestall confusion amongst those who would like to use one of the functions called "describe"... Hmisc package - describe numeric name count of observations count of missing

Dear all, I'm trying to gsub() "%" with "\%" with no obvious success. > temp1 <- c("mean", "sd", "0%", "25%", "50%", "75%", "100%") > temp1 [1] "mean" "sd" "0%" "25%" "50%" "75%" "100%" > gsub("%",

I am designing a package to analyze fire department data. I created an S4 class called CAD (short for Computer Aided Dispatch data) as part of this package that essentially extends the data.frame class. When the user initializes a CAD object, a data.frame object is broken down into seperate incident data and unit response data that are stored in separate slots. This separation is intentional

I am merging two dataframes using a relational key (incident number and incident year), but not all the records match up. I want to be able to review only the records that cannot be merged for each individual dataframe (essentially trying to select records from one dataframe using a multi-value relational key from the other dataframe). The following code shows what I am trying to do. The final

Hi, I'm really struggling with barplot I have a data.frame with 3 columns. The first column represents an "incident" type The second column represents a "month" The third column represents a "time" Code for a sample data.frame incidents <- rep(c('a','b','d','e'), each =25) months <- rep(c(1,2), each =10) times

Thanks for the tips. I did find a detailed article on how to run Icecast 1.3.x in a chroot jail at incidents.org (actually it's in Google's cache, couldn't find it on incidents.org site anymore): http://216.239.37.100/search?q=cache:8Jnwn-j8Yh4C:www.incidents.org/protect/borland.php+icecast+chroot+jail&hl=en&ie=UTF-8 It doesn't really solve the problem of running Icecast

I am trying to plot the linear fit by id of the following data (test.l): id year incidents 100 1 0 101 1 1 102 1 21 103 1 27 104 1 3 105 1 12 100 2 5 101 2 5 102 2 19 103 2 10 104 2 2 105 2 12 100 3 0 101 3 0 102 3 22 103 3 14 104