similar to: Multiplying elements of a list by rows of a matrix

I have a list 'ans' from the following code: tt <- rnorm(50) rr <- rnorm(50) ans <- lm(rr~tt) ans[1] is "$coefficients", ans[2] is "$residuals", ans[3] is "$effects", ... and so on up to ans[12]. Is there an easy way to display just these names and not the data they contain? I thought I saw my advisor type "ans$" and they were displayed,

Dear R list, I have the following data: set.seed(1) n <- 5 # number of subjects tt <- 3 # number of repeated observation per subject numco <- 2 # number of covariates x <- matrix(round(rnorm(n*numco),2), ncol=numco) # the actual covariates x > x [,1] [,2] [1,] -0.63 -0.82 [2,] 0.18 0.49 [3,] -0.84 0.74 [4,] 1.60 0.58 [5,] 0.33 -0.31 I need to form a matrix

Hi! This is my first time posting. I've read the general rules and guidelines, but please bear with me if I make some fatal error in posting. Anyway, I have a continuous response and 29 predictors made up of continuous variables and nominal and ordinal categorical variables. I'd like to do lasso on these, but I get an error. The way I am using "lars" doesn't allow for the

Hello! # I have a list with several data frames: mylist<-list(data.frame(a=1:2,b=2:3), data.frame(a=3:4,b=5:6),data.frame(a=7:8,b=9:10)) (mylist) # I want to grab only one specific column from each list element neededcolumns<-c(1,2,0) # number of the column I need from each element of the list # Below, I am doing it using a loop: newlist<-NULL for(i in 1:length(mylist) ) {

HI all, I'm new to R. Say I have a multi-layered list called newlist. ############ > str(newlist) List of 2 $ :List of 5 ..$ : num [1:8088] NA 464 482 535 557 ... ..$ : num [1:8088, 1:2] NA 464 482 535 557 ... ..$ : num [1:8088, 1:3] NA 464 482 535 557 ... ..$ : num [1:8088, 1:4] NA 464 482 535 557 ... ..$ : num [1:8088, 1:5] NA 464 482 535 557 ... $ :List of 3 ..$ : num

I a using plink on a large SNP dataset with a .map and .ped file. I want to get some sort of file say a list of all the SNPs that plink is saying that I have. ANyideas on how to do this? -- Thanks, Jim. [[alternative HTML version deleted]]

Hello all, Maybe I'm being thick, but I was trying to figure out a simple way to create a list with the same dimension of another list, but populated with NA values. masterlist = list( aa=list( a=matrix(rnorm(100),10,10), b=matrix(rnorm(130),13,10), c=matrix(rnorm(140),14,10)), bb=list(

I have a list containing 48 objects (each with 30 rows and 4 columns, all numeric), and wish to produce 4 boxplot series (with 48 plots in each) , one for each column of each object. Basically I want a boxplot from boxplot(mylist[[]][,i]) for i in 1:4. It seems that I can create a boxplot of length 48 from the entire list, but I don't seem able to subscript to return 4 boxplots from the list

like this, the list is below, I want to remove the last one . not using newlist[-2], but using the function detect its component is numeric(0) and then remove it from the list. newlist [[1]] [1] 2 3 [[2]] [1] numeric(0) [[3]] [1] 7 [[alternative HTML version deleted]]

Hello, thank you all for your patience and time I am essentially trying to get disorganised data into long form for linear modelling. I have 2 dataframes "rec" and "book" Each row in "book" needs to be pasted onto the end of several of the rows of "rec" according to two variables in the row:" MRN" and "COURSE" which match. I have

R-helpers: I'm trying to build a package, but I'm a bit new to the whole S3/S4 methods concept. I'm trying to add a new definition of the zoo function "as.yearmon", but I'm getting the following error when it gets to this point during a package install: *** R CMD INSTALL STARStools * installing to library

Hello, I'm trying to get postfix and mailman going on CentOS 5.4. I had this working previously, six to eight months ago, and shut it down since the need for use was no longer there. I've now reactivated mailman and set up a list. The software versions I'm using are httpd 2.2.14, postfix 2.3.3, and mailman 2.1.9. All the services are started, the list is created, and email is sent to

This is a minor release of Shorewall. WARNING: This release introduces incompatibilities with prior releases. See http://www.shorewall.net/upgrade_issues.htm. Changes are: a) There is now a new NONE policy specifiable in /etc/shorewall/policy. This policy will cause Shorewall to assume that there will never be any traffic between the source and destination zones. b) Shorewall no longer

hello , i''m currently trying to set-up Traffic Shapping with Shorewall and I have strong feelings that I found a bug. I may be mistaken, but I tried everything and can''t get it to work. I''ve turned ON TC_ENABLED=Yes and CLEAR_TC=Yes when i start shorewall ( shorewall start ), i get this message : Setting up Traffic Control Rules... TC Rule "2 eth1 0.0.0.0/0 tcp

Hi all .., I have a list of 7000 dataframes with similar column headers and I wanted to add a new column to each dataframe based on a certain condition which is the same for all dataframes. When I extract one dataframe and apply my code it works very well as follows :- First suppose this is my first dataframe in the list > OneDF <- Mylist[[1]] > OneDF ID Pdate

my list al is as below: mylist=list(c(2,3),5,7) > mylist [[1]] [1] 2 3 [[2]] [1] 5 [[3]] [1] 7 How could I get the following FOUR lists: First one [[1]] [1] 3 [[2]] [1] 5 [[3]] [1] 7 Second one [[1]] [1] 2 [[2]] [1] 5 [[3]] [1] 7 Third One [[1]] [1] 2 3 [[2]] [1] 7 Last one [[1]] [1] 2 3 [[2]] [1] 5 Do I have to use 'for' loops? Please give me sone suggestions! Thank you

chan_sip.c6524 reload_config= unable to get ip address from asterisk, sip disabled The ip address is working fine, Internet works great. Can anyone help...Thanks

1. I have a list of lm (linear model) objects. Is it possible to select, through subscripts, a particular element (say, the intercept) from all the models? I've tried something like this: List[[1:length(list)]][1] All members of the list are similar. My goal is to have a list of the intercepts and lists of other estimated parameters. Is it better to convert to a matrix? How to do this? 2.

I am getting the following message when Shorewall stops can anybody shed any light on this message and where I should be looking? Thanks root@bobshost:~# shorewall stop Loading /usr/share/shorewall/functions... Processing /etc/shorewall/params ... Processing /etc/shorewall/shorewall.conf... Loading Modules... Stopping Shorewall...Processing /etc/shorewall/stop ... IP Forwarding Enabled

I would like to use grep and gsub to manipulate a vector to make the names used consistent, i.e. reduce a level or two. However, here is what I found when I attempted to use grep and gsub: > tmp_test<-c("House 1 Plot Plus +100","House 2 Plot Plus +100","House 3 Plot Plus -100","House 4 Plot Plus -100","House 1 Plus +100","House 2