similar to: help with if statement

I have a dataframe such like the following: ID TIME DV 1 0 0.880146038 1 1 0.88669051 1 3 0.610784702 1 5 0.756046666 2 0 0.456263368 2 1 0.369991537 2 3 0.508798346 2 5 0.441037014 3 0 0.854905349 3 1 0.960457553 3 3 0.609434409 3 5 0.655006334 . . . . . . I would like to generate another column with the normalized values of DV. for each ID, normalize to the value at TIME 0. I was able to

Hi, all, I have a column like the following: ID TIME sub_001 0 sub_001 24 sub_002 0 sub_002 24 sub_003 0 sub_003 24 sub_004 0 sub_005 24 .. .. is there a way for me to just

I have a table like the following: TABLE NO. 1 ID TIME 1325 0 1325 0 . . . . . . TABLE NO. 1 ID TIME 1325 0 1325 0 . . . . . . TABLE NO. 1 ID TIME 1325 0 1325 0 . . . . . . TABLE NO. 1 ID TIME 1325 0 1325 0 . . . . . . I used the following code: sim <- read.table("sim.tab", skip=1, as.is=T,header=T) it did not work, as there're rows with characters in between the data.

Hola, Por favor, necesito insertar una fila debajo de las filas que tengan DV distinto de cero, pero no me deja insertar hasta el final de la tabla. Esta es mi tabla y este es el código con el que estoy apurado. C ID TIME DV AMT RATE CMT SS II EVID GRUPO VISITA DOSIS VECES FORMA NAP EDAD SEXO ALTURA PESO 11 0 0 3 0 1 1 12 1 3 0 3 2 1 0 77 2 147 74 11 1.417 0.001 0 0 2 0 0 0 3 0 3 2 1 0.001

# I've tried to make this easy to paste into R, though it's probably so simple you won't need to. # I have some data (there are many more variables, but this is a reasonable approximation of it) # here's a fabricated data frame that is similar in form to mine: my.df <- data.frame(replicate(10, round(rnorm(100, mean=3.5, sd=1)))) var.list <- c("dv1",

Hi all, This is my first post to the developers list. As I understand it, aggregate() currently repeats a function across cells in a dataframe but is only able to handle functions with single value returns. Aggregate() also lacks the ability to retain the names given to the returned value. I've created an agg() function (pasted below) that is apparently backwards compatible (i.e.

Hi All I have been struggling with this model for some time now and I just can't get it to work correctly. The messages I get when running the code is: DLSODA- Warning..Internal T (=R1) and H (=R2) are such that in the machine, T + H = T on the next step (H = step size). Solver will continue anyway. In above message, R = [1] 0 0 DINTDY- T (=R1) illegal In above message, R = [1]

Full_Name: Woolton Lee Version: 2.1 OS: windows Submission from: (NULL) (128.118.224.46) I did the following ('g' and 'h' are both numeric vectors) > i <- abs(g-h) creating a vector 'i' with values, > i [1] 0.08 0.00 0.33 0.00 0.00 0.00 0.00 0.33 0.00 0.00 0.08 0.08 0.20 0.00 0.13 Now, I want to create a new vector =1 whenever 'i' = 0.33 and =0

HI: I need ideas on how to make this code shorter (maybe with a second loop?). The code as it is works, but in this case I only have 14 samples, but it will become insane with more, so I need a way to make it more automatic. The problem is that the output from ts1, ts2, and so on is a vector with more than one value, so I do not know how to solve this. Thanks Prenewbie The code is the

Hi, I am a newbie of R, and playing with the "ifelse" statement. I have the following codes: ## first, for(i in 1:3) { for(j in 2:4) { cor.temp <- cor(iris.allnum[,i], iris.allnum[,j]) if(i==1 & j==2) corr.iris <- cor.temp else corr.iris <- c(corr.iris, cor.temp) } } this code is working fine. I also tried to perform the same thing in another way with "ifelse":

Hello All, I am trying to create a column of weights based off of factor levels from another column. I am using the weights to calculate L scores. Here is an example where the first column are scores, the second is my "factor" and the third I want to be a column of weights. I can do what I want with an ifelse statement (see below), but I am wondering if anyone knows of a cleaner way

Hi All, I want to draw samples (n=4) from one of 2 triangular distributions for each value in a matrix. I am using an ifelse statement to try to define which distribution to draw from. >From the output, I can see that the ifelse statement is choosing the correct distribution, however, my n=4 simulations aren't occurring. Is there a way to adjust the ifelse statement to fix this, or must

Hello everyone, I have a (small) issue. I already googled a lot, so I decided to use ifelse instead of if (){} else{} All the elements seem to work seperately, but combined in the ifelse statement, it doesn't seem to work. #The price function is a function which is normally distributed with only positive answers price<-function() {abs(rnorm(1,10,25))} #Before I use pieceprice in the

Dear R helpers Suppose val1 = c(10, 20, 35, 80, 12) val2 = c(3, 8, 11, 7) I want to select either val1 or val2 depending on value of third quantity val3. val3 assumes either of the values "Monthly" or "Yearly". If val3 = "Monthly", then val = val1 and if val3 = "Yearly", then val = val2. I tried the ifelse statement as ifelse(val3 =

Hi there, I'm very new on R and I hope someone can help me to solve the problem in using the ifelse statement with the xtable function(library xtable). I'm trying to get the printing of the elements of two lists in a sorted way. These two list have in common the their names. I will try to give an example: the first list looks like this: $code1 Code code1 Nation

I am using R in a Microsoft Windows environment. I have a dataset called “mp1b”. I have a variable called h. h can take a value from -1 to 5. If h <1, I want to create a new dataset called mp2 that is the same as mp1b: “mp2<-mp1b” If h > 0, I want to set create a dataset mp2, where I limit the original dataset to those where mp1b$group = =h. similar to:

Hi R-helpers, I am trying to use this ifelse statement to recode a variable: > data$SOCIAL_STATUS<-ifelse(data$SOCIAL_STATUS=="B" & data$MALE>4, "C", "B") (i.e., if social status is B and there are more than 4 males, then recode social status to C; otherwise, leave it B) But, it's not working. See the below R output. Notice that there were 71

Hello, I'm doing some scripting and I've noticed that R doesn't seem to have an if (cond){ do }ifelse (cond) { do } else { do } type block. Is this correct or am I missing something. THX Paul -- Research Technician Mass Spectrometry o The / o Scripps \ o Research / o Institute

Dear R-community My ODE problems looks as follows: (1) dA/dt = u*A - v*B (2) dB/dt = v*B - u*A where u is a constant, and v=k*t (k=constant, t=time) Does anybody knows a good function/procedure of solving? Should one involve the equation (3) dv/dt = k? Thanks for your support. -- Dominik Heinzmann Master of Science in Mathematics, EPFL Ph.D. student in Biostatistics Institute of Mathematics

Hi guys, My code (next 2 lines below) isn't doing what I'm expecting it to: tmp <- ifelse(uncurated$days_to_tumor_recurrence=="null","norecurrence","recurrence") curated$recurrence_status <- tmp I want the column "recurrence_status" in my output file to have values "recurrence" (if the input value had a number in the