Displaying 20 results from an estimated 400 matches similar to: "McNemar's Test Question"
2010 Dec 28
1
Problem applying McNemar's - Different values in SPSS and R
Hi friends,
I get different values for McNemar's test in R and SPSS. Which one should i
rely on when the p values differ.
I came across this problem when i started learning R and seriously give up
on SPSS or any other proprietary software.
Thank u in advance
Output in SPSS follows
*Crosstab*
hsc
Total
ABN
NE
ABN
tvs
ABN
Count
40
3
43
Row %
93.0%
7.0%
2009 Jul 19
1
Can I use "mcnemar.test" for 3*3 tables (or is there a bug in the command?)
Hello all,
I wish to perform a mcnemar test for a 3 by 3 matrix.
By running the slandered R command I am getting a result but I am not sure I
am getting the correct one.
Here is an example code:
(tt <- as.table(t(matrix(c(1,4,1 ,
0,5,5,
3,1,5), ncol = 3))))
mcnemar.test(tt, correct=T)
#And I get:
McNemar's Chi-squared
2005 Jan 24
1
mcnemar.test odds ratios, CI, etc.
Does anyone know of another version of the Mcnemar test that provides:
1. Odds Ratios
2. 95% Confidence intervals of the Odds Ratios
3. Sample probability
4. 95% Confidence intervals of the sample probability
Obviously the Odds Ratios and Sample probabilities are easy to calculate
from the contingency table, but I would appreciate any help on how to
calculate the confidence
2006 Dec 26
3
McNemar test in R & SPSS
Hello,
I am hoping someone can clarify why I might obtain a quite different value
in R & SPSS for a McNemar test I ran.
Firstly, here is the R syntax & output
R OUTPUT
> mctest <- as.table(matrix(c(128,29,331,430),
+ ncol =2, dimnames = list(group=c("preMHT","postMHT"),
+ assault=c("yes","no"))))
> mctest
assault
2010 Sep 14
1
Using McNemar's test to detect shifts in response from pre- to post-treatment
Hello Everyone,
I've been asked to check if there is a significant difference in the following:
Pre Post
Group A 15/19 14/19
Group B 14/19 10/19
My sense is that I need to perform McNemar's test on these data because responses are correlated within patient from the pre-test to the post-test.
The question is how to do this. I'm a SAS user
2010 Jan 28
0
Update to exact2x2 package: Exact McNemar's test
Hi all,
I have updated the exact2x2 package which calculates exact conditional tests and the matching confidence intervals for 2x2 tables. The big change in the update is to allow the option paired=TRUE which gives an exact McNemar's test together with odds ratio estimates and confidence intervals. See vignette("exactMcNemar") for details.
The original release is described in the
2010 Jan 28
0
Update to exact2x2 package: Exact McNemar's test
Hi all,
I have updated the exact2x2 package which calculates exact conditional tests and the matching confidence intervals for 2x2 tables. The big change in the update is to allow the option paired=TRUE which gives an exact McNemar's test together with odds ratio estimates and confidence intervals. See vignette("exactMcNemar") for details.
The original release is described in the
2009 Jun 01
1
using "cochran.test()" as a "mcnemar.test()" ?
Hello all
I wish to perform a mcnemar.test() for a 5X5 matrix.
Wikipedia tells me (http://en.wikipedia.org/wiki/Cochran_test) I should turn
to cochran.test.
The only place I found it was in the "outliers" package, but the command
cochran.test() acts differently then mcnemar.test() , and doesn't take a
table as input.
Any ideas on how to use it ?
#Example code:
aa =
2009 Jun 22
2
Automatically Adding Categories
Greetings,
I have two files which contain responses to a series of multiple
choice questions. One
file contains responses before an "intervention" and the other
contains the responses afterward.
There were three possible responses to each question: D, F, T (for
Don't Know, False, and True).
I would like to try McNemar's test to determine if there was any
significant
2010 Apr 27
1
Should mcnemar.test use as.factor instead of factor
I am working with the mcnemar.test function and the help does not show a maintainer/author, but it is part of the stats package.
My issue is that I want to use the test on 2 variables with possible values of 0:3, in one of the tests one of the variables does not have any 3's, so to make sure that the matrix is square I do:
> x <- factor(x, levels=0:3)
> y <- factor(y, levels=0:3)
2006 Apr 13
1
about McNemar
Hello sir: How can I perform McNemar (paired chi square test) by using R?
