Displaying 20 results from an estimated 10000 matches similar to: "how to make a table of summary statistics"
2011 May 19
2
trouble with summary tables with several variables using aggregate function
Dear all,
I am having trouble creating summary tables using aggregate function.
given the following table:
Var1 Var2 Var3 dummy
S1 T1 I 1
S1 T1 I 1
S1 T1 D 1
S1 T1 D 1
S1 T2 I 1
S1 T2 I 1
S1 T2 D 1
S1 T2 D 1
S2
2009 Sep 22
3
converting a character vector to a function's input
Hi all, I have been trying to solve this problem and have had no luck so far.
I have numeric vectors VAR1, VAR2, and VAR3 which I am trying to cbind. I also have a character vector "VAR1,VAR2,VAR3". How do I manipulate this character vector such that I can input a transformed version of the character vector into cbind and have it recognize that I'm trying to refer to my numeric
2004 Aug 17
5
Bug in colnames of data.frames?
Hi,
I am using R 1.9.1 on on i686 PC with SuSE Linux 9.0.
I have a data.frame, e.g.:
> myData <- data.frame( var1 = c( 1:4 ), var2 = c (5:8 ) )
If I add a new column by
> myData$var3 <- myData[ , "var1" ] + myData[ , "var2" ]
everything is fine, but if I omit the commas:
> myData$var4 <- myData[ "var1" ] + myData[ "var2" ]
the name
2014 Aug 21
2
pregunta
Buenas noches Javier y José,
Estoy en contra de usar attach(), asi que propongo la siguiente alternativa
con with():
# paquete
require(epicalc)
# los argumentos en ... pasan de epicalc:::cc
# ver ?cc para mas informacion
foo <- function(var1, var2, var3, ...){
or1 <- cc(var1, var2, ...)
or2 <- cc(var1, var3, ...)
list(or1 = or1, or2 = or2)
}
# datos
x <-
2012 Jul 01
2
list to dataframe conversion-testing for identical
HI R help,
I was trying to get identical data frame from a list using two methods.
#Suppose my list is:
listdat1<-list(rnorm(10,20),rep(LETTERS[1:2],5),rep(1:5,2))
#Creating dataframe using cbind
dat1<-data.frame(do.call("cbind",listdat1))
colnames(dat1)<-c("Var1","Var2","Var3")
#Second dataframe conversion
2006 Jan 13
2
find mean of a list of timeseries
Can someone please give me a clue how to 're'write this so I dont need
to use loops.
a<-ts(matrix(c(1,1,1,10,10,10,20,20,20),nrow=3),names=c('var1','var2','var3'))
b<-ts(matrix(c(2,2,2,11,11,11,21,21,21),nrow=3),names=c('var1','var2','var3'))
2014 Aug 21
2
pregunta
Estimados
Estoy entrenando hacer funciones que respondan a comandos,
en esta caso en la salida gráfica se observa que dice : Exposure=var3 y
outcome=var 1
quisiéramos que se reflejan los nombres de la base de datos : var1=estado,
var2=cake, var3=chocolate
Espero haberme explicado adecuadamente
Adjunto tabla con datos
####################################
#Comando que llama
2014 Apr 11
6
crear variable en base a nombre de columnas que tienen un 1
Buenos días.
Hoy ando un poco (o bastante) espeso y no doy con la tecla de una cosa
que seguro que es muy simple..
Pongo un ejemplo.
var1 <- c(rep(0,3),rep(1,2))
var2 <- c(rep(1,2),0,0,1)
var3 <- c(rep(1,2),rep(0,3))
var4 <- c(rep(1,2),rep(0,3))
datos <- data.frame(fila=1:5,var1, var2, var3, var4)
datos
datos
fila var1 var2 var3 var4
1 1 0 1 1 1
2 2 0
2013 Mar 25
2
Faster way of summing values up based on expand.grid
Hello!
# I have 3 vectors of values:
values1<-rnorm(10)
values2<-rnorm(10)
values3<-rnorm(10)
# In real life, all 3 vectors have a length of 25
# I create all possible combinations of 4 based on 10 elements:
mycombos<-expand.grid(1:10,1:10,1:10,1:10)
dim(mycombos)
# Removing rows that contain pairs of identical values in any 2 of
these columns:
mycombos<-mycombos[!(mycombos$Var1
2014 Apr 11
2
crear variable en base a nombre de columnas que tienen un 1
Carlos, en principio si sería algo así, sólo que en vez de quedarme con
todas las columnas var1 a var4 tuviera sólo 3, ya que en mis datos no
hay ningún caso que tenga el valor 1 en más de 3 variables..
