similar to: Deleting rows with special character

Dear list, I was curious how to subtract a vector from matrix? Say, I have mat <- matrix(1:40, nrow=20, ncol=2) x <-c(1,2) I want, x-mat[1,] and x-mat[2,], and so on... Basically, subtract column elements of x against column elements in mat. But x-mat won't do it. Thanks, Mike [[alternative HTML version deleted]]

HI Eliza, You could do this: set.seed(15) mat1<-matrix(sample(1:800,124*12,replace=TRUE),nrow=12) # smaller dataset #Your codes ?list1<-list() ?for(i in 1:ncol(mat1)){ ? list1[[i]]<-t(apply(mat1,1,function(x) x[i]-x)) ? list1} ?x<-list1?? x<-matrix(unlist(x),nrow=12) x<-abs(x) ?y<-colSums(x, na.rm=FALSE) z<-matrix(y,ncol=10) ?z<-as.dist(z) ?z ?# ?? 1?? 2?? 3?? 4?? 5??

Dear useRs, I have a matrix with 38 columns and 365 rows. what i want to do is the following..... 1. subtracting from each column, first itself and then all the remaining columns. More precisely, from column number 1, i will first subtract itself(column 1) and then the remaining 37 columns. Afterwards i will take column number 2 and do the same. In this way i want to proceed till 38th column.

I am stuck on a simple problem where an example works fine but the real one does not. I have a data.frame where I wish to sum up some values across the rows and create a new data.frame with some of old data.frame variables and the new summed variable. It works fine in my simple example but I am doing something wrong in the real world. In the real world I am loading a labeled data.frame. The

Dear all, i searched for some classification methods and I have no glue if i took the right once. My problem: I have a matrix with 17000 rows and 33 colums (genes and patients). The patients are grouped into 3 diseases. No I want to classify the patients and for sure i want to know which rows are more helpful for the classification than others. I tried SVM and random forest. Do you think this

I have a matrix of 5 columns and 64 rows, let's call it "mat1". All values are 1 or 0. I need to take the values of the elements by row and create a single numeric element that can be placed its respective slot in a 64-element list, named "list1". For example, mat1[11,1:5] = 0,1,1,0,1 and I must put 01101, with a length of 1, into the 11th element of list1. I can create

Hi, May be this helps: ?tb[1,]%*%(((val-rep(meansb79[1,],5))^2)/6) #??????? [,1] #[1,] 1.47619 tryvarb<-c(1,2,3,4,4,4,4) ?var(tryvarb) #[1] 1.47619 tb[2,]%*%(((val-rep(meansb79[2,],5))^2)/6) #???????? [,1] #[1,] 1.904762 sapply(seq_len(nrow(tb)),function(i) tb[i,]%*%(((val-rep(meansb79[i,],5))^2/6))) # [1] 1.4761905 1.9047619 1.9047619 1.9047619 1.9047619 2.2857143 1.9047619 # [8] 1.9047619

Good Afternoon, I'm trying to create a graph that displays the best way the following information. ??? For instance organized by bar graph, A, B, C Source X1000s X600s X500s X250s X100s X50s X10s X5s X3s X1s 1 A 47 63 75 116 125 129 131 131 131 131 2 B 37 64 45 11 25 19 61 131 186 186 3 C 17 62 25 66 12 29 91 171 186

I'm new to R so forgive me if this seems like a simple question: So I have table where the row titles are string variables. When I plot the data with rows along the x-axis, the data is ordered alphabetically as opposed to the order of the table. How can I preserve the row order of the table in the plot? Thanks in advance. -- View this message in context:

Let me start by saying I am rather new to R and generally consider myself to be a novice programmer...so don't assume I know what I'm doing :) I have a large matrix, approximately 300,000 x 14. It's essentially a 20-year dataset of 15-minute data. However, I only need the rows where the column I've named REC.TYPE contains the string "SAO " or "FL-15". My

**NEW TO R**-been trying to teach myself with no prior experience in computer languages, so I apologize if I am poor at using technical terms Hi, I have perused some of the previous posts on this topic and tried their solutions, but am still coming up with error messages(sometimes more than 50 at a time) I have: a csv file with four columns(that I have read into R, no problem, we will call it

Sorry, the use of rows/columns I found so far was rather contradictive, both refering to what can be gotten via subset() instead of what I'm looking for. Is there a way to get multiple colums/rows? Something like corpus.df${mph,mgl,eng} Thanks in advance for any answers. -- Joel Prokopchuk

Hi, all, I have a column like the following: ID TIME sub_001 0 sub_001 24 sub_002 0 sub_002 24 sub_003 0 sub_003 24 sub_004 0 sub_005 24 .. .. is there a way for me to just

Dear folks, I have a question about the image() function in R. I found the following link talking about this but the replies didn't help with my situations. http://r.789695.n4.nabble.com/question-on-image-function-td839275.html#a839276 To be simple, I will keep using the example in the above link. Suppose the data are like x y mcpvalue 0.4603578

Hi Guys, It is very simple question, but I can't find the answer! Please help me. I use R and such simple function as length() doesn't work. The result is always 1 even if my data are more then 1 observations! Do I have to load any additional library? > length(Ret_1) [1] 1 > length function (x) .Primitive("length") Thank you!!! -- Best regards, Andy Fetsun

The following code is giving me problems. I want to export densities of a distribution to a csv file. At the bottom of the code I use the hist function to generate the densities. But hist is returning values greater than 1. I don't understand, why. Any help you can supply is greatly appreciated. # Set word path dir<-"~/Research/MR Distribution Analysis/" setwd(dir)

I have a data frame called chemdata with this structure: > str(chemdata) 'data.frame': 14886 obs. of 4 variables: $ site : Factor w/ 148 levels "BC-0.5","BC-1",..: 104 145 126 115 114 128 124 2 3 3 ... $ sampdate: Date, format: "1996-12-27" "1996-08-22" ... $ param : Factor w/ 8 levels "As","Ca","Cl",..:

I have next table source destine 3 3 7 7 6 6 3 4 4 4 4 3 3 3 3 3 3 3 3 3 3 4 4 4 4 3 3 4 4 3 I'm trying to create an array with the number of occurrences between the source and destination. id_ap<-levels(factor(df$v_source)) num_AP<-length(levels(factor(df$v_source))) mat<-matrix(data=NA,nrow=num_AP,ncol=num_AP, byrow=TRUE,dimnames=list(id_ap,id_ap)) 1 2 3 4 5 6 7

Hi all, I'm trying to use ggplot to make a boxplot of some data, but I can't seem to figure out how to make it use the data I'm giving it. The data is in a data.frame so that it has two columns: >meltl value L1 1234 1 1234 1 1235 1 ... 1255 1 2335 2 3444 2 ... 10001 50 12311 50 ... The first column is my x value, the second is my y. I'd like to produce one boxplot for

Dear all, i try to plot with ggplot2. Therefor I have an matrix with 3 colums. With cbind I add an additional column called "col". I need this column "col" because in a later step and want to specify here some plot details which I will get from another analysis If I want to plot with this code, I have the problem that the legend is wrong. Blue changed to green and green to