similar to: Data Extraction

Hello, I have two very basic questions (console attached): 1) What am I getting an error message for # 5 and # 7 ? 2) How to fix the code? I would appreciate receiving your help. Thanks, Pradip Muhuri ###### Reproducible Example ##### N <- 100 set.seed(13) df<-data.frame(matrix(sample(c(1:10),N, replace=TRUE),ncol=5)) keep_var <- c("X1", "X2") drop_var

Hello, I would like to learn how to set up Github/repository and upload/update files and am looking for "Github for Dummies". Any help will be appreciated. Thanks, Pradip

Hello, Using the svyplot () function, I have plotted four graphs that are saved in four different .png files. I am looking for examples how to redraw the same four graphs within grid viewports so that they stay together on a page. The goal is to create one .png file that will include all four graphs (2 rows, 2 columns). Any help would be appreciated. Thanks, Pradip Pradip K. Muhuri,

Hello, Although my R code for the svymean () and svyquantile () functions works fine, I am stuck with the svyby () and make.formula () functions. I got the following error messages. - Error: object of type 'closure' is not subsettable # svyby () - Error in xx[[1]] : subscript out of bounds # make.formula () A reproducible example is appended below. I would appreciate if

Hi Berend, I see you are one of the contributors to the rbecnhmark package. I am sorry that I am bothering you again. I have tried to run your code (slightly tweaked) involving the benchmark function, and I am getting the following error message. What am I doing wrong? Error in benchmark(d1 <- s1(df), d2 <- s2(df), d3 <- s3(df), d4 <- s4(df), : could not find function

Hello List, My goal is to create a 5 category variable (p1_st_data$ob_mrj_cat), based on the p1_st_data$obt_mrj_p variable, using the following code for 50 States and District of Columbia (N=51). p1_st_data$ob_mrj_cat <- cut (p1_st_data$obt_mrj_p, quantile (p1_st_data$obt_mrj_p, (0:5/5), include.lowest=TRUE)) The issue is that, for Utah, I am getting an <NA> instead of (42,48.7] in

Hi Everyone, I am a new R user and trying to run R jobs in batch mode. Robert Muenchen (2009), in his book "R for SAS and SPSS Users", has suggested writing a small batch file like mR.bat as shown below: "C:\Program File\R\R-2.10.0\bin\Rterm.exe" --no-restore --no-save < %1 > %1.Rout 2>& 1 Could anyone tell me in which directory or subdirectory I should

Hello, I am an Intro-level R and ggplot2 user and looking for resources to self teach dynamic report generation in R using knitr. Any advice would be highly appreciated. Thanks, Pradip

Hello, The most part of the program works except that the following logical variable does not get created although the second logical variable-based extraction works. I don't understand what I am doing wrong here. state_pflt200 <- df$p_fatal <200 df[state_pflt200, c("state.name","p_fatal")] I would appreciate receiving your help. Thanks, Pradip Muhuri

Hello, I was trying to draw histograms of age at death and got the following 2 error messages: 1) Error in tapply(1:NROW(x), list(factor(strata)), function(index) { : arguments must have same length 2) Error in findInterval(mm[, i], gx) : 'vec' contains NAs In addition: Warning messages: 1: In min(x) : no non-missing arguments to min; returning Inf 2: In max(x) :

Hello List, My goal is to apply a user-defined function on several columns of a data frame. When testing the code on a reproducible example below, I get the following error message. > #now Write a new function using the above cut ()/quantile function to apply on different columns of the data frame > > CutQuintiles <- function(x) { + cut (test1$x,quantile (test1$x,

Hello, The following code is expected to produce 4 charts. But, I only get charts 1,2 ,& 4, NOT CHART # 3. For Chart# 3, I am getting the following error message: Error in tapply(1:NROW(x), list(factor(strata)), function(index) { : arguments must have same length I would appreciate if someone could help me resolve the issue. Thanks, Pradip # BELOW IS THE REPRODUCIBLE EXAMPLE setwd

Hello List, Could someone tell why I can't install the Himsc and survey packages for R version 2.13.0 (2011-04-13)? What am I doing wrong here? Thanks, Pradip > install.packages ("Hmisc", dependencies=TRUE) --- Please select a CRAN mirror for use in this session --- Warning: unable to access index for repository http://watson.nci.nih.gov/cran_mirror/bin/windows/contrib/2.13

Hola, me gustar?a hacer algo como en el siguiente ejemplo A un df a?adirle una columna que es la transformaci?n de otra, en plan a todo lo que sea x1, x2, x3 lo llamo prueba 1 todo lo que sea x4,x5,x6 lo llamo prueba 2 el resto de x las dejo como est?n. Ser?a algo as? col1 <- c('x1', 'x2', 'x11', 'x1','x33', 'x1','x4', 'x5',

Hola: Como dice Carlos, algo así, por ejemplo: transforma <- function(df) sapply(df, function(x) ifelse(x%in%c("x1","x2","x3"), "prueba1",ifelse(x%in%c("x4","x5","x6"),"prueba2",x))) > transforma(df1)       col1  [1,] "prueba1"  [2,] "prueba1"  [3,] "x11"  [4,]

Yo copio y pego este código y me sale correctamente. Se me ocurre que pueda deberse a la versión de R ¿cuál usas? El 10/09/2020 a las 17:51, Samura . escribió: > Gracias por las respuestas. > > Probé lo de hacer la función y no me salía. Pensaba que hacía algo mal. > Ahora con el código de Marcelino tampoco me sale. > > col1 <- c('x1', 'x2', 'x11',

Hi List, My goal is to force R not to print in scientific notation in the sixth column (rel_diff - for the p-value) of my data frame (not a matrix). I have used the format.pval () and printCoefmat () functions on the data frame. The R script is appended below. This issue is that use of the format.pval () and printCoefmat () functions on the data frame gives me the desired results, but coerces

Hi List, I have spent more than 30 minutes, but failed to read in this file using the read.table() function. I could not figure out how to fix the following error. Error in scan(file, what, nmax, sep, dec, quote, skip, nlines, na.strings, : line 1 did not have 6 elements Any help would be be appreciated. Thanks, Pradip Muhuri ####### below is the reproducible example xd1 <-

Hi, I'm trying to copy the first row of one data frame to another. This is the statement I am using : df2[1,]<-df1[1,]; I have printed them out separately: df1[1,] = A C D E F But after copying: df2[1,] = 96 29 88 122 68 Why isn't it copying? They are both data frames, and "as.character" isn't working either. Thanks for your input :) [[alternative HTML version

Dear R community members and R experts I am stuck at a point and I tried with my colleagues and did not get it out. Sorry, I need your help. Here my data (just created to show the example): # generating a dataset just to show how my dataset look like, here I have x variables # x1 .........to X1000 plus ind and y ind <- c(1:100) y <- rnorm(100, 10,2) set.seed(201) P <-