Thanks!
------------------------------
*******************************************
Xin Meng
Capitalbio Corporation
National Engineering Research Center
for Beijing Biochip Technology
BioPharma-informatics & Software Dept.
Research Engineer
Tel: +86-10-80715888/80726868-6438
Fax: +86-10-80726790
Email??xmeng
2005 Dec 17
0
- McNemar with unequal sample sizes
Hi,
i need to test the equality of proportions in a paired case, like here:
after before
+ -
+ 10 14
- 5 53
So usually i use the mcnemar.test(stats).
Due to mortality, I now got the problem that my sample sizes in both
factors are not equal any more -- there are less cases in the "after"
condition. I already learned that Ekbohm (1982) and Marascuilo adressed
the problem
2013 Feb 01
2
Nested loop and output help
Hello Everyone,
My name is Thomas and I have been using R for one week. I recently found
your site and have been able to search the archives of posts. This has
given me some great information that has allowed me to craft an initial
design to an inquiry I would like to make into the breakdown of McNemar's
test. I have read an intro to R manual and the posting guides and hope I am
not violating
2009 Jul 24
2
How to test frequency independence (in a 2 by 2 table) with many missing values
Hello dear R help group.
My question is statistical and not R specific, yet I hope some of you might
be willing to help.
*Experiment settings*: We have a list of subjects. each of them went
through two tests with the answer to each can be either 0 or 1.
*Goal*: We want to know if the two experiments yielded different results in
the subjects answers.
*Statistical test (and why it won't
2006 May 17
1
mc nemar test
Hello R users,
I would like to perform a mc nemar test.
There is my data :
__________________________________
x <- matrix(4:1,2,2)
x
[,1] [,2]
[1,] 4 2
[2,] 3 1
__________________________________
My population is too small for normal approximation.
__________________________________
library(concord)
mcnemar.mh(x)
$statistic
[1] 0.2
$p
[1] 0.6547208
Warning message:
low
2010 Nov 29
1
cross tabulate variables by subject id
Dear list,
I have data like this:
dat1 <- data.frame(subject=rep(1:10,2),
cond1=rep(c("A","B"),each=5),
cond2=rep(c("C","D"),each=10),
choice=sample(0:1,10,replace=TRUE))
I would like to compare subjects' "choice" for (cond1=="A" &
cond2=="C") vs
2015 Jan 29
3
pregunta
Estimados
Para analizar tres muestras cualitativas independientes se utiliza Cochran-Mantel-Haenszel test
?Cual script es el adecuado para analizar tres variables dependientes? en MCNEMAR solo se permite analizar dos variables cualitaticvas dependientes
saludos
José
[[alternative HTML version deleted]]
2013 Jan 28
2
Adjusted R-squared formula in lm()
What is the exact formula used in R lm() for the Adjusted R-squared? How can I interpret it?
There seem to exist several formula's to calculate Adjusted R-squared.
Wherry’s formula [1-(1-R2)·(n-1)/(n-v)]
McNemar’s formula [1-(1-R2)·(n-1)/(n-v-1)]
Lord’s formula [1-(1-R2)(n+v-1)/(n-v-1)]
Stein 1-(n-1/n-k-1)(n-2)/n-k-2) (n+1/n)
Theil's formula (found here:
2005 Jul 11
1
validation, calibration and Design
Hi R experts,
I am trying to do a prognostic model validation study, using cancer
survival data. There are 2 data sets - 1500 cases used to develop a
nomogram, and another of 800 cases used as an independent validation
cohort. I have validated the nomogram in the original data (easy with
the Design tools), and then want to show that it also has good results
with the independent data using 60
2011 Apr 20
1
possible minor bug in fisher.test
Hi,
I received a bug report for my exact2x2 package that seems to apply to fisher.test in the stats package also.
Here is some code which creates the error:
>x<-factor(c(0,1,1),levels=c(0,1))
> y<-factor(c(1,1,1),levels=c(0,1))
> fisher.test(x,y)
Error in fisher.test(x, y) : 'x' and 'y' must have at least 2 levels
>
The help says that x and y could be