similar to: plotting and saving diagrams automatically

Hello everyone, I need some help with lists inside lists (a good way to emulate a struct)\ Assume that there is a small list called fred: fred <- list(happy = 1:10, name = "squash") and a big list called bigfred that includes fred list 5 times bigfred <- rep(fred,5) Is it possible somehow to index all these sublists(fred) inside bigfred with a more direct way like this:

I have a list of dataframes i.e. each list element is a dataframe with three columns and differing number of rows. The third column takes on only two values. I wish to split the list into two sublists based on the value of the third column of the list element.  Second issue with lists as well. I would like to reduce each of the sublist based on the range of the second column, i.e. if the range of

Dear all, I would like to ask your help concering two R lists. If I did everything should have the same structure (that means the same number of sublists, and their sublists also the same number of sublists). What would change between the two lists is the contents of each element in the lists. Could you please help me understand how I can do that in R? I would like to thank you in advance for

Hi all, I want to do this: B.list$aa= (a loop containing My.fun acting on the reults of second function on a A.list$aa)) or, overally B.list$aa = function (A.list$aa) B.list and A.list has many sublists aa, ab and.... Is there a way I can apply the function and loop on all sublists of A.list and get B.list? Thanks in advance. -- View this message in context:

Greetings R experts, I'm having some difficulty recovering lda objects that I've saved within sublists using the save.image() function. I am running a script that exports a variety of different information as a list, included within that list is an lda object. I then take that list and create a list of that with all the different replications I've run. Unfortunately I've been

dear R family, [a text file has been attached for better understanding] i have a list of 16 and each of of that is further subdivided into variable number of lists. So, i have a kind of list into lists phenomenon. [[1]]$'1' 1 2 3 4 5 6 7 8 9 [[1]]$'2' 1 2 3 4 5 6 7 8 9 i want to convert both these sublists into

Dear R Gurus: How do I find the functions which are primitives, please? Thanks, Edna Bell

I wonder what's the right way in R to do the following -- placing objects of the same kind together in subarrays of varying length. Here's what I mean: > word <- c("a","b","c","d","e","f","g","h","i","j") > kind <- c(1,1,1,2,3,4,5,5,7,7) > d <-

Dear list members, I am stuck with navigating in a rather complicated list object. In general I would need a solution to access all first (or other) elements of the different sublists in one list: test=list(a=list(1,2),b=list(3,4),c=list(5,6)) like: test[[1:3]][[1]] which should result in c(1,3,5) Is there any way to access lists in such a way? Using unlist would create quite

Hi all, I have an object that looks (roughly) like the following: l <- list(a = matrix(rnorm(9), 3), b = matrix(rnorm(9), 3), c = matrix(rnorm(9), 3)) l$a[3,] <- sample(c("Message 1", "Message 2", "Message 3")) l$b[3,] <- sample(c("Message 1", "Message 2", "Message 3")) l$c[3,] <- sample(c("Message 1",

Dear all, this is a rather basic question; i am not sure how to structure my data well: I want to extraxt various measures from my raw-data. These measures are of different sizes, so I decided to store them in a list, like: run1 <- list(Dom = (my_vector), mean = (my_single_number)) I can do that in a for loop for 40 runs, ending up with 40 lists: run1, run2, ..., run40. To have all the

Hi; It seems to me that has probably been asked in the past. But I cannot find the track. I usually need to extract elements from a list and contruct vector from them; e.g., to create a table. Perhaps there is a way to directly extract them without looping? Simple example: > S.lst $sublist.1 $sublist.1$age [1] 24.58719 $sublist.1$weight [1] 60.82861 $sublist.2 $sublist.2$age [1] 32.39551

Hi, I need to compare two matrices with each other. If you can get one of them out of the other one by resorting the rows and/or the columns, then both of them are equal, otherwise they're not. A matrix could look like this: [,1] [,2] [,3] [,4] [,5] [,6] [,7] [,8] [1,] 0 1 1 1 0 1 1 0 [2,] 1 1 0 0 0 1 0 1 [3,] 1 0 1 0 0

This seems to be a simple problem, and I feel that there ought to be a simple answer, but I can't seem to find it. I have a function that returns a number of values as a heterogeneous list - always the same length and same names(), but a number of different data types, including character. I want to apply it to many inputs, resulting in a list of lists. I would like to turn this list of

Hello R-ologists, Imagine you have a list "list" like so: >list [[1]] [1] "IPI00776145.1" "IPI00776187.1" [[2]] [1] "Something" "IPI00807764.1" "IPI00807887.1" [[3]] [1] "IPI00807764.1" [[4]] [1] "Somethingelse" What I need to achieve is a filtered list "list2" like so: >list2 [[1]] [1]

I''ve got a page I''ve implemented a bunch of observables and sortables. There are around 330 items in the list. The Observables (for hide/show of sublists) don''t seem to impact performance, but the Sortables take a very long time to load when the page is refreshed or submitted--even after accounting for the server-side processing and latency. I''ve

Hi everyone, Suppose I have a list named "lst", see below: > lst $sub1 ... $sub1$x ... $sub1$y .... $sub2 ... $sub2$x ... $sub2$y ? $sub3 ... ... ... Now, I want to extract the sub-sublist $y from every sublist(sub1, sub2...) and then storage them to a new list. I know how to extract them by subscript or list name one by one, but I wonder if there exist some tricks to finish this

Hi, I apologize for my english. I?m trying to read a file, but the name of this file changes every day, for example: today is May 24, 2012 bonos<- read.table("C:/Bonos/*20120524*.csv", header=TRUE, sep="\t") So, tomorrow I want to read the file again, but i don?t want to put the date by myself, i want this automatically. I know that if a put day() this instruccion gives

my problem is more complex than below but I think below can suffice. i have a list and the name of it at the top level is GGG. so, if i do an lapply and operate on lower components in the sublist, then I can do as shown in EXAMPLE 1 and what will come back will be named GGG at the top level. but, suppose that , the function inside the lapply function was more complex and i wanted to

This function (understandably) takes quite a long time, because it has to go through each function in module and write its binary. But it probably can be parallelized if different threads would write binaries separately, and then merge them together. Is this implemented or planned? Yuri