Había llegado a una solución (mucho menos elegante que usando reshape),
que implicaba un for sobre las filas.
Jorge, creo que tu solución me vale.
Muchas gracias a los dos..
Saludos
El
2008 Apr 28
1
error in summary.Design
Dear list,
after fitting an lrm with the Design package (stored as "mymodel") I
try running a summary, but I get the following error:
dim(mydata)
[1] 235 9
names(mydata)
[1] "id" "VAR1" "VAR2" "VAR3" "VAR4" "VAR5" "VAR6" "VAR7" "VAR8"
summary(mymodel)
Error in `contrasts<-`(`*tmp*`,
2011 Jan 23
3
FUNC_ODBC and ARRAY
Gentlemen,
I have googled, searched the mailing list archives, and even spoke on
the IRC channel, but have not found an answer to the following
problem. I am attempting to retrieve multiple columns in an ODBC query
using ARRAY per the solutions offered by many individuals. My dialplan
code is as follows:
exten => _.,n,Set(ARRAY(var1,var2,var3)=${ODBC_LOOKUP(${KEYVAL})})
exten =>
2010 Jun 18
3
inverse function of melt
Dear list,
I'm looking for an inverse function of melt(which is in package reshape).Namely, I had a data frame like this
(Table1)
YEAR VAR1 VAR2 VAR3
1995 7 3 45
1996 5 6 32
1997 6 10 15
I transformed my data by using the melt function and my data was reshaped in the following format:
(Table2)
YEAR variable
2009 Sep 01
2
Simple question about data.frame reduction
Hi,
this is a simple question
I have this data.frame:
> test <-
data.frame(var1=c(1,1,1,1,1,1),var2=c("a","a","b","c","d","e"),var3=c("a1","a1","b1","a1","c1","d1"))
> test
var1 var2 var3
1 1 a a1
2 1 a a1
3 1 b b1
4 1 c a1
5 1
2008 Mar 19
4
plot with diffrent colour and plotting symbols
Dear mailing list members,
I am a new R user, I would like to plot the follewing data
var1 <- c(1,2,1,1,2,1,2,1,2,2)
var2 <- round(rgamma(10,2,1)/0.1)*0.1
var3 <- c(0,1,0,1,0,0,0,0,1,0)
var4 <- c(1,2,2,2,1,1,1,1,1,1)
Var <- data.frame(var1,var2,var3,var4)
Var <- Var[sort(Var$var1),]
tt <- Var$var1+((runif(length(Var$var1))/6)-(0.5/6))
labelname <- c("time 1",
2009 Nov 25
1
Sampling dataframe
Hi,
I have a table like that:
> datatest
var1 var2 var3
1 1 1 1
2 3 1 2
3 8 1 3
4 6 1 4
5 10 1 5
6 2 2 1
7 4 2 2
8 6 2 3
9 8 2 4
10 10 2 5
I need to create another table based on that with the rules:
take a random sample by var2==1 (2 sample rows for example):
var1 var2 var3
1 1
2008 Aug 07
2
List of "occurrence" matrices
R users,
I don't know if I can make myself clear but I'll give it a try. I have
a data.frame like this
x <- "var1,var2,var3,var4
a,b,b,a
b,b,c,b
c,a,a,a
a,b,c,c
b,a,c,a
c,c,b,b
a,c,a,b
b,c,a,c
c,a,b,c"
DF <- read.table(textConnection(x), header=T, sep=",")
DF
and I would like to sum all the combinations/occurences by a factor
(letter in this case) between
2008 Apr 11
4
Format regression result summary
Hello to the whole group.
I am a newbie to R, but I got my way through and think it is a lot easier to
handle than other software packages (far less clicks necessary).
However, I have a problem with respect to the summary of regression results.
The summary function gives sth like:
Residuals:
Min 1Q Median 3Q Max
-0.46743 -0.09772 0.01810 0.11175 0.42252
2016 Apr 28
0
Antwort: RE: Interdependencies of variable types, logical expressions and NA
Hi
your initial ds
> str(ds)
'data.frame': 2 obs. of 3 variables:
$ var1: num 1 1
$ var2: logi TRUE FALSE
$ var3: logi NA NA
first result
> str(ds)
'data.frame': 2 obs. of 6 variables:
$ var1 : num 1 1
$ var2 : logi TRUE FALSE
$ var3 : logi NA NA
$ value_and_logical: logi TRUE TRUE
$ logical_and_na : logi TRUE NA
2010 May 05
3
concatenate values of two columns
Dear list,
I'm trying to concatenate the values of two columns but im not able to do it:
i have a dataframe with the following two columns:
X VAR1 VAR2
1 2
2 1
3 2
4 3
5 4
6 4
what i would like to