similar to: concatenating expressions and standard text

Hello, Could someone explain to me what the rules are for concatenation of DWARF location expressions? For example in lib/CodeGen/PrologEpilogInserter.cpp there is a call to DIExpression::prepend to concatenate the stack slot address of a variable to an existing expression. Now the problem here is that the former is a 'Memory location description' while the latter could very well be a

Hi all, I'm building a plot of the values in tmeant (below) against positions 1 to 5, using matplot. tmeant looks like this: case1 case2 pos1 861.8466 818.5909 pos2 961.2841 976.3466 pos3 878.6080 1262.8523 pos4 950.8011 1129.6080 pos5 968.1080 1063.3920 I also have lower (object tl) and upper (object tu) bounds on the confidence intervals as follows: tl: pos1

Dear R people, I have to deal with the output of a function which comes as a matrix of vectors. You can reproduce the structure as given below: x <- list(c(1,2,4),c(1,3,5),c(0,1,0), c(1,3,6,5),c(3,4,4,4),c(0,1,0,1), c(3,7),c(1,2),c(0,1)) data <- matrix(x,byrow=TRUE,nrow=3) colnames(data) <- c("First", "Length", "Value") rownames(data)

Dear all, I want to concatenate the elements of two vectors such as a<-c("a1","a2") b<-c("b1","b2") and obtain "a1b1", "a1b2","a2b1","a2b2" I tried the paste and paste0 functions, but they yielded elementwise concatenation such as "a1b1","a2b2" I am wondering that is there an efficient

Dear R users: I just got confused some R code used in linear mixed model~ example,two factors,A, B,C,A is fixed ,B,C are random,and B is nested in C,if I wannt to use linear mixed model,are the following code correct for each case? case1:want to know random effect of B, case1<-lme(y~A*B*C,random=~B|C) where "B|C" stand for what?,mean B is nested in C? case2: how to wirte

R-users, I want to concatenate columns from different files in a single object. I'm doing bad. My peace of code is as follow: rawdata <- list.files("./data") for (i in rawdata) { mat[ ] <- read.table(paste(i ,sep="")) } At the end of the loop I have just one column. What I'm doing wrong? Thanks, Fred -- View this message in context:

Hi I have a data frame with values in following format. param case1 1 a 2 b 2 c 2 d 3 e 4 f how to use aggregate so that it I only one row for each 'param' value. the output for the above input should be param case1 1 a 2 b,c,d 3 e 4 f Thanks M -- ------------- Mary

I am trying to concatenate 2 datasets that don't have exactly the same column. In SAS I did: data summary; set agency prop; run; No problem in R I get error message summary <-rbind(agency,prop) Error in match.names(clabs, names(xi)) : names do not match previous names But when I use rbin.fill, that overwrites the second file w/ first one. Is there a way to replicate the sas process

Hi, I'm trying to write a simple function like case1 <- function (m, cov, Q, R) { theta <- (acos(R/sqrt(Q^3))) beta <- (-2)*sqrt(Q)*cos(theta/3)+m[1]/3 rho1 <- (-2)*sqrt(Q)*cos((theta+2*pi)/3)+m[1]/3 rho2 <- (-2)*sqrt(Q)*cos((theta-2*pi)/3)+m[1]/3 stderrb <- deltamethod( ~(-2)*sqrt(Q)*cos(theta/3)+x1/3,m,cov) stderrr1 <- deltamethod(

I found: max.col(matrix(c(1,3,2),nrow=1)) Is there a more concise/elegant way? Thanks, ----- TO GET MORE DETAILS CLICK HERE -- View this message in context: http://r.789695.n4.nabble.com/finding-index-of-maximum-value-in-vector-tp4651663.html Sent from the R help mailing list archive at Nabble.com.

Hello there, I would like to simulate X --Normal (20, 5) Y-- Normal (40, 10) and the correlation between X and Y is 0.6. How do I do it in R? Thank you very much ----- TO GET MORE DETAILS CLICK HERE -- View this message in context: http://r.789695.n4.nabble.com/How-to-simulate-correlated-data-tp4651667.html Sent from the R help mailing list archive at

Hi, I would like to ask how the paste(S1, S2, sep="") function internally works. Are the two stings copied to a new String? I have a program where successively strings are build up. First the program calls an external function and depending on the result it builds up strings to visualize the result. The external function is really fast, also for huge input data. But the

Hey there, I'm pretty sure I've found a bug with doveadm when concatenating with another search key. While doveadm HEADER <field pattern> works fine when not using additional search keys, it doesn't work properly when concatenating with other serarch keys - it then simply seems to ignore the additional HEADER <field pattern> search key. It's reproduceable, also

I''m a newbie and I''ve been trying to figure this out for a little while now, hopefully someone can point me in the right direction. case1 <div id="new"> </div> case2 <div id="new"><div id="item1"></div></div> <div id="new2"><div id="item1"></div></div> With RJS in

> From: aprantl at apple.com <aprantl at apple.com> > Since it sounds like the problem is only with implicit descriptions, would a rule > such as "if the expression has a DW_OP_stack_value, add an extra > DW_OP_deref" work for the PrologueEpilgueInserter or do we need > something more principled? Right, that could very well be sufficient for this particular case so

Dear all, I am trying to create a vector name, for example tmax.195012 from tmax., 1950 and 12. Obviously I don't wish to simply type it because the 3 name components are changing in each iteration within a loop. Is there any way of concatenating those 3 components (which are a mixture of numbers and letters)? Thanks for reading, Panos

Hi How do I concatenate two lists element-by-element? Example: list.1 <- list(temperature=c("hot","cold") , size=c("big","medium")) list.2 <- list(temperature=c("lukewarm") , size=c("massive","tiny")) list.wanted <- list(temperature=c("hot","cold","lukewarm") ,

Hi, what is the recommended way to vertically concatenate 2 data frames with the same column names but different number of rows? My problem is something along these lines: df1 <- data.frame(var1=var1,var2=var2,var3=var3) # nrow(df1)=1000 df2 <- data.frame(var1=var4,var2=var5,var3=var6) # nrow(df2)=2000 I tried df <- c(df1,df2), no success. stack does not seem to be appropriate

Dear friends. I use nls() and encounter the following puzzling problem: I have a function f(a,b,c,x), I have a data vector of x and a vectory y of realized value of f. Case1 I tried to estimate c with (a=0.3, b=0.5) fixed: nls(y~f(a,b,c,x), control=list(maxiter = 100000, minFactor=0.5 ^2048),start=list(c=0.5)). The error message is: "number of iterations exceeded maximum of

Hi! Some bootloaders (eg. syslinux) have to ability to load multiple ramdisks, effectively concatenating them. This makes it very easy to augment ramdisks, like eg. customizing an installer. Can I do something similar with XEN? Separating the ramdisk cpio arhives with commas in the config file didn''t work... -- Thanks, Feri. _______________________________________________ Xen-users