similar to: How to subtract the counter i in for loop?

hi R users I have a data set with the name AA AA<-1:100 Now I want to get a child array from AA every 10 numbers e.g. ab =c(10,20,30,40,50,60,70,80,100) How could I subtract aa from AA? thank you . -- TANG Jie Email: totangjie@gmail.com Tel: 0086-2154896104 Shanghai Typhoon Institute,China [[alternative HTML version deleted]]

Hello, I'm having problems working with date values in POSIXct format. Here is what I got (eg.lig attached): x <- read.table("eg.txt", sep = ',', col.names=c("ok","time","secs","lig")) # it gives time as factor z <- cbind(x,colsplit(x$time, split="\\s", names=c("date", "clock")))

Hi list, I am looking at the data yarn in package, I don't understand what is dimension of this data set. I did the following: > library(pls) > data(yarn) > dim(yarn) [1] 28 3 > head(yarn) NIR.1 NIR.2 NIR.3 NIR.4 NIR.5 NIR.6 NIR.7 NIR.8 NIR.9 NIR.10 NIR.11 1 3.06630 3.08610 3.10790 3.09720 2.99790 2.82730 2.62330 2.40390 2.19310 2.00580 1.83790 2

Hi all I have a large SAS data set, how do I get it read in R? The data is too big (about 400,000 rows by 100 columns) to be saved as an Excel file. How should I get it read in R? Any packages? I don't seem to find any. Thanks, Mike [[alternative HTML version deleted]]

Dear All   I have the following data (somewhat simplyfied):   TINF <-1 a <-c(500,750,1000,1250,1500,1750,2000) b <-c(8,12,18,24,36,48,60,72,96)   following function:   infcprodessa <-function (D, tin, tau, ts)   (D * (1 - exp(-0.048 * tin))/(tin * (0.048*79) * (1 - exp(-0.048 * tau)))) * exp(-0.048 * (ts - tin)) z <-sapply(1:1, function(n) infcprodessa(1000,TINF,12,12-TINF))   is

Hi, this is likely very easy to do but I don't find the right terms to search for the solution. I want to show in a bar chart how much different categories deviate from the average percentage change. Thus, in the following example I would like to set the zero line or base or whatever it is called to the average of the values (=0.82) and the bars should show the deviation from that, i.e.

hi guys..please help me with this i am working on two data frames one goes like this: DF1 Sample_id RepairHours Denatured Dose ZeroMean FourtyFiveMean NinetyMean 1 SDM071 0 1 B 60.5 19.0 45.0 2 SDM071 1 1 B 46.0 23.0 42.5 3 SDM071 2 1 B 52.5 24.0 40.0 4 SDM071

Dear all, I have problems with iif function using sqldf library. I counted abundance (Num) of different "SPECIES" in two moments (esf) saving the information in two Tables (esf50, esf100): esf50 SAMPLE SPECIES Num esf 1289 diso1 44 50 1289 diso2 5 50 1289 diso3

Are they the same with .RData being the newer format?? Thanks, ...Tao

Hi, I'm trying to user lmer function from lmerTest package because, if I understood correectly, it allows to make better inference than lmer method from lme4 package. However, whatever I do I keep getting this error: Error in lme4::lFormula(formula = mark ~ ssCount + sTime+ : rank of X = 1660 < ncol(X) = 1895 any ideas what could be a problem? thanks, Srecko [[alternative HTML

Dear all, I have an R script that uses Rcpp, and I have been trying to parallelize it using mclapply (I tried with the multicore and the parallel library) Sometimes (not always, interestingly), the CPU use for each core drops, usually so that the total over all cores reaches 100%, i.e., as fast as if using just one single core fully. I tried my code directly from within emacs, and also using a

Hello r-help, I've been banging my head against the computer in an attempt to learn how to divide my matrix into segments by rows. I want to be able to return each segment as a newly named object. I've tried looking at the apply functions and creating a for loop but brain no work. Here's the basic starting objects that I believe would be needed to separate the matrix. mat <-

Dear help list, I have a timestamp in as a chron object: > (x <- chron(dates = c("12/02/11", "22/11/11"), + times = c("07:30:00", "04:00:00"), + format = c(dates = "d/m/y", times = "h:m:s"))) [1] (12/02/11 07:30:00) (22/11/11 04:00:00) Now I want to shift the timestamp by 06:30 (hh:mm) backwards, to get

hi all: Following is simple example, for(i in 1:10000000){ a<-function(i){ #some function that has an error } } What I want to know is the way to find the error point in for-loop, What "i" makes the error. is there any way to solve it instead of debugging and finding an error manually? Thanks, -- View this message in context:

Dear all, I have written some function that can go up to many lines. Two of the lines give warning errors like: Error in print(....)[c(1, : error in evaluating the argument 'x' in selecting a method for function 'print': Error in ... regions with no neighbours found now obviously this kind of error will halt the execution of the function. I tried *try()* or *tryCatch()*

Dear expeRts, ?? i? use sapply for loop,?and i want to break it when i needed, how to do that?? e.g. sapply( 1:10, function(i) { if(i==5) break and jump out of the function sapply } ) I want to do it because i have to loop 1000000 times, but i don't know when it will break, that means, it may need break at i=5 or at i=50000, for the possible of the? last case, i don't use for loop,

Dear R users, I am running simulations (1000), and in my simulation I am looking at specific sums. For example, if the sum is >=4 then count this, if say <3, then don't count, if the sum=3, then generate a random number from uniform distribution, if this number is say less than 0.5, then count this sum, if greater than 0.5, then don't count. I am having trouble with introducing this

Hi all: My OS is 32bit winxp,but I wanna install 64bit R2.14.1. >From the following website,it says "You can also go back and add 64-bit components to a 32-bit install, or vice versa" http://cran.r-project.org/bin/windows/rw-FAQ.html#Can-both-32_002d-and-64_002dbit-R-be-installed-on-the-same-machine_003f Does it mean that I can install and run 64bit R2.14.1 under 32bit

In the following data.frame there are 6 columns, but 7 are written to the CSV file. install.packages("pmlr") library(pmlr) data(enzymes) write.table(enzymes, sep=",", eol="\n",file="albert.csv")

I have a dataframe from an On-Board Survey with weights ("expwgt") and variables for up to 8 used lines: VEH1 through VEH8. The lines are labeled "MT-..1" through "MT-902". I want to know how many transfers there are between MT-802 and MT-901. That is, when one of them is VEHx and the other is VEHx+1 or VEHx-1 E.g. {VEH1 = MT-802 AND VEH2 = MT-901 } plus {VEH2 =